2. Complete the profile level notes shown below, perform the customary arithmetic check, provide a detailed sketch, and a detailed solution. STA BS HI FS IFS ELEV BM25 5.3650 254.1458 0+ 000 2.3225 2+ 000 1.3256 4+ 000 2.8945 6+ 000 1.9978 TP, 4.2544 5.4444 8+ 600 1.6452 10 + 200 6.5874 12 + 500 5.8942 14 + 900 5.6100 16 + 300 3.2542 18 + 700 2.6540 TP2 2.0021 6.5566 16 + 200 7.4845 18 + 850 4.5100 20 + 300 5.8900 22 + 070 3.2010 BM26 5.6412

2. Complete the profile level notes shown below, perform the customary arithmetic check, provide a detailed sketch, and a detailed solution. STA BS HI FS IFS ELEV BM25 5.3650 254.1458 0+ 000 2.3225 2+ 000 1.3256 4+ 000 2.8945 6+ 000 1.9978 TP, 4.2544 5.4444 8+ 600 1.6452 10 + 200 6.5874 12 + 500 5.8942 14 + 900 5.6100 16 + 300 3.2542 18 + 700 2.6540 TP2 2.0021 6.5566 16 + 200 7.4845 18 + 850 4.5100 20 + 300 5.8900 22 + 070 3.2010 BM26 5.6412

