Expermint 3-Torsion Test

Using the tensile test simulation tool, a. generate the stress-strain curve for aluminum b. Indicate the following points in the stress-strain curve for aluminum and give the corresponding values: limit of proportionality elastic limit 0.2% offset yield stress (include the graph illustrating how this was determined) ultimate stress fracture stress c. Calculate modulus of elasticity.   d. compare aluminum with nylon (include the related graph) and answer the following: Which has higher tensile strength? Provide the necessary values to support the answer. Which is stiffer? Support your answer with calculations.

T. T*LT eJ*ee Fig(3) Fig(2) Fig(1) Discussion : 1- Through the results of the experiment and graphs, what is the effect of the following factors on the twisting of a material if it has a fixed length: L.(Material Type, G, J, Stiffness) 2- Which is better in torsion applications, solid columns or hollow columns, if they are made of one material and have the same external length, ang diameter, reinforce answer practically and theoretically by comparing the properties (Mass, J, G). 3- What is the effect of increasing the length of the axes or columns on the angle of torsion with the stability of the material and the load? 4- Are there positive applications of convolution? Give examples.

02: A steel specimen 12mm diameter has gauge length 50mm. the steel specimen had tested via tensile test under maximum load 66KN with elongation 7.5mm, and the yield load of this specimen is 15KN with elongation 2.4mm. Calculate: 1- The engineering ultimate stress (ultimate tensile strength), and engineering strain at this point. 2- The engineering stress and strain at yield point. 3- The modulus of elasticity, and the modulus of resilience. 4- The final or fracture strain of a steel specimen, if you know that the final length of specimen after testing is 58.5mm. 5- The true stress and strain for ultimate point.

Mild steel 1 Young;s modulus 1219.5 Yield strain and stress (0.4101,500.08) Failure stress and strain :not able to find because the given data shows the experiment did not reach the failure point.  if the material stress and strain does not reach a failure point ,what dose it means , does it means that the material is more stronger?

An electric car manufacturer is looking to utilize some stock AISI 8740, hot rolled steel bars that are around 2 inches in diameter for their conveyor system that is being set up to start producing their own batteries. The data sheet shows the the bars to have 132,000 psi tensile strength, 87,500 psi yield strength, and 16.7% elongation. A hardness of 262 Bhn allows it to be finish machined after heat treatment. They keep their workspace at 70°F. What is the working endurance strength, Se? 39,750 psi 28,562 psi 42,500 psi 33,400 psi

10. Measure the diameter of impression using the profile projector and compute for the hardness number using the formula: Where: 2P P – Applied Load D - Diameter of steel ball (8.0 mm) BHN «D(D- /D² – d² d - Ave. diameter of indentation | Raw data: Diameter Specimen (carbon steel) d1 d2 Air cooled 5.13 5.22 Oil quenched Water quenched 4.12 4.36 3.74 3.81 Note: All dimensions are in mm.

In the First project: you have been asked to perform tensile testing for four different materialsand analyse the results and work on some NDT process selection:a. For the results shown in Table 1 of the tensile testing that you have performed, find thefollowing, if you know that the original length of specimen is 20.8 mm and the original diameteris 6.4 mm. Fill the calculated results in the summary table below (Table 1):1. Plot the engineering stress versus engineering strain for each material and L-D Diagram.2. Compute the modulus of elasticity, E in GPa.3. Determine the yield strength at a strain offset of 0.002.4. Determine the tensile strength in MPa.5. What is the approximate %El ductility, measured by percent elongation?6. Compute the modulus of resilience.7. Determine the fracture stress in MPa.8. Compute the final area (Af) in mm2.

A three-point bending test was performed on an aluminum oxide specimen having a circular cross section of radius 5.6 mm; the specimen fractured at a load of 4280 N when the distance between support points was 43 mm. Another test is to be performed on a specimen of this same material, but one that has a square cross section of 18 mm in length on each edge. At what load would you expect this specimen to fracture if the support point separation is maintained at 43 mm? Ff= N

Q7_What is the difference between true strain and engineering strain? What is the relationship that binds them? Q8_ When do the "ears" appear in drawn cup, through cup drawing tests? Q9_Could we use results of tensile tests predict impact failure behavior, why? Q10_Could you estimate ductile-to-brittle transition temperatures for metals having hexagonal close-packed structure, why? Q11_Can creep of metals happen in room temperature, when? Solve a question 7_8_9_10_11

If material A is observed to have twice the modulus of rigidity but the same Poisson's ratio and yield shear stress than that of material B, then which of the following comparisons is always true? Select one: Material A can resist higher normal stresses than material B can before permanent normal deformations occur. O b For the same load that brings the materials to plastic behavior, material A will experience larger permanent shear deformations than material B. Material A can resist higher shear stresses than material B before permanent shear deformations occur. O d. Material B is has a lower ultimate stress than material A.

