When 13.8 ml of 0.870 M lead(II) nitrate reacts with 90.0 ml of 0.777 M sodium chloride, 0.579 kJ of heat is released at constant pressure. What is AH° for this reaction? Pb(NO3)2(aq) + 2NaCI(aq) → PbCl2( s) + 2NANO3(aq) a. 48.3 kJ b. 57.6 kJ С. 39.9 kJ d. 31.6 kJ е. 23.3 kJ

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Chapter6: Thermochemisty
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Problem 6.105QP: A piece of lead of mass 121.6 g was heated by an electrical coil. From the resistance of the coil,...
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When 13.8 mL of 0.870 M lead(Il)
nitrate reacts with 90.0 ml of
0.777 M sodium chloride, 0.579 kJ of
heat is released at constant
pressure. What is AH° for this
reaction?
Pb(NO3)2(aq) + 2NaCI(aq) → PbCl2(
s) + 2NANO3(aq)
a. 48.3 kJ
b. 57.6 kJ
c. 39.9 kJ
d. 31.6 kJ
e. 23.3 kJ
Transcribed Image Text:When 13.8 mL of 0.870 M lead(Il) nitrate reacts with 90.0 ml of 0.777 M sodium chloride, 0.579 kJ of heat is released at constant pressure. What is AH° for this reaction? Pb(NO3)2(aq) + 2NaCI(aq) → PbCl2( s) + 2NANO3(aq) a. 48.3 kJ b. 57.6 kJ c. 39.9 kJ d. 31.6 kJ e. 23.3 kJ
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