Data for four mutually exclusive alternatives are given in the table below. Assume a life of 7 years and a MARR of 9%, Alt. A Alt. B Alt. C Alt. D Do Nothing Initial Cost $5,600 $3,400 $1,200 SO EUAB $1,400 $1,000 $400 SO Salvage Value $400 SO SO SO Reference: Table 9 The AB /AC ratio for the third increment, (A-B) is OA.0.75 OB. 0.92 OC.0.69 OD.0.84
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- The survey firm of Layer, Anderson, and Pope (MAP) LLP is considering the purchase of a pieceof new GPS equipment. Data concerning the alternative under consideration are presented below.First Cost $28,000Annual Income 7,000Annual Costs 2,500Recalibration at end of Year 4 4,000Salvage Value 2,800If the equipment has a life of eight years and MAP’s minimum attractive rate of return (MARR) is5%, what is the annual worth of the equipment?Q15. For the cash flows shown, determine the incremental cash flow between machines B and A (a) in year 0, (b) in year 3, and (c) in year 6. Machine First Cost, $ A B -13,000 -25,000 AOC, $ per Year -1,300-400 Life, Years Salvage Value, $ 5,000 6,000 3 6 a) The incremental cash flow between machines B and A in year 0 is $ . b) The incremental cash flow between machines B and A in year 3 is $. c) The incremental cash flow between machines B and A in year 6 is $ .The cash flows for three mutually exclusive alternatives are given in table below. MARR = 4%. ALB Alt. C 27,000 24,000 7,600 6,500 13% 11% Initial cost Annual benefits ROR Life in years Alt. A $15,000 $4,500 15% 5 Reference: Case Study 8 The best alternative for a MARR of 2.0% using the incremental rate of return analysis is A. Alt. C B. Alt. B C. Alt. A OD.Do-nothing
- Given the following pertinent data for four alternatives, what is the best alternative using the incremental ROR method given MARR=10% Initial Cost Annual CF, $ Life, years 30 O Alt. A Alt. B O Alt. C A O Alt. D B +22,000 +35,000 с -200,000 -275,000 -190,000 -331,350 30 D +19500 +42,000 30 30Any help would be appreciated! Given the data for three different alternatives in the table below, determine the best alternative using the incremental rate of return (∆RoR) analysis. MARR =9%. A B C First cost $15,000 $25,000 $20,000 O &M Cost/ year 1,600 400 900 Benefit/year 8,000 13,000 9,000 Salvage value 3,000 6,000 4,600 Life in years 4 4 4 1. The better alternative between the first increment is ________________. A. Alt. A or Alt. B B. Alt. A C. Alt.C D. Alt. B 2. The better alternative between the second increment is ___________________. A. Alt. B or Alt. C B. Alt. B C. Alt. C D. Alt. AUsing Incremental with EUAW analysis find the best alternative, MARR = %10. should use Excel and show your equations seperately, see below example: [A Benefit - [IC (A/P, i%, n) - Salvage (A/F, i, n)] + A Cost+ G Cost (A/G, i, n)] Data B C A First Cost $2,300,000 $2,780,000 $2,540,000 Salvage Value $82,000 $118,000 $97,000 Annual Benefit $580,000 $670,000 $650,000 M&O $65,000 $78,000 $71,000 M&O Gradient $11,000 $15,000 $12,500 Useful Life, Years 9 9 9 You - ZOOM
- Select the best alternative through internal rate of return analysis. Assume that the minimum attractive rate of return is 10% per year. Machine X |Machine YInitial cost $ 400,000.00 $ 500,000.00Annual operating cost $ 15,000.00 |$ 25,000.00 Annual profit $ 20,000.00 |$ 40,000.00Residual value $ 85,000.00 |$ 100,000.00Project life 15 years | none Engineering Economic AnalysisUsing Incremental with EUAW analysis find the best alternative, MARR = %10. should use Excel and show your equations seperately, see below example: [A Benefit - [IC (A/P, i%, n) - Salvage (A/F, i, n)] + A Cost+ G Cost (A/G, i, n)] A B C $2,300,000 $2,780,000 $2,540,000 $82,000 $118,000 $97,000 $580,000 $670,000 $650,000 $65,000 $78,000 $71,000 $11,000 $15,000 $12,500 9 9 9 Data First Cost Salvage Value Annual Benefit M&O M&O Gradient Useful Life, Years YouAnalyze a CSR capital investment proposal for Ganon Inc. Ganon Inc. is evaluating a proposal to replace its HID (high intensity discharge) lighting with LED (light emitting diode) lighting throughout its warehouse. LED lighting consumes less power and lasts longer than HID lighting for similar performance. The following information was developed: Line Item Description Value HID watt hour consumption per fixture 500 watts per hr. LED watt hour consumption per fixture 300 watts per hr. Number of fixtures 800 Lifetime investment cost (in present value terms) to replace each HID fixture with LED $300 Operating hours per day 10 Operating days per year 300 Metered utility rate per kilowatt-hour (kwh)* $0.12 *Note: A kilowatt-hour is equal to 1,000 watts per hour. a. Determine the investment cost for replacing the 800 fixtures.fill in the blank 1 of 1$ b. Determine the annual utility cost savings from employing the new energy solution.fill in the blank 1 of 1$ c. Should…
- For the following table, if the MARR is 10% per year and a useful life for each alternative of six years that equals the study period. The rank order of alternatives from least capital investment to greatest capital investment is Do nothing Fill the table with the missing values. > A C в Do nothing > A ? (2) ? (4) A capital investment A annual revenues A annual costs A market value A IRR -15,000 -2000 -3000 4,000 900 460 -150 -1,000 6,000 -100 -2,220 3,350 ? (5) (6) 12.7% 10.9% Alternative chosen (1) (3) 1. write the alternative chosen 2. write the two alternatives compared 3. write the alternative chosen 4. write the two alternatives compared 5. what is IRR incremental (final answer) 6. write the alternative chosenAlternative Overall Incremental Rate Of Return in % When Initial Alternative Investment,$ Rate of Return, % Compared with Alternative A В A - 40,000 29 B - 75,000 15 1 -100,000 16 7 20 D -200,000 14 10 13 12 If the alternatives are independent, which should be selected if the company's MARR is 15% per year? (Include: procedure and explain) O Only alternative A O Alternatives A and B O Alternatives A and C Alternatives A, B, and C O OThree independent alternatives are given below. If MARR is 18%, what is your decision? A B C Initial Cost $4.50 $1.90 $1.20 Annual Revenues $4.00 $2.50 $3.00 Salvage Value $0.50 $0.90 $0.00 Annual Operating & Maintenance Costs $1.20 $1.90 $2.70 Estimated life, in years 3 Infinite