This is a part of a review I'm studying, NOT a graded assignment, please do not reject. Thank you!Am I doing this problem right? I would like someone to verify I'm doing this correctly, thank you!I understand that there are multiple questions here, but I've already answered some of them and most are very simple problems, I appreciate your understanding! Y(s)Find the transfer function, 7(s) = ( using Mason's rulea) The number of forward paths, Kb) The Single loop gainsc) Ad) Ake) T(s)1₂ 6R(S) 11 sti@K= 3(2) L₁ = ( 3X 5+1)X( 5+2 X (3) = = = 95L₂= (-5X Sta) (3) = -1552 = 4₂ⒸA=1 - (L₁+₂) = 1 + 35135+2 + 5+2|4₁=4₂=4₂=1155 -FⒸT= Y/₁₂ = P₁A₁¹RA₂-PA₂ = ((+35+2)+(547) + (6))AT(s) = tryingtoSimplify=5+2 31 Y(s)Ans.=4₁4=(5+2)(5² +35+2) +15(5+₂) +/55 (5² +35+2)(5+2) (5²+35+2)35P₁ = 5²+35+2P₁ = (34)(55)(3)P₁ = (st1X-4)=3/171₁=(6)(5+₂)(5² €38+2) + 95(5+2) + (55(5³²+35+2)(s+a)(s²+35+2)-= T(S)(5+2)(5²+35+2)(5+2)(5² +35+2)+15(5+2)+155 (5=+35+2)

From the given signal flow graph, the transfer function of the system needs to be calculated along…

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Introductory Circuit Analysis (13th Edition)

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Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

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This is a part of a review I'm studying, NOT a graded assignment, please do not reject. Thank you!

Am I doing this problem right? I would like someone to verify I'm doing this correctly, thank you!

I understand that there are multiple questions here, but I've already answered some of them and most are very simple problems, I appreciate your understanding!

Y(s)
Find the transfer function, 7(s) = ( using Mason's rule
a) The number of forward paths, K
b) The Single loop gains
c) A
d) Ak
e) T(s)
1₂ 6
R(S) 11 sti
@K= 3
(2) L₁ = ( 3X 5+1)X( 5+2 X (3) = = = 95
L₂= (-5X Sta) (3) = -1552 = 4₂
ⒸA=1 - (L₁+₂) = 1 + 35135+2 + 5+2
|
4₁=4₂=4₂=1
155 -F
ⒸT= Y/₁₂ = P₁A₁¹RA₂-PA₂ = ((+35+2)+(547) + (6))
A
T(s) = trying
to
Simplify
=
5+2 31 Y(s)
Ans.
=4₁
4=
(5+2)(5² +35+2) +15(5+₂) +/55 (5² +35+2)
(5+2) (5²+35+2)
35
P₁ = 5²+35+2
P₁ = (34)(55)(3)
P₁ = (st1X-4)=3/17
1₁=(6)
(5+₂)(5² €38+2) + 95(5+2) + (55(5³²+35+2)
(s+a)(s²+35+2)
-= T(S)
(5+2)(5²+35+2)
(5+2)(5² +35+2)+15(5+2)+155 (5=+35+2)

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