3) a) A wire sample (1 mm in diameter by 1 m in length) of an aluminum alloy (containing 1.2% Mn) is placed in an electrical circuit such as that shown in the figure below. A voltage drop of 432 mV is measured across the length of the wire as it carries a 10 A current. Calculate the electrical conductivity of this alloy Length, I Area, A Sample geometry

3) a) A wire sample (1 mm in diameter by 1 m in length) of an aluminum alloy (containing 1.2% Mn) is placed in an electrical circuit such as that shown in the figure below. A voltage drop of 432 mV is measured across the length of the wire as it carries a 10 A current. Calculate the electrical conductivity of this alloy Length, I Area, A Sample geometry

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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3) a) A wire sample (1 mm in diameter by 1 m in length) of an aluminum alloy (containing 1.2% Mn) is placed in an electrical circuit such as that shown in the figure below. A voltage drop of 432 mV is measured across the length of the wire as it carries a 10 A current. Calculate the electrical conductivity of this alloy - Length, I Area, A Sample geometry b) Copper has an electrical conductivity of 58.00 × 10° S/m and a free electron density of 104 x 10"m³. Calculate the drift velocity of these electrons under an electric field of 0.5 V/m.
1) a) A wire sample (1 mm in diameter by 1 m in length) of an aluminum alloy (containing 1.2% Mn) is placed in an electrical circuit such as that shown in the figure below. A voltage drop of 432 mV is measured across the length of the wire as it camies a 10 A current. Calculate the electrical conductivity of this alloy -Length, / Area, A Sample geometry b) Copper has an electrical conductivity of 58.00 x 106 S/m and a free electron density of 104 x 10²7m²³. Calculate the drift velocity of these electrons under an electric field of 0.5 V/m.
(c) Aluminium is a good conductor of electricity. A 100 m aluminium wire of diameter 2.25 mm is to be used in domestic electrical wiring. If a voltage of 250V and a current of 13 amps are needed, answer the following i. What is the conductivity of the aluminium wire? ii. Give two reasons why aluminium wire is not used in domestic wiring in Zambia? iii. Give three applications of pure aluminium.
OS. The output power of a solar PV module is 120 Watts. Number of cells in module are 36 Estimate the following: (take insolation value as 1100 W/m' and efficiency as 18% ) Total output voltage Total output current Total area of module iv. Area of one PV cell Calculate number of PV Modules required to generate power of 48OW. V. 益

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In the last column in the data table, it says that it's about voltage(v) divided by current(A) is equal to ohms so V/A = ohms. So if it's V/A and if you divide them to get the slope it's (y2-y1)/(x2-x1) then shouldn't V be the y value and A be the x value? And can you also try to use a line of best bit instead of drawing the line through each dot?
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A wire sample (0.75 mm in diameter and 20 cm in length) is placed in anelectrical circuit. A voltage drop of 464 mV is measured across the length ofthe wire as it carries a 2 A current. Calculate the electrical conductivity of thisalloy. From Table 4 below, which gives the conductivities of differentmaterials at 20C, identify the material. MaterialElectrical Conductivity(Sm-1)Manganin 2x106Nickel 14x106Aluminium 30x106Copper 50x106Silver 63x106Table 4. Conductivities of different materials at 20 C.
Conduc-Thor-s. Thor has two square prism conductors that are made of the same ohmic material and with properties indicated below. Conductor Length | Cross-Section Side Length Alpha L Beta L/2 s/4 Suppose both conductors are subject to the same potential difference AV across their length while keeping their temperatures fixed. Which of the following is the correct relation between the electric currents, Ia and IB, through Alpha and Beta? O A. Ia = 8IB O B. 8Ia = Ig O. Ia = 4I8 O D. 4Ig = Ig Clear my choice
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