7.10 Calculate the maximum heat gain through the floor for a room directly over a boiler room. The air tempera- ture at the underside of the floor is 100°F, and the room air temperature desired close to the floor is 70°F. The floor is 4 in. concrete with vinyl tile finish.

7.10 Calculate the maximum heat gain through the floor for a room directly over a boiler room. The air tempera- ture at the underside of the floor is 100°F, and the room air temperature desired close to the floor is 70°F. The floor is 4 in. concrete with vinyl tile finish.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

* It required to design a ducting system to condition the building shown in figure (1). The uantity of outdoor is (20%) of supply air. Using information in table, find 1- The sensible and latent load for cooling coil. 2- The quantity and condition of supply air to each place. 3- By using equal pressure drop method, design the rectangular ducting system with maximum height side (600mm). 4- Illustrate the all process on psychometric chart. Outdoor 45 °C db & 30% RH Out let type Celling conditioning indoor conditioning 24 °C db & 50% RH diffuser Number of diffuser 2 for each place 15 kpa 10 kpa 15 kpa By pass factor Apparatus dew point 9°C Ap losses diffuser Ap losses filter Ap losses coil 0.15 R/w 1.5 6m 6m 6m Room (1) Room (2) Room (3) 4m RSH=8KW RSH=6KW RSH=8KW RLH=2KW RLH=1KW RLH=2KW 2m AHU Mechanical Room (4) RSH=20KW 4m Room RLH=3KW 4m 14m
* It required to design a ducting system to condition the building shown in figure (1). The uantity of outdoor is (20%) of supply air. Using information in table, find 1- The sensible and latent load for cooling coil. 2- The quantity and condition of supply air to each place. 3- By using equal pressure drop method, design the rectangular ducting system with maximum height side (600mm). 4- Illustrate the all process on psychometric chart. Outdoor 45 °C db & 30% RH Out let type Celling conditioning indoor conditioning 24 °C db & 50% RH diffuser Number of diffuser 2 for each place 15 kpa 10 kpa 15 kpa By pass factor Apparatus dew point 9°C Ap losses diffuser Ap losses filter Ap losses coil 0.15 R/w 1.5 бm бm бm Room (1) Room (2) RSH=6KW Room (3) 4m RSH=8KW RSH=8KW RLH=2KW RLH=1KW RLH=2KW 2m AHU Mechanical Room (4) RSH=20KW 4m Room RLH=3KW 4m 14m
I need right solution with clear calculations. A workplace is occupied by 100 people who are averaging 250 Watts/person. The space is measured as 30 meters x 20 meters x 15 meters (L x W x H). What is the internal heat gain of this space given off by a full staff? If you need to provide the workplace 10 air changes per hour, what type of infiltration inflow rate need to be (cubic meters/hour)?
If the cooling tower range and approach are 10 and 15 degrees centigrade respectively, find the cooling tower effectiveness.
Given problem: Tolits is working on a restaurant famous for its soup. His end of shift is 5:00 pm and needs to go home by that time to pick up his wife, Marites for their anniversary date. A customer made a reservation at 5:15 pm and wants his soup to be ready at that exact time. To ensure the quality of the soup, it should be served at a temperature which is exactly 86C. Tolits needs to prepare the soup before the end of his shift. Initially, as Tolits is preparing the soup, its temperature is 21∘C and placed on a pan heated at 149∘C. After 5 minutes, its temperature is 36∘C. The soup is done (cooked) once its temperature is 120∘C. Tolits found out that cooling it in a sink full of cold water, while the faucet is running with the water resulting to roughly constant temperature of 26∘C, could bring the temperature of the soup to 86C to be ready at 5:15 pm. How many minutes before the end of the shift of Tolits should he start cooking soup so that he is done before 5:00 pm and his…
• A 6 MW generator had a thrust of 103,000 lb. The outside diameter of the step bearing is 12 in, and the inside diameter is 8 in. Employ a film thickness of 0.004 in. Use SAE 20 oil at 120 , the specific heat of the oil being 0.6 BTU/lb deg F, and density of 0.307 lb/cu. in Determine: (d) Temperature rise
6. A Thomas meter is located in an air duct of 2 sq ft cross-sectional area. The air weighs 0.083 lb per cu ft, and its specific heat is 0.24. Assume a controlled temperature differential of 5° and heater potential of 110 volts. Plot the velocity as abscissa and amperage as ordinate for veloc- ity 0 to 300 ft per min. Assume constant amperage of 3, and plot tem- perature difference against velocity. Discuss the curves from the stand- point of accuracy of the system. J: よ itet legeted oulindriool oir tube
Please Help me to solve the following physi cal example #1 A Boiler hAS 0.22 m² of net furnace area supported by SA - 36 stay bolts, spuced O.134 by 0.134 m. The mAXimum working pressure is 1, 225 k Pa Calculate: a) diameter of an Stay bolt B) Number of stoybolts re guired Take 3= 114 MPA ond %3D State the paragraph of ASME code used year
5.72 A cold air chamber is proposed for quenching steel ball bearings of diameter D = 0.2 m and initial temperature T₁ = 400°C. Air in the chamber is maintained at -15°C by a refrigeration system, and the steel balls pass through the chamber on a conveyor belt. Optimum bearing production requires that 70% of the initial ther- mal energy content of the ball above -15°C be removed. Radiation effects may be neglected, and the convection heat transfer coefficient within the chamber is 1000 W/m².K. Estimate the residence time of the balls within the chamber, and recommend a drive veloc- ity of the conveyor. The following properties may be used for the steel: k = 50 W/m K, a = 2 x 105 m²/s, and c = 450 J/kg.K. Ball bearing -5 m Cold air Belt V Chamber housing
An evaporative cooling system of 90% saturation efficiency is used for supplying cool air to a greenhouse. The allowable inside temperature is 32 C, when the cooling load is 360kW (50% sensible heat) at outdoor air of 46'Cdb and 26'Cwb. Find the supply air conditions and the air and water flow requirements for the system.
Draw and describe the pyhsical construction, internal energy developed as well as the application of the following set of energy level: 1. Blower 2. Steam Pump 3. AC and DC generators
Calculating the Cooling load of refrigeration for the Chiller and the Electrical Energy Consumed by the chiller. Determine the formular for deriving the kWR (Kilowatts of Refrigeration). (the cooling load for a chiller). Now calculate kWR, kWE and COP, and fill in the missing values of the table (Log started). (Note: majority of kWE has already been calculated), show working out. Time Flow (Litres per second) EnterTemp (C) LeaveTemp (C) kWE (kW) 30/04/2021 8:50 24.21847528 12 5.900000095 66.55913978 30/04/2021 8:51 24.21847528 12 5.900000095 66.55913978 30/04/2021 8:55 23.51422053 12.10000038 6 64.62365591 30/04/2021 8:56 23.51422053 12.10000038 6 64.62365591 30/04/2021 9:00 27.64518476 12.10000038 6.099999905 80.81395349 30/04/2021 9:01 25.62528992 Log Started Log Started Log Started Log Started Log Started 12.10000038 5.699999809 80.11764706