The data in Table 2.13 are a sample from a larger data set collected on people discharged from a selected Pennsylvania hospital as part of a retrospective chart review of antibiotic usage in hospitals [7]. The data are also given in Data Set HOSPITAL.DAT with documentation in HOSPITAL. DOC at www.cengagebrain.com. Each data set at www.cengagebrain.com is available in six formats: ASCII, MINITAB-readable format, Excel-readable format, SAS-readable format, SPSS-readable format, and Stata-readable format, and as a text file (R-readable format). Compute the mean and median for the duration of hospitalization for the 25 patients.

Question

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Answer 1

Textbook Question

Chapter 2, Problem 1P

The data in Table 2.13 are a sample from a larger data set collected on people discharged from a selected Pennsylvania hospital as part of a retrospective chart review of antibiotic usage in hospitals [7]. The data are also given in Data Set HOSPITAL.DAT with documentation in HOSPITAL. DOC at www.cengagebrain.com. Each data set at www.cengagebrain.com is available in six formats: ASCII, MINITAB-readable format, Excel-readable format, SAS-readable format, SPSS-readable format, and Stata-readable format, and as a text file (R-readable format).

Compute the mean and median for the duration of hospitalization for the 25 patients.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

Expert Solution & Answer

To determine

Find the mean for the duration of hospitalization for the 25 patients.

Find the median for the duration of hospitalization for the 25 patients.

Answer to Problem 1P

The mean for the duration of hospitalization for the 25 patients is 8.6 days.

The median for the duration of hospitalization for the 25 patients is 8 days.

Explanation of Solution

Calculation:

Mean and median:

Step by step procedure to obtain mean and median using MINITAB software is given as,

Choose Stat > Basic Statistics > Display Descriptive Statistics.
In Variables enter the column Dur_stay.
Choose option statistics, and select Mean, Median.
Click OK.

Output using MINITAB software is given below:

Fundamentals of Biostatistics, Chapter 2, Problem 1P

Hence, the mean for the duration of hospitalization for the 25 patients is 8.6 days, and the median is 8 days.

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Answer 2

Textbook Question

Chapter 2, Problem 1P

The data in Table 2.13 are a sample from a larger data set collected on people discharged from a selected Pennsylvania hospital as part of a retrospective chart review of antibiotic usage in hospitals [7]. The data are also given in Data Set HOSPITAL.DAT with documentation in HOSPITAL. DOC at www.cengagebrain.com. Each data set at www.cengagebrain.com is available in six formats: ASCII, MINITAB-readable format, Excel-readable format, SAS-readable format, SPSS-readable format, and Stata-readable format, and as a text file (R-readable format).

Compute the mean and median for the duration of hospitalization for the 25 patients.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

Expert Solution & Answer

To determine

Find the mean for the duration of hospitalization for the 25 patients.

Find the median for the duration of hospitalization for the 25 patients.

Answer to Problem 1P

The mean for the duration of hospitalization for the 25 patients is 8.6 days.

The median for the duration of hospitalization for the 25 patients is 8 days.

Explanation of Solution

Calculation:

Mean and median:

Step by step procedure to obtain mean and median using MINITAB software is given as,

Choose Stat > Basic Statistics > Display Descriptive Statistics.
In Variables enter the column Dur_stay.
Choose option statistics, and select Mean, Median.
Click OK.

Output using MINITAB software is given below:

Fundamentals of Biostatistics, Chapter 2, Problem 1P

Hence, the mean for the duration of hospitalization for the 25 patients is 8.6 days, and the median is 8 days.

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Answer 3

Textbook Question

Chapter 2, Problem 1P

The data in Table 2.13 are a sample from a larger data set collected on people discharged from a selected Pennsylvania hospital as part of a retrospective chart review of antibiotic usage in hospitals [7]. The data are also given in Data Set HOSPITAL.DAT with documentation in HOSPITAL. DOC at www.cengagebrain.com. Each data set at www.cengagebrain.com is available in six formats: ASCII, MINITAB-readable format, Excel-readable format, SAS-readable format, SPSS-readable format, and Stata-readable format, and as a text file (R-readable format).

Compute the mean and median for the duration of hospitalization for the 25 patients.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

Expert Solution & Answer

To determine

Find the mean for the duration of hospitalization for the 25 patients.

Find the median for the duration of hospitalization for the 25 patients.

Answer to Problem 1P

The mean for the duration of hospitalization for the 25 patients is 8.6 days.

The median for the duration of hospitalization for the 25 patients is 8 days.

Explanation of Solution

Calculation:

Mean and median:

Step by step procedure to obtain mean and median using MINITAB software is given as,

Choose Stat > Basic Statistics > Display Descriptive Statistics.
In Variables enter the column Dur_stay.
Choose option statistics, and select Mean, Median.
Click OK.

