Elementary Linear Algebra: Applications Version
12th Edition
ISBN: 9781119282365
Author: Howard Anton, Chris Rorres, Anton Kaul
Publisher: WILEY
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Evaluate the given expression with u = (2, −2, 3), v = (1, −3, 4), and w = (3, 6, −4).(a) ‖u + v‖
(b) ‖−2u + 2v‖
(c) ‖3u − 5v + w‖
Simplify.
21) V3(5 – V6)
23) 4V15(5+ V3-
In Exercises 3–4, use the order of operations to simplify each
expression.
8 - 3? ÷ 9
|-5| - [5 - (18 - 6)]?
3.
4. 4
(2 – 9)° + 32 ÷ 1 + 3
5. Simplify: 3 - [2(x – 2) – 5x].
Chapter 3 Solutions
Elementary Linear Algebra: Applications Version
Ch. 3.1 - In Exercises 12, find the components of the...Ch. 3.1 - In Exercises 12, find the components of the...Ch. 3.1 - In Exercises 34, find the components of the vector...Ch. 3.1 - In Exercises 34, find the components of the vector...Ch. 3.1 - a. Find the terminal point of the vector that is...Ch. 3.1 - Let u = (3, 1, 2), v = (4, 0, 8), and w = (6, 1,...Ch. 3.1 - Show that there do not exist scalars c1, c2, and...Ch. 3.2 - In Exercises 34, evaluate the given expression...Ch. 3.2 - Let v = (2, 3, 0, 6). Find all scalars k such that...Ch. 3.2 - Prob. 9E
Ch. 3.2 - Prob. 11ECh. 3.3 - Prob. 1ECh. 3.3 - In Exercises 36, find a point-normal form of the...Ch. 3.3 - In Exercises 36, find a point-normal form of the...Ch. 3.3 - In Exercises 710, determine whether the given...Ch. 3.3 - In Exercises 710, determine whether the given...Ch. 3.3 - In Exercises 1112, determine whether the given...Ch. 3.3 - In Exercises 1314, find projau. a. u = (1, 2), a =...Ch. 3.3 - In Exercises 1520, find the vector component of u...Ch. 3.3 - In Exercises 1520, find the vector component of u...
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- Identify the rule of algebra illustrated by the statement. a. x+9=9+x b. 5x32=5x32 c. 2+5x2y2=2y2+5x2y2arrow_forwardevaluate the given expression with u = (2,−2,3), v = (1,−3,4), and w = (3,6,−4). (a) ∥u+v∥arrow_forwardLet a=⟨−2,3,4⟩, b=⟨4,5,−2⟩, and c=⟨2,0,1⟩. Determine [(a×b)×c]−[a×(b×c)]. Hint: Try to simplify the expression first to make the calculations easier! Select one: a. ⟨20,−10,−16⟩ b. ⟨12,13,6⟩ c. ⟨24,−5,−18⟩ d. ⟨12,−18,−24⟩ e. ⟨10,−18,−25⟩arrow_forward
- evaluate the given expression with u = (2,−2,3), v = (1,−3,4), and w = (3,6,−4). (d) ∥3u−5v+w∥arrow_forward3. 4 7.) Simplify the expression: 4.8 + 2.2w -1.4w + 2.4arrow_forwardA.(negative infinity,-5.1)U(0,-12.2) B.(negative infinity,-1.6)U(0,1.9) C.(-1.6,0)U(1.9, positive infinity) D.(negative infinity, positive infinity)arrow_forward
- In Exercises 3-4, evaluate the given expression with u = (2,-2,3), v = (1, −3, 4), and w = = (3,6,-4). 3. a. ||u + v|| c. ||-2u + 2v|| b. ||u|| + ||v|| d. ||3u-5v + w||arrow_forward4.3.PS-14 Simplify the expression 8h + (-7.7d)– 18+5d - 3.7h. 8h + (- 7.7d)– 18+ 5d – 3.7h = (Simplify your answer. Use integers or decimals for any numbers in the expression.)arrow_forward
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