4

Complete the following set of profile level notes to answer questions [Select] [Select] [ Select] Station BS BM1 2.565 1+100 1+200 TP1 1+300 1+400 1+500 HI FS IFS TP2 1.946 ? 1.946 BM2 ? 33.562 3.741 1.768 2.543 The HI at TP1 is 1.154 0.752 3.051 Elevation (m) 32.756 ? 31.500 30.429 The elevation at station 1+100 is The backsight reading at TP1 is

Problem 1 Fill the table and use 25% expansion factor Fill Vol. Cut Vol. Fill Vol. Cum. yd (25%) (-) Station Cut, ft? Fill, ft? yd' (+) yd3 Vol. yd3 120+00 0. 121+00 195 122+00 239 123+00 425 124+00 410 56 124+50 90 111 125+00 0. 183 126+00 200 127+00 199 128+00

Module 03- Coursework Activity 03 Complete the Differential Leveling Notes by providing data to the unknown quantities. STA HI FS IFS BM33 0+00 1+00 2+00 3+00 TP1 4+ 40 5+00 6 +00 TP2 8+00 9 +00 10+00 11+00 BM34 BS 2.32 2.77 2.22 3.43 3.06 2.45 1.7 2.2 1.2 0.9 2.2 3.7 1.6 2.8 3.6 2.0 1.1 ELEV 328.70 m

Answer =109 cfs

2. Complete the following set of profile level notes and show the customary arithmetic check. Plot the profile (you can use a graphing paper for the plot). STA BS HI FS IFS ELEV BM, 0 + 00 + 10 TP1 0.95 220.90 m 3.0 2.3 3.13 0.64 0+22 2.7 +30.5 2.8 +34.2 3.1 +39.3 0.5 +42.5 0.8 TP2 0+45 2.16 1.28 0.9 +48.6 1.2 +50 1.7 +53.7 2.8 ТРз 0.82 2.37 TP4 1.35 3.50 + 75 3.0 BM, 1.99

1:49 A ה 5% ll ,ll > וN 1.jpg Area Wire Diameter in sq. mil cir. mil MCM mm A 1.02 mm B (51/1270) in 40.1575 mil II

Complete the following set of profile level notes and show the customary arithmetic check. STATION BS HI FS IFS ELEVATION 115.32 m BM1 0+ 05 010 0.77 2.1 25 TP1 1.66 3.66 017 0+21 0+ 25 0+ 29 23 25 2.7 13 0+33 19 2.1 TP2 2.22 2.88 0+ 38 0.4 08 13 0 50 14 TP3 1.77 3,44 0+ 55 17 TP4 2.15 2.71 2.9 0.69 28 BM2 2.67

survey question: fill the angel measurement report Table 2 Angle measurement records Positions Half round One round Stations Objects HC readings of VC angles angles АЗ A4 FL 00 00 05 A1 95 40 20 A1 FR 275 40 41 A4 180 00 30 00 00 04 89 53 36 269 53 30 179 58 56 00 00 02 A1 АЗ FL A2 A2 FR АЗ A2 Al FL 81 48 10 261 47 37 180 01 01 A4 A4 FR A1 00 00 15 92 39 05 255 36 27 162 57 53 A4 A2 FL A3 A3 FR A2

1. Ah = [ Select ] 2. Av [ Select ] 3. MA = [ Select ] %3D 4. C, = [Select ] 5. Dy = [ [ Select ] 50 k-ft В C D 2.5 15 ft k/ft A 10 ft 10 ft El = constant %3D > > > > >

Answer Keys: By = 49,111.11 N Vcmax = -9277.78 N +Mcmax = 54,222.22 N-m

1. PROFILE zile level notes and show the customary arithmetic check. LEVELING. Complete the following of pro- set STA BS HI FS IFS ELEV BM - a 1.24 234.51.m TP - 1 I+ 00 + 25 + 50 + 75 ТP - 2 2+ 00 + 25 + 50 TP +3 3.40 4.6 2.8 3.6 2.4. 3,21 2.46 1.2. 3.2 2.8 3.06 2.74 BM - D 2.40

Which feature control frame would you use to tolerance the one-inch slot perpendicular to datum feature A and symmetrical with the four-inch feature within a tolerance of .005 at MMC in the drawing below? Use MMC and MMB wherever possible. 1.000-1.010 138 4.000-4.020 A. B. C. D. E. O E O O A с B B OD .005(M) A 4.00 .005 MA BM 1 005 (M) A BM 0.005MABM .005 M AMB 2.00 A