Output using MINITAB software is given below:

Fundamentals of Biostatistics, Chapter 2, Problem 1P

Hence, the mean for the duration of hospitalization for the 25 patients is 8.6 days, and the median is 8 days.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Textbook Question

Chapter 2, Problem 1P

The data in Table 2.13 are a sample from a larger data set collected on people discharged from a selected Pennsylvania hospital as part of a retrospective chart review of antibiotic usage in hospitals [7]. The data are also given in Data Set HOSPITAL.DAT with documentation in HOSPITAL. DOC at www.cengagebrain.com. Each data set at www.cengagebrain.com is available in six formats: ASCII, MINITAB-readable format, Excel-readable format, SAS-readable format, SPSS-readable format, and Stata-readable format, and as a text file (R-readable format).

Compute the mean and median for the duration of hospitalization for the 25 patients.

Definition Definition Measure of central tendency that is the average of a given data set. The mean value is evaluated as the quotient of the sum of all observations by the sample size. The mean, in contrast to a median, is affected by extreme values. Very large or very small values can distract the mean from the center of the data. Arithmetic mean: The most common type of mean is the arithmetic mean. It is evaluated using the formula: μ = 1 N ∑ i = 1 N x i Other types of means are the geometric mean, logarithmic mean, and harmonic mean. Geometric mean: The nth root of the product of n observations from a data set is defined as the geometric mean of the set: G = x 1 x 2 ... x n n Logarithmic mean: The difference of the natural logarithms of the two numbers, divided by the difference between the numbers is the logarithmic mean of the two numbers. The logarithmic mean is used particularly in heat transfer and mass transfer. ln x 2 − ln x 1 x 2 − x 1 Harmonic mean: The inverse of the arithmetic mean of the inverses of all the numbers in a data set is the harmonic mean of the data. 1 1 x 1 + 1 x 2 + ...

Expert Solution & Answer

To determine

Find the mean for the duration of hospitalization for the 25 patients.

Find the median for the duration of hospitalization for the 25 patients.

Answer to Problem 1P

The mean for the duration of hospitalization for the 25 patients is 8.6 days.

The median for the duration of hospitalization for the 25 patients is 8 days.

Explanation of Solution

Calculation:

Mean and median:

Step by step procedure to obtain mean and median using MINITAB software is given as,

Choose Stat > Basic Statistics > Display Descriptive Statistics.
In Variables enter the column Dur_stay.
Choose option statistics, and select Mean, Median.
Click OK.

Output using MINITAB software is given below:

Fundamentals of Biostatistics, Chapter 2, Problem 1P

Hence, the mean for the duration of hospitalization for the 25 patients is 8.6 days, and the median is 8 days.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution & Answer

To determine

Find the mean for the duration of hospitalization for the 25 patients.

Find the median for the duration of hospitalization for the 25 patients.

Answer to Problem 1P

The mean for the duration of hospitalization for the 25 patients is 8.6 days.

The median for the duration of hospitalization for the 25 patients is 8 days.

Explanation of Solution

Calculation:

Mean and median:

Step by step procedure to obtain mean and median using MINITAB software is given as,

Choose Stat > Basic Statistics > Display Descriptive Statistics.
In Variables enter the column Dur_stay.
Choose option statistics, and select Mean, Median.
Click OK.

Output using MINITAB software is given below:

Fundamentals of Biostatistics, Chapter 2, Problem 1P

Hence, the mean for the duration of hospitalization for the 25 patients is 8.6 days, and the median is 8 days.

Answer 8

Expert Solution & Answer

To determine

Find the mean for the duration of hospitalization for the 25 patients.

Find the median for the duration of hospitalization for the 25 patients.

Answer to Problem 1P

The mean for the duration of hospitalization for the 25 patients is 8.6 days.

The median for the duration of hospitalization for the 25 patients is 8 days.

Explanation of Solution

Calculation:

Mean and median:

Step by step procedure to obtain mean and median using MINITAB software is given as,

Choose Stat > Basic Statistics > Display Descriptive Statistics.
In Variables enter the column Dur_stay.
Choose option statistics, and select Mean, Median.
Click OK.

Output using MINITAB software is given below:

Fundamentals of Biostatistics, Chapter 2, Problem 1P

Hence, the mean for the duration of hospitalization for the 25 patients is 8.6 days, and the median is 8 days.

Answer 9

Expert Solution & Answer

Answer 10

Expert Solution & Answer

Answer 11

To determine

Find the mean for the duration of hospitalization for the 25 patients.

Find the median for the duration of hospitalization for the 25 patients.

Answer 12

Answer to Problem 1P

The mean for the duration of hospitalization for the 25 patients is 8.6 days.

The median for the duration of hospitalization for the 25 patients is 8 days.

Answer 13

Explanation of Solution

Calculation:

Mean and median:

Step by step procedure to obtain mean and median using MINITAB software is given as,

Choose Stat > Basic Statistics > Display Descriptive Statistics.
In Variables enter the column Dur_stay.
Choose option statistics, and select Mean, Median.
Click OK.

Output using MINITAB software is given below:

Fundamentals of Biostatistics, Chapter 2, Problem 1P

Hence, the mean for the duration of hospitalization for the 25 patients is 8.6 days, and the median is 8 days.

Answer 14

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Answer to Problem 1P

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