A rod specimen of ductile cast iron was tested in a torsion-testing machine. The rod diameter was 16 mm, and the rod length was 360 mm. When the applied torque reached 254.8 N-m, a shear strain of 1780 microradians was measured in the specimen. What was the angle of twist in the specimen? Part 1 Calculate the shear stress in the specimen. Correct Answer: T= 316.97 eTextbook and Media Part 2 Correct Use Hooke's Law to calculate the shear modulus of the specimen. answer: G= 178073.034 Part 3 eTextbook and Media Incorrect MPa Answer: Calculate the angle of twist in the specimen. D=0.8006 MPa O Attempts: 1 of 5 used Attempts: 1 of 5 used

Question One a) In a tensile test, material mechanical properties are determined by relating deformations to the applied forces. i. Sketch a typical specimen used in such tests and on it indicate two important dimensions i Sketch the difference you would cxpect in tensile and compressive deformations Sketch a stress-strain curve/graph you would expect from such a test and on it indicate how you would obtain (1) Young's modulus, E(2) clastic limit,oei(3) yield strength ay and (4) ultimate tensile strength duTS ii. b) In such a test, as the one in (a) above, a specimen manufactured from steel, and had an original diameter of 12.8 mm and gauge length of 50.8 mm. The resulting data, stress and strain, is listed in the table below. Strain 0.007 0018 0.032 005 0 052 0.056 0.06 0.005 0072 0.076 011 0.15 017 022 024 (m/ m) Stress 80.8 218 390 540 600 630. 650 640 634 643 745 851 885 815 770 (MPa) By plotting stresses on the vertical axis and strains on the horizontal axis, plot a stress-strain…

Calculate the yield strength, tensile strength, strain and Young’s Modulus of a cylindrical tensile test specimen with original dimensions, 21mm length and 5mm diameter, if at the limit of its elastic deformation the force exerted in a tensile test was 3120N and the maximum force the material withstood was 4125N. At its elastic limit the specimen was found to have a length of 23.5 mm.

Q2/ Aluminum tensile specimen with 12.5mm diameter, a gauge length of 50.8mm and the final diameter was 10.5mm. • Plot the engineering stress-strain curve and the true stress- strain curve. Determine proportion limit, young's modulus, the yield point, the ultimate tensile strength, the failure stress on drawing? • Determine Ductility? • Determine Resilience modulus and toughness modulus? 0.006 0.008 0.012 0.017 Strain mm/mm Apparent Stress N/mm 100 0.004 0.22 0.25 0.27 150 200 290 325 480 450 410 True stress N/mm 100.1 150.3 201 326 400 500 550 620

Question 3: Describe how the compatibility equation of deformation can be used to solve statical indeterminate structures?

10. A standard steel specimen of 0.504" diameter elongated 0.0125" in an 8" gage length during a test where it was subjected to a tensile force of 6249 lb. If the specimen's gage length was measured to be 8.0025" after the test was over, what was the permanent plastic deformation? What is the elastic deformation and what is the modulus of elasticity of that metal? r PL AE

Bronze alloy, the following true stresses produce the corresponding plastic true strains, before to necking: On the basis of this information, compute the true stress necessary to produce a true strain of 0.25 and then find the engineering stress and strain at this point. True stresses (MPa) True strain 354 0121 70 018

10. A torsion test shows that the shear modulus of an aluminumspecimen is 4.6 x 106psi. When the same specimen is used in atensile test, the modulus of elasticity is found to be 12.2 x 106psi. Find the Poisson’s ratio for the specimen.

Stress (MPa) 1000- 800 600 400- 200 0 0.0 - PMMA 1% TPU 1% Ultem 1% Pristine 0.4 0.8 1.2 1.6 Strain (%) 2.0 2.4 2.8

Q5/ The Stress-strain diagram of any ductile metal or alloys reveals several critical points. Based on your understanding of this diagram, plot it schematically (without scale) and specify the following points: 1. Tensile streng th 2. Yield strength 3. At what stage the necking occurs 4. The fracture strength 5. The elastic zone 6. The Plastic zone 7. Young modulus of elasticity

At higher temperature, strength and strain hardening are increased, whereas, ductility is decreased which permits greater plastic deformation True False O Saaly i The strength constant (C) is increased with increasing of temperature True O False O The metal is becoming weaker as strain increases, this is because of .strain hardening (work hardening) property True O False O ly The engineering stress and strain are defined relative to the instantaneous area and length of test specimen True O False O In sheetmetal working processes, the surface area-to-volume ratio of .w.p. is low True O False O aly ihi Determine the value of the strain-hardening exponent for a metal that will cause the average flow stress to be 70% of the final flow stress after deformation 0.444 0.421 0.422 0.428 aaly i For pure copper (annealed), the strength coefficient = 330 MPa and strain-hardening exponent = 0.52 in the flow curve equation. Determine the average flow stress that the metal experiences if it is…

A torsion test most often is performed on shafts to determine the material and/or the torsional properties of the material. Your role in a recognized material testing company is to determine the material of a circular bar from experimental data of angle of twist obtained from a torsion test to be selected later in a design of a gearbox machine. The datasheet provides the following tables: Modulus of Rigidity (GPa) 60 < G < 80 Material Aluminum Alloy 1100-H14 Gray Cast-Iron 200 < G < 300 The shafts have the following details: Shafts Geometrical Details Gauge Length (mm) Diameter (mm) 144.53 23.5 The data obtained from the test are collected for shaft A are presented by the following testing data table: Shaft A Torque KN.m Twist Angle (Degree) 32.45 15.81 110.92 110.92 Elastic Range Your manger asked you to perform the following: 1- Calculate the polar 2nd moment of inertia in mm*. 2- Determine the materials of shaft A using the tests data and datasheet, explain your results. 3- Plot the…