explain the solution Soln(a)(b)FBDTP (05(50)Wsin 30 k"fx=-MKN"W (930° + P sin/50²)- Normal forceN = W (930' + P 3in (80²) = 1/2 w² + p sin (50²)andPretma=насеm=7Wuy oPCs (50¹) - wsin (30²) - fx=g→ Peg (50²) - W_ _ 4₂ [2/w + P sin [10]} = aga+1 +(J3MK)P =g2(9 (50)- sin(50)100 x ( 23.01 + 1/2 + √3 x 0.30)05 (50)-0.305in (50)W= 100M730'of the blockya=2m 524x=030P =N233-35 NلیN

Name: explain the solution Soln(a)(b)FBDTP (05(50)Wsin 30 k"fx=-MKN"W (930°
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Description: explain the solution Soln(a)(b)FBDTP (05(50)Wsin 30 k"fx=-MKN"W (930° + P sin/50²)- Normal forceN = W (930' + P 3in (80²) = 1/2 w² + p sin (50²)andPretma=насеm=7Wuy oPCs (50¹) - wsin (30²) - fx=g→ Peg (50²) - W_ _ 4₂ [2/w + P sin [10]} = aga+1 +(J3MK

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ya=2m 52 4x=030 P (05(50) Wsin 30 k "fx-MKN wen 30° + P sin(50) - Normal force N = W (930' + P 3in (80¹) = 1/2 w² + p sin (50²) and Pret = ma насе m= 7 W PCs (50¹) - wsin (30²) - fx= uy o g → Peg (50²) - W_ _ 4₂ [2/w + P sin [jo]] = a g a +/+ (5₁ MK) P = g 2 (9 (50)- sin(50) 100 x ( 23.01 + 1/2 + √3 x 0.30) 05 (50)-0.305in (50) Soln (a) (b) T FBD W= 100M 730' of the block N P = 233-35 N لی N

ya=2m 52 4x=030 P (05(50) Wsin 30 k "fx-MKN wen 30° + P sin(50) - Normal force N = W (930' + P 3in (80¹) = 1/2 w² + p sin (50²) and Pret = ma насе m= 7 W PCs (50¹) - wsin (30²) - fx= uy o g → Peg (50²) - W_ _ 4₂ [2/w + P sin [jo]] = a g a +/+ (5₁ MK) P = g 2 (9 (50)- sin(50) 100 x ( 23.01 + 1/2 + √3 x 0.30) 05 (50)-0.305in (50) Soln (a) (b) T FBD W= 100M 730' of the block N P = 233-35 N لی N

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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