Please answer thank you. Choices : a.895 b.598 c.958 d.589

Compute for the unknown Line AB BC CD DE EA LINE AB BC CD DE EA Distance 300 400 250 350 277.96 DISTANCE 250 UNKNOWN 300 UNKNOWN 400 Bearing S 37 30 E S 43 15 W N 73 W UNKNOWN UNKNOWN BEARING N 73 00 W N 12 45 E S 37 30 E N 65 45 E S 43 15 W ■

5 122 lab. 12 10 4 9 8 7 9 G 4 54 MM CM DE 20 20 3 104 14 EL 26 50 2 3 1 10 INCH 6 Normal 躁 Strong Subtitle Styles AaB B AaBbCcDd AaBbc Title 1 No Spac... Subtle Question 2: Given that this soccer field inside the track has a distance of 100 meters from goal to goal, determine the Representative Fraction (RF) of this image. Focus E

D. OMMITED MEASUREMENTS 1. Compute the omitted measurements for lines 3-4 and 4-5 Latitude Departure Line Bearing Distance N (+) S(-) E (+) W (-) 1 2 s 18 11 w 59.13 N 68 15 2 3 w 71.70 3 4 50.50 4 5 N 43 23 E 5 6 N 77 45 E 69.92 6 1 s 21 29 E 57.86

2. Complete the profile level notes shown below, perform the customary arithmetic check, provide a detailed sketch, and a detailed solution. STA BS HI FS IFS ELEV BM25 0+ 000 5.3650 254.1458 2.3225 2+ 000 1.3256 4+ 000 2.8945 6+ 000 1.9978 TP, 4.2544 5.4444 8+ 600 1.6452 10 + 200 6.5874 12 + 500 5.8942 14 + 900 5.6100 16 + 300 3.2542 18 + 700 2.6540 TP2 2.0021 6.5566 16 + 200 7.4845 18 + 850 4.5100 20 + 300 5.8900 22 + 070 3.2010 BM26 5.6412

QUESTION 4 Table Q4 shows the booking of levelling fieldwork conducted during light rain. It was later found out that some of the readings are illegible due to the rain water. Complete the booking and perform all checks. Table Q4 BS IS FS HPC RL Remarks 19.245 17.155 TBM 1 RL 17.155 2.010 A 17.169 3.431 0.461 18.784 с (СР) 3.079 D 1.471 20.744 E ? 21.455 ТВМ 2 RL 21.459

QUESTION 4 Table Q4 shows the booking of levelling fieldwork conducted during light rain. It was later found out that some of the readings are illegible due to the rain water. Complete the booking and perform all checks. Table Q4 BS IS FS HPC RL Remarks ? 20.662 18.569 TBM 1 RL 18.569 2.010 ? ? 18.645 3.467 0.418 20.244 C (CP) 3.053 ? D E TBM 2 RL 22.968 1.467 22.243 22.959 !! IMPORTANT ! SAVE THIS QUESTION PAPER (SHADED AREA) IN PDF AND SUBMIT IT TO THE E-LEARNING WEBSITE

Task 2 The following offsets are taken from a chain line to an irregular boundary towards right side of the chain line. chainage 0 25 50 75 100 125 150 Offset 'm' 3.6 5.0 6.5 5.5 7.3 6.0 4.0 Common distance d =25m You have been asked to estimate the area using the following methods and compare and comment on their difference and accuracy. a) Trapezium Rule b) Simpson's Rule

Зсcos'x - 1 To evaluate 1- sin?x dx, the integrand can be transformed to A J(3tan?x - csc²x) dx ® J3cos x (1- sec²x) dx © (3 cos x - sec?x) dx O S(3cos?x + csc?x) dx D (Зс

From the field notes of a closed traverse shown below, Lines Bearing AB BC CD DA N 53'27' 0"E S 66 54' 0"E S 29'8' 0"W N 52'0' 0"W Distances 59.82 70.38 76.62 95.75 ma) Determine the Error of closure b) Relative Precision (in fraction form; format: 1/wholenumber)

The technical description of a six-corner lot is tabulated in the table below. LINES BEARING DIST LAT DEP DMD DPD ТР-1 15 11 20 3051.74 1-2 33 W 190.30 2-3 33 3 W 300.00 3-4 33 3 W 4-5 89 54 E 302.27 5-6 6. 6-1 W 312.82 a. Plot the given data. b. Calculate the distances of line 3-4 and line 5-6. c. Calculate the area of the lot by DMD.

Generating project specs from BIM data is the only means to create a specification deliverable True False 49°F Sunny esc échappe F1 F2 F3 F4 % F5 F6 A &

Pls. Answer it completely

somehow supoose to give this answers,  but how??? can u provide nicely to anderstand calculations  Cy=2 Cx= 11.6By= 2 Bx=11.6Ay=8Ax=11.6