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- The wall (thickness L) of a furnace is comprised of brick material (thermal conductivity, k = 0.2 Wm¯' K'). Given that the atmospheric temperature is 0°C at both sides of wall, the density (p) and heat capacity (c) of the brick material are 1.6 gm cm³ and 5.0 J kg K¯l respectively. du Solve pc = k- subject to initial conditions as u(x,0) = x²(L – x). ốt Consider the case 2=- p² only.Instead of 0.q, you have to use my student ID using the last 3 digits. If the last 3 digits of my student ID are 495.q use 495 instead. Question 2: Equivalent Nodal Forces of 2-D Plane Finite Elements ( For the four-node linear plane element shown below with a uniform surface traction along its side 2-3. You are required to evaluate the force matrix by using the energy equivalent nodal forces. Let the thickness of the element be t= 10 + 0.q mm. T = 20 + 0.q N/mm2 (0, 4) (5, 4) (0, 0) (8, 0) 1 2I want to know how much heat the tube lost due to the material it is made of aluminum or steel. Even if it is a small difference in temperature. I want to know which material Conduct Heat the Best through this problem. material: Aluminum, steel ( the dimensions are the same for both) temperature touching cylinder: 65 Celcius temeprature inside cylinder 64.5 celsius room temperature 24 celcius Tube measurements outer radius r1 r1 = 4 in inner radius r2 r2 = 3 in outer circumference C1 C1 = 25.132741228718 in inner circumference C2 C2 = 18.849555921539 in height h = 8 in wall thickness t = 1 in
- Give True or False for the following: 1.In liquids and gases, heat transmission is caused by conduction and convection 2.The surface geometry is the important factor in convection heat transfer 3. The heat transfer by conduction from heated surface to the adjacent layer of fluid, 4. The heat transfer is increased in the fin when &> 1 5.The unit of the thermal diffusivity is m²/s 6. Temperature change between the materials interfaces is attributed to the thermal contact resistance 7. A material that has a low heat capacity will have a large thermal diffusivity. 8. Heat conduction flowing from one side to other depends directly on thickness 9.Fin efficiency is the ratio of the fin heat dissipation with that of no fin 10.The critical radius is represented the ratio of the convicted heat transfer to the thermal conductivityQuestion 2: Air at the temperature of T1 is being heated with the help of a cylindrical cooling fin shown in the figure below. A hot fluid at temperature To passes through the pipe with radius Rc. a) Derive the mathematical model that gives the variation of the temperature inside the fin at the dynamic conditions. b) Determine the initial and boundary conditions to solve the equation derived in (a). air T1 Re Assumptions: 1. Temperature is a function of onlyr direction 2. There is no heat loss from the surface of A 3. Convective heat transfer coefficient is constantCalculate the stiffness matrix for the Q8 element shown below. Make use of the shape functions in natural coordinates and the Jacobian calculated in previous problems. Use 2x2 Gaussian numerical integration. Use plane strain conditions (for unit thickness) with E=200E9 (MPa) and nu=0.25. The final answers is F1= 0.18452e12. I have attached my matlab code below. Please look thru it and correct it. Thanks. u=sym('u') %%ztav=sym('v') %%eta x1=1x2=2x3=3.5x4=3.6x5=4.0x6=2.3x7=1.2x8=0.8 y1=1y2=1y3=1.3y4=2.3y5=3.3y6=3.2y7=3.0y8=2.0X=[x1;x2;x3;x4;x5;x6;x7;x8]Y=[y1;y2;y3;y4;y5;y6;y7;y8]%% diff of ztaDN1Du=1/4*(1-v)*(2*u+v);DN2Du=-u*(1-v);DN3Du=1/4*(1-v)*(2*u-v);DN4Du=1/2*(1-v^2);DN5Du=1/4*(1+v)*(2*u+v);DN6Du=-u*(1+v);DN7Du=1/4*(1+v)*(2*u-v);DN8Du=-1/2*(1-v^2); %% diff of etaDN1Dv=1/4*(1-u)*(2*v+u);DN2Dv=-1/2*(1-u^2);DN3Dv=1/4*(1+u)*(2*v-u);DN4Dv=-v*(1+u);DN5Dv=1/4*(1+u)*(2*v+u);DN6Dv=1/2*(1-u^2);DN7Dv=1/4*(1-u)*(2*v+u);DN8Dv=-v*(1-u);%% find dx/du dx/dv, dy/du and dy/dva=[DN1Du, DN2Du, DN3Du,…
