1. Problem No. 1: For the beam and loading shown and knowing that the distributed load w can be expressed as a function of x, w=kx², determine: a) The value of k so that the distributed load at point A is 400 lb/ft and at point B is 100 lb/ft. (Hint: x axis along beam ACB with the origin at C) b) The magnitude and location of the resultant of the distributed load using the integration approach. c) Verify your results with the table in Figure 5.8.A for a parabolic spandrel. d) The reactions at the beam supports. 400 lb/ft A 12 ft Parabola 6 ft- 100 lb/ft B

Elements Of Electromagnetics
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ISBN:9780190698614
Author:Sadiku, Matthew N. O.
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1. Problem No. 1: For the beam and loading shown and knowing that the distributed load w can
be expressed as a function of x, w=kx², determine:
a) The value of k so that the distributed load at point A is 400 lb/ft and at point B is 100
lb/ft. (Hint: x axis along beam ACB with the origin at C)
b) The magnitude and location of the resultant of the distributed load using the integration
approach.
c) Verify your results with the table in Figure 5.8.A for a parabolic spandrel.
d) The reactions at the beam supports.
400 lb/ft
A
12 ft-
Parabola
6 ft-
100 lb/ft
B
Transcribed Image Text:1. Problem No. 1: For the beam and loading shown and knowing that the distributed load w can be expressed as a function of x, w=kx², determine: a) The value of k so that the distributed load at point A is 400 lb/ft and at point B is 100 lb/ft. (Hint: x axis along beam ACB with the origin at C) b) The magnitude and location of the resultant of the distributed load using the integration approach. c) Verify your results with the table in Figure 5.8.A for a parabolic spandrel. d) The reactions at the beam supports. 400 lb/ft A 12 ft- Parabola 6 ft- 100 lb/ft B
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