Write the vector expression for the acceleration a of the mass center G of the simple pendulum in both n-t and x-y coordinates for the instant when = 51° if 0 = 1.50 rad/sec and 0 = 3.680 rad/sec². Answers: a=( a = ( i i 2.6' en + i i+ i et) ft/sec² j) ft/sec²
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- + G In the above diagram, the wheel starts from rest and rolls without slipping. The force (you don't need the value) causes a constant angular acceleration of 7.112 rad/s2. The radius of the wheel is R - 0.392 m. What is the magnitude of the acceleration of the point at the top of the wheel at time t 1.400 s? This is the point at the outer edge directly above the center of gravity, Gwhere the force F connects to the wheel. Use units of m/s. Don't place units in your answer, 3 oFor my exam reviewer: (DYNAMICS) A flywheel has its angular speed increased uniformly from 18 rad/s to 75 rad/s in 80 s. If the diameter of the wheel is 3.5 ft, determine the magnitudes of the normal and tangential components of acceleration of a point on the rim of the wheel when t = 80s, the magnitude of the acceleration, and the total distance the point travels during the time period. Find: total distance (in ft) *Do show full solution. Thank you so much.A load is raised 11 ft by the gears and wheel system below. Gear A is initially rotating at rest and accelerates uniformly to omega = 24 rpm in t= 10 sec and maintain then maintain this constant 24 rpm speed. The dimensions are rA= 1 in, rB= 9 in and rC=16 in. 2) After 10 sec, find the distance s2 in feet and in NC es needed to reach the 11 ft, find thetaC2(t), alphaA2, alphaB2 in rad/s^2, omegaA2(t), omegaB2(t) in rad/s, thetaA2(t), in rad and the distance s2 in ft that should be made to get to the 11 ft raising distance of the load. 3) Deduce the number of revolutions made by gear A and how long it will take, to raise the load up to 11 ft.
- WORKSHEET: A racing car starts at rest at point A and increases its speed around the track at a constant rate of 6 ft/sec², traveling counterclockwise. Determine the position and the time at which the car's acceleration magnitude reaches 20 ft/sec². y ↑ 200 ft Used with permission from "Engineering Mechanics: Dynamics." McGill/King, 4th Ed, 2003Q1. Member AB is rotating (about fixed point A) with angular velocity (@ = 1 rad/sec) and angular acceleration (a = 2 rad/sec?) and driving the link CD (rotating about fixed point D at constant velocity) as shown in figure. Select five right answers. (a) Tangential Acceleration (a:) of link AB will not be zero (b) Tangential Acceleration (a) of link AB will be zero D 450mm (c) Tangential Acceleration (a,) of link CD will not be zero 200 mm 100 mm 60 H (d) Tangential Acceleration (a,) of link CD will be zero (e) All points on link CB will have same linear velocity 0 All points on link CB will have same angular velocity Formula • Tangential acceleration of a rotating link -ra • Radial (normal) acceleration of a rotating link = v³ /r= wr velocity of a rotating Ink (v) = r.w (g) Angular acceleration (a) for link CD will be zero (h) Angular acceleration (a) for link CB will not be zero Q2. Magnitude of linear velocity of any point “H" located at the half of the length of a rotating link CB…A wheel rotating with 17 rev/s is uniformly accelerated at 0.5 rad/s² for 5 seconds. It then rotates with a uniform speed for next 7 s. Then it is made to stop in next 15 s. Determine (i)maximum angular velocity; (ii) total angular displacement (Enter only the values in the boxes by referring the units given . Also upload the hand written copy in the link provided) Solution: The maximum velocty in rad/s is The total displacement in rad is
- The x-coordinate of a particle in curvilinear motion is given by x = 3.8t3 - 2.6t where x is in feet and t is in seconds. The y-component of acceleration in feet per second squared is given by ay = 3.9t. If the particle has y-components y = 0 and vy = 5.2 ft/sec whent = 0, find %3D %3D the magnitudes of the velocity v and acceleration a when t = 5.3 sec. Sketch the path for the first 5.3 seconds of motion, and show the velocity and acceleration vectors for t = 5.3 sec. Answers: V = i ft/sec a = ft/sec2The slider P can be moved inward by means of the string S as the bar OA rotates about the pivot 0. The angular position of the bar is given by 0 = 0.4 +0.12t+ 0.06t³, where 0 is in radians and t is in seconds. The position of the slider is given by r = 0.8 0.1t 0.05t2, where r is in meters and t is in seconds. Determine and sketch the velocity and acceleration of the slider at time t = 2 s. Find the angles a and ß which v and a make with the posi- tive x-axis. S 0 Problem 2/144 رفع جكx Incorrect. In the overhead view of the figure, five forces pull on a box of mass m = 3.3 kg. The force magnitudes are F = 11 N, F, = 19 N, F3 = 2.8 N, F4 = 15 N, and Fs = 4.3 N, and angle 04 is 34°. Find the (a) x-component and (b) y-component of the box's acceleration, and also give the acceleration as (c) a magnitude and (d) an angle relative to the positive direction of the x axis. (Note that the angle will be negative if it is below the horizontal.) (a) Number T2.9 Units (b) Number T-53.9 Units (c) Number UnitsT Units e to search 7:01 PM 会 ENG 4/4/2021 17 pgdn pause break prt sc insert delete %23 %, 4 9. backspace E R | ১২ 3.
- The dimensions of the various links of a mechanism, as shown in Fig. 3, are as follows: OA = 0.3 m: AB = 1 m: CD = 0.8 m; and AC = CB. If the crank OA rotates at 100 rpm. in the anticlockwise direction, find, for the given configuration: 1. velocity and acceleration of B and D: 2. angular acceleration of the links AB and CD. 45 0.6 m- Eig 3You want to move a heavy box with mass 30.0 kg across a carpeted floor. You pull hard on one of the edges of the box at an angle 30∘ above the horizontal with a force of magnitude 240 N, causing the box to move horizontally. The force of friction between the moving box and the floor has magnitude 41.5 N . Find both the x and y components of the acceleration of the box.? What is the box's acceleration just after it begins to move?4. 2) The hydraulic cylinder D extends, moves the rigid rod ABC, and causes the collar A to move with velocity and acceleration both to the left. If the dimensions 4 1.0 ft, and 2 = 1.7 ft, VA = 4.9 ft/s, aa = 2.6 ft/s2, and the angle 0 = 27°, determine the speed of point B. Please pay attention: the numbers may change since they are randomized. Your answer must include 2 places after the decimal point, and proper unit. В 12 D a Your Answer: Answer units 1,