Implement function reverse that takes a slice of integers and reverses the slice in place without using a temporary slice.
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- Q2: Implement function F (A, B, C) = m (2,4,6,7) using 1:4 deMUX F (B, C).Write a recursive function that finds the minimum value in an ArrayList. Your function signature should be public static int findMinimum(ArrayList<Integer>) One way to think of finding a minimum recursively is to think “the minimum number is either the last element in the ArrayList, or the minimum value in the rest of the ArrayList”. For example, if you have the ArrayList [1, 3, 2, 567, 23, 45, 9], the minimum value in this ArrayList is either 9 or the minimum value in [1, 3, 2, 567, 23, 45] Hint:The trick is to remove the last element each time to make the ArrayList a little shorter. import java.util.*; public class RecursiveMin{public static void main(String[] args){Scanner input = new Scanner(System.in);ArrayList<Integer> numbers = new ArrayList<Integer>();while (true){System.out.println("Please enter numbers. Enter -1 to quit: ");int number = input.nextInt();if (number == -1){break;}else {numbers.add(number);}} int minimum =…Implement this algorithm: Implement a function cross_out_multiples that takes as arguments a list of boolean values (true/false) called is_prime and a number n. The function sets the boolean values at all multiples of n (2*n, 3*n, 4*n ...) that are in the list to false. Implement a function sieve(n) which gives back a list of all primes below n.
- Write a recursive function that finds the minimum value in an ArrayList. Your function signature should be public static int findMinimum(ArrayList<Integer>) One way to think of finding a minimum recursively is to think “the minimum number is either the last element in the ArrayList, or the minimum value in the rest of the ArrayList”. For example, if you have the ArrayList [1, 3, 2, 567, 23, 45, 9], the minimum value in this ArrayList is either 9 or the minimum value in [1, 3, 2, 567, 23, 45] ================================================ import java.util.*; public class RecursiveMin{public static void main(String[] args){Scanner input = new Scanner(System.in);ArrayList<Integer> numbers = new ArrayList<Integer>();while (true){System.out.println("Please enter numbers. Enter -1 to quit: ");int number = input.nextInt();if (number == -1){break;}else {numbers.add(number);}} int minimum = findMinimum(numbers);System.out.println("Minimum: " + minimum);}public static int…Implement a function GetMinimumCutSegments(int[] arr, int k) that takes in an array arr of positive integers and an integer k, and returns the minimum number of contiguous segments of the array that must be concatenated to form an array of size k. The function should return -1 if it is not possible to create an array of size k by concatenating contiguous segments of the input array. Example: Input: [1, 2, 3, 4], 6 Output: 2 Explanation: The minimum number of contiguous segments that must be concatenated to form an array of size 6 is 2. The two segments that can be concatenated are [1, 2] and [3, 4]. Input: [1, 2, 3, 4], 7 Output: -1 Explanation: It is not possible to create an array of size 7 by concatenating contiguous segments of the input array. Constraints: The input array arr will have at most length 100. The integer k will be at least 1 and at most 10^6. Can you write a C# function that solves this problem? public int GetMinimumCutSegments(int[] arr, int k) { // Your code…implement QuickSort of ints that sorts the numbers in the non-decreasing order. Implement the rearrange function using QuickSort ( such that the pivot is set on the extreme left and the rearrangement is carried on on two pointers) using the O(n) time algorithmThe function gets as input an array, and index of the pivot.The function rearranges the array, and returns the index of the pivot after the rearrangement. int rearrange(int* A, int n, int pivot_index); Implement the QuickSort algorithm. - For n<=2 the algorithm just sorts the (small) array (smaller number first). - For n>=3 the algorithm uses the rearrange function with the pivot chosen to be the median of A[0], A[n/2], A[n-1]. void quick_sort(int* A, int n);
- implement QuickSort of ints that sorts the numbers in the non-decreasing order and in c language Implement the rearrange function used for QuickSort using the O(n) time algorithm with two pointers. The function gets as input an array, and index of the pivot. The function rearranges the array, and returns the index of the pivot after the rearrangement. please write form as: int rearrange(int* A, int n, int pivot_index); 2, Implement the QuickSort algorithm. For n<=2 the algorithm just sorts the (small) array (smaller number first). - For n>=3 the algorithm uses the rearrange function with the pivot chosen to be the median of A[0], A[n/2], A[n-1]. write as form: void quick_sort(int* A, int n);Write a function that takes in the head of a Singly Linked List and an integer k, shifts the list in place (i.e., doesn't create a brand new list) by k positions, and returns its new head. Shifting a Linked List means moving its nodes forward or backward and wrapping them around the list where appropriate. For example, shifting a Linked List forward by one position would make its tail become the new head of the linked list. Whether nodes are moved forward or backward is determined by whether k is positive or negative. Each LinkedList node has an integer value as well as a next node pointing to the next node in the list or to None / null if it's the tail of the list. You can assume that the input Linked List will always have at least one node; in other words, the head will never be None / null.int getMax(int arr[], int n) { intmx=arr[0]; for (inti=1; i<n; i++) if (arr[i] >mx) mx=arr[i]; returnmx; } Can u give me the code for this one as well....this is the first function and countsort is the second
- Write a recursive function maxArrayList (ArrayList A, int first, int last) that receives an ArrayList A, first index, last index and returns the largest integer number in the ArrayList A public static int maxArrayList (ArrayList A, int item) that receives an ArrayList A, an integer called item and returns the number of times that item occurs in A public static int searchArrayList (ArrayListWrite pseudocode for a function Det-Quicksort(A, p, r) that receives array A[1..n], and indices p and r. The function should sort the subarray A[p..r] recursively (meaning you should call itself). You can also use a function LinearSearch(A, p, r, v) that searches subarray A[p..r] for an element of value v and return its index (in case it exists) in O(r − p) time. (Just to give you something to compare to, the solution has 8 lines.)Write a function f1 that takes the root of a binary tree as a parameter and returns the sum of the nodes which are the right child of another node. The root of the tree is not a child of any node. Consider the following class definitions while writing your code.SEE MORE QUESTIONS