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- A precipitate of Fe(OH)3 is contaminated with Mg(OH)2. The best way to get rid of the impurity is by: Select one: O a. Washing O b. Digestion O c. Ignition O d. Reprecipitation D.Reprecipitation O e. Mixed cystall formationWhich of the following salts gives the following Ksp expression? Ksp = 108s5 a. Sn(OH)4B. Cu2C2O4c. Cu3PO4d. Al2(CO3)3Tiame tests, the yello w colour oT sodium lons can mask the coIour of otner lons. Explain why blue glass is used to ldentity ions in the presence of sodium. Saved Normal B|I|U fx | | D E li Delete column
- Give the expression for the solubility product constant for Ca3(PO4)2- Select one: O a. B Ca2+PR PO43-P Ca3(PO4)2 O b. [ Ca2+P[ PO43-P Ca3(PO4)2 O c. R Ca2+P[3 PO43-3 Ca3(PO4)2 O d. [ Ca2+j?[ PO43-73 O e. [Ca2+j³[PO43-12th acedic scuticns Balance the fallowng redex reacti ans rusine cxidatian ununbers. Explain process. Helle 34 b) Fe4, 24 (aq) c) Uo 24 34 2-What is the Kf expression for the following complexation reaction? Al3* (ag) + 6F (aq) [AIFP (aq) Select one: | AIF ° A1 А. | AP* ]| F |* | AIF3- | 6 KĘ = В. | AIF,3- | K = | AI* ]| F]° K = | AIF3- |6 D.
- W JLZFw751LyNbHc3lINf3gth356g/iewformledit_requested%-true alpha hydrogen aboratory X O beta hydrogen sigma hydrogen 42. Phenol reacts with ferric ions to form violet coloured complex red coloured complex yellow coluored complex 43. Propan-2-ol + lodine + NAOH----- No formation of CHI3-coloriless solution Formation of CHI3-fine yellow precipitate No formation of CHI3-black brownish solution 44. are substances that produce hydroxylions (OH- lons) when dissolved in water." Acids Bases Alcohols34. Which of the following statements is/are TRUE considering the reaction below? CdCO3 = Cd2+ + CO,2- 1. Dissolving CdCO3 in a 0.001 M HCI solution will decrease its solubility II. Dissolving CDCO3 in a 0.001 M Cd(NO3), solution will decrease its solubility. O l only. O Il only. O Both I and II.Balance the following equations
- Which would precipitate first upon addition of the sodium salts of the following anions to solutions 0.10 M in Pb(NO3)2?ion Ksp of lead saltA. IO3- 3.2 x 10-13B. Cl- 1.6 x 10-5C. Br- 4.0 x 10-5D. C2H3O2- 1.8 x 10-3E. OH- 1.2 x 10-15 The answer is Eteaching and le X n/takeAssignment/takeCovalentActivity.do?locator-assignment-take L irch 5 + Free Online Survey... Home - Academia... Submit Answer 6 The reaction of hypochlorite ion with iodide ion in 1 M aqueous hydroxide solution OCI+I→ OI+ CIT & [Review Topics] [References] Use the References to access important values if needed for this question. is first order in OCI and first order in I™. Complete the rate law for this reaction in the box below. Use the form k[A] [B]", where '1' is understood for m, n ... (don't enter 1) and concentrations taken to the zero power do not appear. Rate = Retry Entire Group Modules Create Your Rubric-... In an experiment to determine the rate law, the rate constant was determined to be 8.58 x 10¹ M¹s¹. Using this value for the rate constant, the rate of the reaction when [OCI] = 6.80 x 10-³ M and [I] = 5.49 × 10-³ M would be M/s. 7 + 1 more group attempt remaining 8 The Utility Experts ... ◄◄ 9 ▶11 ☆ ►► f12 » All B insert I ← 6:45 PM 12/14/2023 prt…The given data is based on the following chemical reaction: 31 (ag) + H2O2(ga) + 2H3O*(gg) –→I; (@@) + 4H¿O(I) HI HO. H2O Buffer Rate Trial-1 0.03M 0.0001M 10mL 0.1M 0.2035M/s Trial-2 0.06M 0.0001M 10mL 0.1M 0.4072M/s Trial-3 0.03M 0.0002M 10mL 0.1M 0.2041M/s Trial-4 0.06M 0.0001M 10mL 0.2M 1.6290M/s Trial-5 0.03M 0.0001M 20mL 0.1M 0.2030M/s Trial-6 0.015M 0.0001M 10mL 0.1M 0.1018M/s Question-1: What is the rate order with respect to the iodine? Question-2: What is the rate order with respect to the hydrogen peroxide? Question-3: What is the rate order with respect to the buffer? Note: The buffer consists of acetic acid (CH3O,H) and sodium acetate (NaCH3O2). However just calculate with the concentrations given.