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who use their own cups when they purchase a coffee beverage, and the proportion of customers who use their own cups when they purchase an espresso beverage. Customers using their own cups get a 5% discount, which is displayed on the receipt. The owner randomly selects 50 receipts from all coffee purchases and 50 receipts from all espresso purchases. For coffee purchases, 24 receipts showed that the customer used their own cup. For espresso purchases, 18 receipts showed that the customer used their own cup. Assuming the conditions for inference have been met, what is the 99% confidence interval for the difference in proportion of customers who use their own cups? Find the z-table here. O (0.48 - 0.36) ±2.58 0.48(1– 0.48) , 0.36(1-0.36) 50 50 O (0.48 - 0.36)±2.33, 0.48(1–0.48) 50 0.36(1-0.36) 50 O (0.52 - 0.64) ±2.58 0.52(1-0.52), 0.64(1–0.64) 100 100 0.52(1-0.52), 0.64(1–0.64) 100 (0.52 - 0.64) ±2.33, 100

who use their own cups when they purchase a coffee beverage, and the proportion of customers who use their own cups when they purchase an espresso beverage. Customers using their own cups get a 5% discount, which is displayed on the receipt. The owner randomly selects 50 receipts from all coffee purchases and 50 receipts from all espresso purchases. For coffee purchases, 24 receipts showed that the customer used their own cup. For espresso purchases, 18 receipts showed that the customer used their own cup. Assuming the conditions for inference have been met, what is the 99% confidence interval for the difference in proportion of customers who use their own cups? Find the z-table here. O (0.48 - 0.36) ±2.58 0.48(1– 0.48) , 0.36(1-0.36) 50 50 O (0.48 - 0.36)±2.33, 0.48(1–0.48) 50 0.36(1-0.36) 50 O (0.52 - 0.64) ±2.58 0.52(1-0.52), 0.64(1–0.64) 100 100 0.52(1-0.52), 0.64(1–0.64) 100 (0.52 - 0.64) ±2.33, 100

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.6: Summarizing Categorical Data
Problem 11CYU
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The owner of a popular coffee shop wants to determine if there is a difference between the proportion of customers who use their own cups when they purchase a coffee beverage, and the proportion of customers who use their own cups when they purchase an espresso beverage. Customers using their own cups get a 5% discount, which is displayed on the receipt. The owner randomly selects 50 receipts from all coffee purchases and 50 receipts from all espresso purchases. For coffee purchases, 24 receipts showed that the customer used their own cup. For espresso purchases, 18 receipts showed that the customer used their own cup. Assuming the conditions for inference have been met, what is the 99% confidence interval for the difference in proportion of customers who use their own cups? Find the z-table here. O (0.48 - 0.36) ±2.58/ 0.48(1–0.48) , 0.36(1–0.36) 50 50 0.48(1-0.48) 0.36(1-0.36) (0.48 - 0.36) ±2.33/ 50 50 O (0.52 - 0.64)±2.58 0.52(1-0.52) 0.64(1-0.64) + 100 100 0.52(1-0.52) , 0.64(1-0.64) (0.52 - 0.64) ±2.33, 100 100
Transcribed Image Text:The owner of a popular coffee shop wants to determine if there is a difference between the proportion of customers who use their own cups when they purchase a coffee beverage, and the proportion of customers who use their own cups when they purchase an espresso beverage. Customers using their own cups get a 5% discount, which is displayed on the receipt. The owner randomly selects 50 receipts from all coffee purchases and 50 receipts from all espresso purchases. For coffee purchases, 24 receipts showed that the customer used their own cup. For espresso purchases, 18 receipts showed that the customer used their own cup. Assuming the conditions for inference have been met, what is the 99% confidence interval for the difference in proportion of customers who use their own cups? Find the z-table here. O (0.48 - 0.36) ±2.58/ 0.48(1–0.48) , 0.36(1–0.36) 50 50 0.48(1-0.48) 0.36(1-0.36) (0.48 - 0.36) ±2.33/ 50 50 O (0.52 - 0.64)±2.58 0.52(1-0.52) 0.64(1-0.64) + 100 100 0.52(1-0.52) , 0.64(1-0.64) (0.52 - 0.64) ±2.33, 100 100
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