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- Calculate the FeSCN ^+2. Presume that all of the SCB ions react. Record these values in the table below.enow.com/ilrn/takeAssignment/takeCovalentActivity.do?locator%3Dassignment-take nd 10 ☆ 可R [References] Magnesium metal is very malleable, and is able to be pounded and stretched into long, thin, narrow "ribbons" that are often used in the introductory chemistry lab as a source of the metal. If a strip of magnesium ribbon is ignited in a Bunsen burner flame, the magnesium burns brightly and produces a quantity of white magnesium oxide powder. 1S From the information given above, indicate one chemical property of magnesium metal. O Magnesium is able to be pounded and stretched into long, thin, narrow "ribbons". O Magnesium is malleable. O Magnesium burns in air. O Magnesium "ribbons" are often used in the introductory chemistry lab as a source of the metal. Submit Answer Try Another Version 1 item attempt remaining Previous Next Save and Exit Cengage Learning | Cengage Technical Support 2:17 PM 1/26/2021 DELLWhat is the purpose of the WO3 and Cu
- Explain why Ei3 for Ca is considerably greater than either Ei1 orEi2.iles Tab Window Help OWL X CICh x takeCovalentActivity.do?locator-assignment-take Submit Answer 2 Quiz 5.pdf 80 F3 94 Q 12 F4 [Review Topics] [References] Use the References to access important values if needed for this question. Potassium hydrogen phthalate is a solid, monoprotic acid frequently used in the laboratory to standardize strong base solutions. It has the unwieldy formula of KHC, H4O4. This is often written in shorthand notation as KHP. How many grams of KHP are needed to exactly neutralize 29.0 mL of a 0.402 M calcium hydroxide solution? grams KHC, H404 Mass= Retry Entire Group Math 122 Quiz 5.docx % 5 Para X tv i. 9 F5 & A ve X Wea Show All F12 XСНО CO,H CO2ET
- 29. asaaappp plsssBriefly explain why the FeCl3 bonds to the Cl and not the I. This can be done either by considering the reactant side of the equation or the product side of the equation.Nernst equation for pair CIO4|Cr': RT E = E° + nF In «(CIO, )a*(H*) a(Cl¯) RT E = E° + nF Cloa(CIO; )a(H*) a(Cl¯) RT a(CIO, Ja*(H*) E = E° – -In nF a(Cl¯) nF a(CIO, )a*(H*) E = E° + lg RT a(Cl¯)