2. The following 6 pedigrees were determined to show linkage to a trait: Pedigree A: LOD = 1.8 Pedigree B: LOD = 2.2 Pedigree D: LOD = -1.2 Pedigree E: LOD = -2.2
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- A. What is the inheritance pattern of the pedigree illustrated above? Explain in 1 sentence minimum citing two pieces of evidence from the pedigree to support your answer. B. Assuming that the disorder portrayed in this pedigree is very rare, based on your answer in a., what are the most likely genotypes of I-2, Ill-7 and I1-3. C. Based on your answer in a, what are the odds that IV-1 and IV-2 would have an affected male child?a. 1 dominant allele will contribute 120/10 = 12 cm to the base height of the plant.b. The height of the parent plant 1 Genotype of the parent plant 1 – D1D1D2D2D3D3d4d4d5d5 The height of the parent plant 2 Genotype of the parent plant 2 – d1d1d2d2d3d3D4D4D5D5Contributing alleles – D4D4D5D5. The height of the plant without any contributing alleles would be 80 cm. The plant with genotype d1d1d2d2d3d3D4D4D5D5 has 4 contributing allele each of which contributes 12 cm to the base. Hence, the height of the plant with genotype d1d1d2d2d3d3D4D4D5D5 would be 80 + 12 + 12 + 12 + 12 = 128 cm. c. Parents – D1D1D2D2D3D3d4d4d5d5 × d1d1d2d2d3d3D4D4D5D5 Gametes – D1D2D3d4d5 × d1d2d3D4D5 F1 generation – D1d1D2d2D3d3D4d4D5d5 The height of the plants of F1 generation = 80 + 12 + 12 + 12 + 12 + 12 = 140 cm Hence, Genotype of the F1 = D1d1D2d2D3d3D4d4D5d5 Phenotype of…Please consider the pedigree below. There are no cases of false paternity. I B II A 2 3 III AB (A IV в 1 a. Which individual/s definitely has/have Bombay phenotype in the descendants of I-1 and I-2? b. What are the genotypes of individuals II-2 and III-2 at the ABO and H loci?
- Cierra Ballierajh - Pedigree - Go × + resentation/d/1vcm90PtSWx93LtacvlAUJk84UPuJ9DpU8nS94-XrBPQ/edit#slide-id.g97df83752a_0_315 Fit Co add speaker notes 4× ☆ C Quick... 20 + BIUA - PEDIGREES: Problem 7 (continued) This pedigree shows the inheritance of a type of X-linked color blindness. It is a recessive trait. Carriers have NOT been half-shaded in this pedigree. I 어디어디 2 3 4 II 1 2 3 QUESTIONS ... 3. Use the letter "b" to represent the color blindness allele. What is the genotype of individual IV-I? bb 4. What evidence is there that this type of color blindness is recessive? III IV C 3 Emmatheteachie 2020 65°F Prt Scn Home EndSearch the menus (Alt+/) 75% Normal text Calibri в IUA 11 + ... 1.| 2 | 3 | • 4.| 5 6 8 12. Although Laurlanthalasa, Princess of the Qualinesti elves, is known for riding into battle on a silver dragon, this is not her main form of transportation. She generally travels by way of griffon. Although the allele for a "crown" of feathers around the head is dominant, it is rarely found in the wild. This may be due to the fact that it makes the griffons stand out, thus making them less effective hunters and more visible to their natural enemies, evil chromatic dragons. This scarcity also makes them prized by elven royalty. Lauralanthalasa was given a breeding pair of bald griffons by an admirer who claims that they are both hybrids for the crowned gene. Create a Punnett Square to determine if Lauralanthalasa will have any chance using these two griffins to produce crowned offspring. Alleles (letters) and Phenotypes All Genotype and Phenotype Parent Punnett Square Possibilities Genotypes…PEDIGREE ANALYSIS ANSWER THE FOLLOWING QUESTIONS 1. The chart shows a family's pedigree for Hitchhikers Thumb. Is this trait dominant or recessive? 2. How do you know? 3. How are individuals III-1 and III-2 related? 4. How would you name the two individuals that have Hitchhiker"s thumb? 5. Name the 2 individuals that were carriers of Hitchhiker's Thumb. 6. Is it possible for individual IV-2 to be a carrier? Why?
- 5 & :56M ******* 24 DIHYBRID CROSSES DRV 0 Stv T alı A @ zladenA 9160p2-id2 bns obidalbaneoviene da II\ MOD YR 21 $59A ... Create a dihybrid cross and determine the expected phenotypic percentages of the offspring of two corn plants both of which are heterozygous for colour and texture (RrTt X RrTt). Don't forget to include clear let statements, and follow the all six steps taught on solving genetics problems. insig moni nellog: bna. zoom. A corn geneticist has three pure lines of genotypes a/a ; B/B ; C/C, A/A ; b/b ; C/C, and A/A ; B/B ; c/c. All the phenotypes determined by a, b, and c will increase the market value of the corn; so, naturally, he wants to combine them all in one pure line of genotype a/a ; b/b ; c/c. a. Outline an effective crossing program that can be used to obtain the a/a ; b/b ; c/c pure line. b. At each stage, state exactly which phenotypes will be selected and give their expected frequencies. c. Is there more than one way to obtain the desired genotype? Which is the best way?Assume independent assortment of the three gene pairs. (Note: Corn will self or cross-pollinate easily.Please consider the pedigree below. There are no cases of false paternity. I II III IV в 1 a. Which individual/s definitely has/have Bombay phenotype in the descendants of I-1 and I-2? b. What are the genotypes of individuals II-2 and III-2 at the AB0 and H loci? Please label your answers a and b, Il-2: and Ill-2:.
- Pedigree Analysis Is a Basic Method in Human Genetics Using the pedigree provided, answer the following questions. a. Is the proband male or female? b. Is the grandfather of the proband affected? c. How many siblings does the proband have, and where is he or she in the birth order?. In a dihybrid test cross, the following results were obtained: A‑B‑, 121; A‑bb, 107; aaB-, 115; and aabb, 93. Do these data approximate a dihybrid test cross ratio with independent assortment? Complete the following table and answer the related questions. Phenotype O E (O-E) (O-E)2 (O-E)2/E A_B_ 121 A_bb 107 aaB_ 115 aabb 93 Totals X2= Instructor’s Calculation of X2= 4.0367 In interpreting this X2 value, you have ____3_______degrees of freedom. In this case do you accept/reject the hypothesis that these data approximate a dihybrid test cross ratio with independent assortment? What is the probability that the deviations are due to chance alone?Using your calculated expected numbers and the following observed numbers for each progeny phenotype, calculate chi-square: 320 short, black, rough hairs 80 long, black, rough hairs Transform the calculated fraction for each phenotype into a number to 2 decimal places, then add and type answer AS NUMBER rounded to one decimal place. 7 2 3 4 % 5 MacBook Pro 6 7 8