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- Given two vectors: M = -31 + 6j – 5k and N = -21 + 3) +k The cross product of MxN equals Choose the best answer. A -9i -7j +3k B) 21i +13j +3k 9i +7j -3k D) 13 E No AnswerGiven: Force P = (-24 i +18 j + 18 k) kN acting at C(3, -7, 2) m. a) Determine the moment of the force P about the origin.b) Determine the moment of the force P about point E (-4,8,4)m and the magnitude of the moment.c) Determine the moment of the force P about axis AB where A(3, 2, 5)m and B(-4, -3,8)m and express the result in vector form.In the shown figure, the length of the side of the square is 2a , if q,=Q is placed at point "5", the E at the center of the square is given by 1 2 3 y 8 L. 7 Select one: O a. E= Q/ (8 /2 TIE ,a²)(i–j) O b. E = Q/ (4 Tte,a²)(-i+j) O c. E= Q/ (4 V/2 TEoa?)(i-j) O d. E= Q/(8 /2 TE ,a²)(-i+j) O e. E= Q/ (4 /2 TEga?)(-i+j)
- A 50-N force is directed along the line drawn from the point whose x, y, z coordinates arc (8.2.3) m to the point whose coordinates are (2, -6, 5) m. What is the scalar moments of the force about the y-axis? a. +167 N b.-167 N c. +137 N d.-137 NThe 29-1b rectangular plate is at rest on a smooth horizontal floor. It is given the horizontal impulses as shown in (Figure 1). Assume I = 20 lb. s. Figure 0.5 ft 5 lb.s 60% 2 ft -0.5 ft-- Part A Determine its angular velocity. Express your answer in radians per second to three significant figures. IVE ΑΣΦΑ ↓↑ vec w = 37.747 Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part B Submit ***** Determine the magnitude of the velocity of the mass center. Express your answer in feet per second to three significant figures. VG = 22.2 ft/s Previous Answers ? rad/sGiven two vectors: M = -3î + 6j – 5k and N = -21 + 3j +k The cross product of MxN equals Choose the best answer. (A) -9i -7j +3k B) 21i +13j +3k c) 9i +7j -3k (D) 13 No Answer
- Consider the two vectors A= 12i + 5j and B = -3i. What is the cross product Ax B? O51 k none of the answers -15k O 15 j 15 k O.51 k -21 O 21 k -512/27 The 4-kN force F is applied at point A. Compute the moment of F about point O, expressing it both as a scalar and as a vector quantity. Determine the dinates of the points on thex- and y-axes about which the moment of F is zero. coor- = 2.68k kN m (x, y) = (-1.3, 0) and (0, 0.78) m Ans. Mo = 2.68 kN m CCW, Mo %3D %3D %3D у, т A (1.2, 1.5) F = 4 kN -x, m Problem 2/27A water molecule consists of an oxygen atomwith two hydrogen atoms bound to it. Theangle between the two bonds is 106◦. If each bond is 0.093 nm long, how far fromthe oxygen atom is the center of mass of themolecule? Take the mass of an oxygen atomto be 16 times the mass of a hydrogen atom.Answer in units of nm
- Question 4) As shown in the figure, three spheres of mA = 1kg, mB = 2kg and mC = 4kg slide towards point O in a frictionless environment. The velocities of spheres A and B are shown in the figure. These three spheres arrive at point O at the same time. If these three spheres move together at a speed of 1m / s in the + x direction after the collision; a) What should be the magnitude of the initial velocity of mass C? b) What angle should the mass C make with the x-axis? c) If the velocity of the mass C is as in a), what will be the change in the kinetic energy of the system consisting of these three spheres as a result of the collision?A ball weighing 800 grams and having a radius of 2cm moves in the direction of the positive x-axis at a speed of 5m/s. It collides with another stationary ball weighing 500 grams and also having a radius of 2cm. The collision occurs off-center, with the vertical components of the centers of the balls differing by 1cm. Following the collision, the lighter ball attains a speed of 3m/s. Determine the velocity of the heavier ball after the collision and calculate the amount of energy lost during the collision.The line of action of the 5300-lb force runs through the points A and B as shown in the figure. Determine the x and y scalar components of F. y, m B (12,9) z F = 5300 lb -x, m A (-10, -3) lb lb Answers: i i
