Concept explainers
Each group member should select one of the following items: a $50 basketball, an $80 jacket, or a $200 television. Fill in the first three columns of the first three rows of the chart below.
To fill: The first three columns of the first three rows of the given chart as
Original Price, p | Discount, r | 1 – r | Sale Price | Multiplier to convert back to p |
p | r | 1 – r |
When a basketball costs $50, a jacket costs $80 and a television costs $200. The department store gives discount of 20% on all sport goods, 25% on all cloths and 10% on all electronics.
Answer to Problem 1A
Solution:
The filled table is shown below,
Original Price, p | Discount, r | 1 – r | Sale Price | Multiplier to convert back to p |
$50 | 0.2 | 0.8 | ||
$80 | 0.25 | 0.75 | ||
$200 | 0.1 | 0.9 | ||
p | r | 1 – r |
Explanation of Solution
Given Information:
A basketball costs $50, a jacket costs $80 and a television costs $200. The department store gives discount of 20% on all sport goods, 25% on all cloths and 10% on all electronics.
Chart is given as:
Original Price, p | Discount, r | 1 – r | Sale Price | Multiplier to convert back to p |
p | r | 1 – r |
Each of the three members selects one of the items:
A $50 basketball, an $80 jacket or a $200 television.
Write the object’s original price in the first column.
Find the appropriate discount percentage.
Convert each percentage to decimal and fill in the second column assumed as r,
Fill the data obtained from the problem in the chart,
Original Price, p | Discount, r | 1 – r | Sale Price | Multiplier to convert back to p |
$50 | 0.2 | 0.8 | ||
$80 | 0.25 | 0.75 | ||
$200 | 0.1 | 0.9 | ||
p | r | 1 – r |
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Chapter 2 Solutions
Elementary and Intermediate Algebra: Concepts and Applications (7th Edition)
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