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- A cannon has an initial hight of 10 meters. The cannon ball has a weight of 15kg. There is no air resistance. If the cannon is fired with an initial angle of 0 degrees and an initial speed of 5 meters/second, what is the range? (the answer is 7.1 but I don't know how that value was found)Use three decimal places on answers Problem 2: A projectile is fired from the edge of a 150-m cliff with an initial velocity of 180 m/s, at an angle of 30° with the horizontal. Neglecting air resistance, find the following: a. Horizontal distance from the gun to the point where the projectile strikes the ground. b. Greatest elevation above the ground reached by the projectile.A basketball hoop is 2.90m above the ground. Lee is 1.96m tall, and the maximum vertical distance between the tip of his hands and the bottom of his feet iS 2.81m. To dunk a basketball, the tip of his hands must be at 0.190m above the basketball hoop or more. What minimum vertical distance in m must Lee jump so that he dunks a basketball? If Lee jumped the vertical distance from the first part, with what vertical speed must he jump in m/s? If Lee jumped the vertical distance from the first part, how long would it take for him to reach that vertical distance in s?
- A mortar rifle, with a maximum range of 40 m on flat ground, is placed on the edge of a 20 m high vertical cliff overlooking the horizontal plain. Specify the distance horizontal R of mortar gun as a function of a (mortar elevation angle above horizontal)!A projectile is fired from point A with an initial velocity . (a) Show that the radius of curvature of the trajectory of the projectile reaches its minimum value at the highest point B of the trajectory. (b) Denoting by the angle formed by the trajectory and the horizontal at a given point C, determine the radius of curvature of the trajectory at C as a function of pmin and θ.A marksman fires a practice round from A toward a target B. If the target diameter is 190 mm and the target center is at the same altitude as the end of the rifle barrel, determine the range of "shallow” launch angles for which the round will strike the target. Neglect aerodynamic drag and assume that the round is directed along the vertical centerline of the target. (Note: The word "shallow" indicates a low-flying trajectory for the round.) Answers: A 900 m/s 0.4575 Ꮎ 1320 m °≤0≤ 0.4576 B O
- What do vectors and scalars have in common? How do they differ?Let the vector v have an initial point at (-5, 5) and a terminal point at (-1,2). Plot the vector V and afterwards follow the guided steps to analyze the vector. That's right! Now answer the three questions below. y 6 8 -10 -9 -8 -7 Component Form: V = Magnitude of v: ||v||= Direction of v: 0₂ = -6 -5 -4 -3 -2 -1 10 9 8 7 6 5 4 3 N CO 2 1 -1 -2 -3 co -4 -5 -6 -8 -9 -10 1 9 10 √(radical form) O (nearest degree) Submit Answer 2 3 4 5 ·X 7Children playing in a playground on the flat roof of a city school lose their ball to the parking lot below. One of the teachers kicks the ball back up to the children as shown in the figure below. The playground is 5.60 m above the parking lot, and the school building's vertical wall is h = 6.70 m high, forming a 1.10 m high railing around the playground. The ball is launched at an angle of θ = 53.0°above the horizontal at a point d = 24.0 m from the base of the building wall. The ball takes 2.20 s to reach a point vertically above the wall. Find the speed (in m/s) at which the ball was launched. Answer= 18.12698336m/s Find the vertical distance (in m) by which the ball clears the wall. =1.40887572 Find the horizontal distance (in m) from the wall to the point on the roof where the ball lands. Answer ? What If? If the teacher always launches the ball with the speed found in part (a), what is the minimum angle (in degrees above the horizontal) at which he can launch the ball and…