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Similar questions

2. Complete the following set of profile level notes and show the customary arithmetic check. Plot the profile (you can use a graphing paper for the plot). STA BS HI FS IFS ELEV BM, 0 + 00 + 10 TP1 0.95 220.90 m 3.0 2.3 3.13 0.64 0+22 2.7 +30.5 2.8 +34.2 3.1 +39.3 0.5 +42.5 0.8 TP2 0+45 2.16 1.28 0.9 +48.6 1.2 +50 1.7 +53.7 2.8 ТРз 0.82 2.37 TP4 1.35 3.50 + 75 3.0 BM, 1.99
(b)- A page of a level with some missing readings is reporduced below. Fill in the missing entries along with the necessary arithmetical checks. Station I.S F.S Rise 1 2 3 4 5 6 7 8 9 10 11 Total = B.S 3.650 X -2.170 X 6.490 X 2.830 3.640 2.410 2.320 3.000 X X 2.420 2.750 Fall 1.320 2.750 1.320 R.L 108.260 Remark
Completely fill up the missing data ((marked with “X”) and apply arithmetical check. STA BMa 0+00 0+10 0+17 TP1 0+25.622 0+30.567 0+45.890 0+60.134 0+85 0+90.567 0+112.750 BS 0.987 HI 122.496 2.521 TP2 1.567 121.632 TP3 2.143 120.275 FS 0+115 BMb Note: All Values are in meters 1.991 IFS 1.243 2.750 1.524 3.124 1.789 2.125 2.897 1.890 ELEV 120.895 119.731 120.117 119.746 XxXxXxXxXxX 118.972 120.065 118.132 118.385
Problem II. For fiqure shown below, -20 40.50 2a/3 0.5a a. Determine the coordinates of the centroid
SHOW COMPLETE SOLUTIONS 2. Complete the missing data. LINE DISTANCE (meter) BEARING 1-2 S 73.45° E N 18.19° E S 74.21° E S 19.71° W S 81.90° W N 52.88° W 2-3 123.4450 3-4 140.2336 4-5 146.3536 5-6 164.8688 6-7 194.7219 7-1 96.3024
Please compute for letter a and letter b
Table: Profile Elevation STATION BS BM1 0+000 +005 0+010 0+015 0+020 0+025 0+030 0+035 0+040 0+045 0+050 0+055 0+060 0+065 0+070 0+075 0+080 0+085 0+090 0+095 0+100 0+105 TP1 0+110 0+115 0+120 0+125 0+130 0+135 0+140 0+145 0+150 0+155 0+160 0+165 0+170 0+175 1.515 1.700 HI FS 1.109 IFS 1.520 1.508 1.490 1.470 1.455 1.408 1.418 1.423 1.428 1.403 1.396 1.420 1.405 1.340 1.323 1.306 1.260 1.234 1.229 1.201 1.130 1.109 1.673 1.636 1.647 1.455 1.472 1.430 1.392 1.352 1.320 1.292 1.255 1.210 1.770 1.120 ELEVATION 100 m 0+180 0+185 0+190 0+195 TP2 0+200 0+205 0+210 0+215 0+220 0+225 0+230 0+235 0+240 0+245 0+250 0+255 0+260 0+265 TP3 0+270 0+275 0+280 0+285 0+290 0+295 0+300 0+305 0+310 0+315 0+320 0+325 0+330 0+335 0+340 0+345 0+350 0+355 0+360 0+365 1.660 1.977 O 1.030 0.913 1.085 1.050 1.017 1.030 1.630 1.648 1.638 1.554 1.389 1.285 1.216 1.161 1.478 1.086 1.039 0.968 0.922 0.913 1.913 1.871 1.814 1.758 1.668 1.545 1.444 1.412 1.353 1.354 1.335 1.328 1.297 1.273 1.241 1.156 1.155 1.101…
4. Complete the accompanying set of profile notes and perform the arithmetic check. Provide a sketch of this project's profile view. (You can use excel to sketch) Station BS (ft) HI (ft) IS (ft) FS (ft) BM1 0+00 1+00 2+00 3+00 3+35 4+00 TP1 5+00 5+20 5+30 6+00 BM2 4.58 4.87 2.59 3.79 4.82 4.98 5.05 7.30 4.60 4.78 4.85 4.89 11.21 10.58 Elevation (ft) 427.06
1"ll Asiacell|ASIACELL Y=(1:4,1)=b O نقطتان )2( Shows polygon with the followng :Find the area (x,y) * 1.8 1.6- 1.4- 1.2 1 0.8- 0.6- 0.4- 0.2- 0.5 1 1.5 2 2.5 3 3.5 4 4.5 5 x=[1,0,2,5,1); y=[0,1,2,1,0]; plot(x, y); area=polyarea (x ,y) x=[1,1,5,2,1]; y=[1,2,3,1,0]; plot(x, y); area=polyarea (x ,y) x=[1,0,2,5,1]: y=[0,1,2,1,0]:.plot(x, y),: area=polyarea (x y) öaslg älbä write a program to find to the variableT of the following * ?functions using mat lab
Find the interior angle B at point 2 inside the baseline of points 1,2 and 3. Please do not write any unit in your answer and round it to 4 decimal place (e.g. xxXX0x). Do not use "'as a decimal seperator. PN Y(m) X(m) 1 1512.482420.25 2 1550.79 2221.24 3 1570.24 2526.97
Some questions require you to use the last three digits of your matric card number as input values. For instance : Matric Card No. : A20EA0061 "061" would be your input values where "0" will be labelled as X, "6" as Y and "1" as Z respectively. When entering angles, use the following format : Example#1: 136° 40' 50" type as 136,40,50 Example#2: 34° 05' 09" type as 34,05,09 Q4. Observing angles in both faces will eliminate the effects due to the non-perpendicularity of the trunnion axis, thus eliminating what type of errors in the angle observations? (single word answer and use lower case only). Your answer Figure 1 bearing BA is (350+x)° (40+Y)' (20+z)" bearing BC is (242+x)° (28+Y)' (24+z)" в
Q3/ The following is an incomplete page of level book in which (?) indicates missing Entry line. Calculate all the missing entries and complete the page of level book. also give the usual arithmetical checks. Station A B C D E F G CHECK B.S. 3.22 2.405 2.14 I.S. F.S 3.78 1.535 1.515 Σ BS- Σ FS ? Σ BS- Σ FS= 3.46 1.175 0.98 ? ? Rise (+) ? ? ? ? ? ERISE- > FALL ? ERISE-FALL = Fall (-) ? ? ? RL 350 ? ? 350.63 ? ? ? L.RL-F. RL L.RL -F. RL= Remarks BM T.P.1 T.P.2 ?