When a certain perfect gas is heated at constant pressure from 15 °C to 95 °C, the heat required is 1136 kJ/kg. When the same gas is heated at constant volume between the same temperatures the heat required is 808 kJ/kg. Determine Cp, Cv, gamma, R, and the molar mass of the gas.
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- One process for decaffeinating coffee uses carbon dioxide ( M=44.0 g/mol) at a molar density of about 14,0 mol/m3 and a temperature of about 60 . (a) Is CO2 a solid, liquid, gas, or supercritical fluid under those conditions? (b) The van der Waals constants for carbon dioxide are a=0.3658 Pa m6/mol2 and b=4.286105 m3/mol. Using the van der Waals equation, estimate pressure of CO2 at that temperature and density. `One of a dilute diatomic gas occupying a volume of 10.00 L expands against a constant pressure of 2.000 atm when it is slowly heated. If the temperature of the gas rises by 10.00 K and 400.0 J of heat are added in the process, what is its final volume?A sealed 19 m3 tank is filled with 7,011 moles of ideal oxygen gas (diatomic) at an initial temperature of 292 K The gas is heated to a final temperature of 490 K. The atomic mass of oxygen is 16.0 g/mol. The final pressure of the gas, in MPa, is closest to: answer round to 4 sig.fig
- What is the volume of a container that holds exactly 1 mole of anideal gas at standard temperature and pressure (STP), defined asT = 0°C = 273.15 K and p = 1 atm = 1.013 * 105 Pa?Two containers of equal volume each hold samples of the same ideal gas. Container A has 2 times as many molecules as container B. If the gas pressure is the same in the two containers, find the ratio of the the absolute temperatures TA and TB ( i.e TA / TB ) . Calculate to 2 decimals.A mole of gas has isobaric expansion coefficient dV/dT = R/p and isochoric pressure-temperature coefficient dp/dT = p/T . Find the equation of state of the gas.
- The volume V of an ideal gas varies directly with the temperature T and inversely with the pressure P. If a cylinder of 50 liters contains oxygen at a temperature of 200 K and a pressure of 5 atmospheres, what would the gas pressure be if the volume was changed to 30 liters and the temperature raised to 240 K?Problem 1: Consider the two-sided chamber shown,where the right half has a volume of V = 590 L and the left half has a volume of 2V. The chamber has a seal which separates the right from the left half. The chamber is sealed and an ideal gas is pumped into the right side at a pressure P= 6.4 atm and temperature T= 78° C. The seal between the two sides is then opened. 2V V Part (a) If the physical temperature decreases by a factor of 2 while the gas fills the chamber, what is the new pressure, in kilopascals? P'= sin() cos() tan() 7 8 HOME cotan() asin() acos() 5 atan() acotan() sinh() 1 2 3 cosh() tanh() cotanh() + END ODegrees O Radians Vol BACKSPACE CLEAR Submit I give up! Hint Feedback Part (b) The chamber is then sealed again, trapping 2/3 of the gas molecules in the left side. The temperature of the left side is then doubled, back to the original temperature T. What is the pressure in the left side of the chamber now, in kilopascals?A tank of compressed air of volume 1.00 m³ is pressurized to 27.6 atm at T = 273 K. A valve is opened, and air is released until the pressure in the tank is 14.3 atm. How many molecules were released? Boltzmann constant is 1.38 x 10-23 J/K. molecules
- A gas bottle contains 4.15×1023 Nitrogen molecules at a temperature of 354.0 K. What is the thermal energy of the gas? (You might need to know Boltzmann's constant: kg = 1.38x10-23 J/K.) 3041 J Submit Answer Incorrect. Tries 1/20 Previous Tries How much energy is stored in ONE degree of freedom for the whole system? 1.01x103 J are correct. Your receipt no. is 159-4121 O Previous Tries What is the average energy of a single molecule? 7.33x10^-21 J Submit Answer Incorrect. Tries 1/20 Previous Tries On average how much energy is stored by ONE degree of freedom for ONE single molecule? 2.44x10-21 j are correct. Your receipt no. is 159-1592 0 Previous TriesThe Ideal Gas Law is given by the equation: PV — пRT Where: P = pressure V = volume n = moles T = temperature in Kelvin In order to solve for the moles, n, you must multiply both sides of the equation by the same expression: PV × = nRT × The resulting equation is: n =α = alpha A possible equation of state for a gas takes the formPV = RT * exp (-α / VRT)in which α and R are constants. Calculate expressions for(∂P/∂V)T, (∂V/∂T)P, (∂T/∂P)V,and show that their product is −1.