- Show step by step solution. Use Mpa unit Sn = 72. The coefficient of linear expansion of aluminum is 0.000023/C°. An aluminum rod 5 meters long is heated so that its temperature rises from 25 °C to 50 °C. What is the change in its length? 3. A rectangular block of concrete has a volume of 5 cubic meters and initial temperature of 30°C. By how much will it expand if the temperature rises by 5 C°? The coefficient of thermal expansion of concrete is 10/C". 4. Cylindrical bars of steel and brass with the same diameter and length are joined at one end. The tenperature of the steel bar is 350 K; brass, 500 K. What is the temperature at the junction? The thermal conductivity of steel is 45 W/mol K; brass, 116.Q3: Consider evaluation of different temperatures of solar photovoltaic/thermal system (PVT) as shown in Figure 1(a). The following set of differential equations represent energy balance equations to be solve using matrices and eigenvalues dTglass = -0.75Tglass + 0.75TPVT (1) dt - 1.18Tglass – 22TpyT + 237wax (2) dt dTwax 12Tglass + 18TpyT – 19 Twax (3) dt Where, Tptass, TPVT, and Twax, are temperatures illustrated in Figure 1(b). At time t-0 the initial conditions are Tglass = 35 , Tpyr = 33, and Twax = 31 °C. Cold sappty In frem water Tank Glass PVT Enpann Nane-PCMPVT Collector Wax Tubes Sterg Tank Mat Nanofluid Heat Exchanger Tepe Contalner Tuek et Pump for drain
- Solve it with Roth table please, I do not understand why when I solve it the third row s^1 is 5K^2+25K+2/(K-3) for the equation:Calculate the stiffness matrix for the Q8 element shown below. Make use of the shape functions in natural coordinates and the Jacobian calculated in previous problems. Use 2x2 Gaussian numerical integration. Use plane strain conditions (for unit thickness) with E=200E9 (MPa) and nu=0.25. I have attached my matlab code below. Please look thru it and correct it. Thanks. u=sym('u') %%ztav=sym('v') %%eta x1=1x2=2x3=3.5x4=3.6x5=4.0x6=2.3x7=1.2x8=0.8 y1=1y2=1y3=1.3y4=2.3y5=3.3y6=3.2y7=3.0y8=2.0X=[x1;x2;x3;x4;x5;x6;x7;x8]Y=[y1;y2;y3;y4;y5;y6;y7;y8]%% diff of ztaDN1Du=1/4*(1-v)*(2*u+v);DN2Du=-u*(1-v);DN3Du=1/4*(1-v)*(2*u-v);DN4Du=1/2*(1-v^2);DN5Du=1/4*(1+v)*(2*u+v);DN6Du=-u*(1+v);DN7Du=1/4*(1+v)*(2*u-v);DN8Du=-1/2*(1-v^2); %% diff of etaDN1Dv=1/4*(1-u)*(2*v+u);DN2Dv=-1/2*(1-u^2);DN3Dv=1/4*(1+u)*(2*v-u);DN4Dv=-v*(1+u);DN5Dv=1/4*(1+u)*(2*v+u);DN6Dv=1/2*(1-u^2);DN7Dv=1/4*(1-u)*(2*v+u);DN8Dv=-v*(1-u);%% find dx/du dx/dv, dy/du and dy/dva=[DN1Du, DN2Du, DN3Du, DN4Du, DN5Du, DN6Du,DN7Du,…Question 2: Air at the temperature of T1 is being heated with the help of a cylindrical cooling fin shown in the figure below. A hot fluid at temperature To passes through the pipe with radius Rc. a) Derive the mathematical model that gives the variation of the temperature inside the fin at the dynamic conditions. b) Determine the initial and boundary conditions to solve the equation derived in (a). air To Re Assumptions: 1. Temperature is a function of only r direction 2. There is no heat loss from the surface of A 3. Convective heat transfer coefficient is constant