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What will be the units for the permeaability constant μ0: (tesla, newton/ampere2, weber/meter, kilogram·ampere/meter, tesla·meter/ampere)
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- Part (b): Watts, volts, and ohms are SI units that can be expressed in the 'base' SI units as follows: kg-m² 53 ohm = kg-m² $³.A21 watt = volt= bottle cm kg.m² $3.A' (Recall that 'A' is the abbreviation for an ampere.) Use algebra and the equation at the top of the page (P=V²/R) to show that the base SI units for watts equal the base SI units for volts²/ohms. You do not need any numbers in this algebraic exercise. Instead, treat each of the base SI units (kg, m, s, A) as if it were an algebra variable (like x or y). Start with the following equation and substitute the base SI units for watt, volt, and ohm: watt = volt² ohmmobile battery during a charge cycle are shown in 1.26 The voltage and current at the terminals of an auto- Fig. P1.26. a) Calculate the total charge transferred to the battery. b) Calculate the total energy transferred to the battery. Figure P1.26 v (V) bnohostib 24 Loiwollol sd lo 16 8- 8. 12 16 20 t (ks) i (A) maxi 24 16 8- the che 4 8. 12 16 20 t (ks)During an experiment to verify Ohm's law, the current and resistance of a circuit are measured. [Resistance is measured in Ohm (2) and current in Ampere (A)]. www R +. Battery The measured value of the current is I = 2.3±0.2 A and that of the resistance is R = 10±0.3 0. The voltage applied (in Volts) can be calculated using the formula, V = IR. Calculate the, a) Voltage applied in the circuit (in Volts) = %3! b) Fractional uncertainty in the voltage = c) Absolute uncertainty (in Volts) in the voltage %3!
- The voltage V (volts), current I (amperes), andresistance R (ohms) of an electric circuitare related by the equation V = IR. Suppose that V is increasing atthe rate of 1 volt/sec while I is decreasing at the rate of 1/3 amp/sec. Let t denote time in seconds. What equation relates dR/dt to dV/dt and dI/dt?In the last column in the data table, it says that it's about voltage(v) divided by current(A) is equal to ohms so V/A = ohms. So if it's V/A and if you divide them to get the slope it's (y2-y1)/(x2-x1) then shouldn't V be the y value and A be the x value? And can you also try to use a line of best bit instead of drawing the line through each dot?The voltage V (volts), current I (amperes), andresistance R (ohms) of an electric circuitare related by the equation V = IR. Suppose that V is increasing atthe rate of 1 volt/sec while I is decreasing at the rate of 1/3 amp/sec. Let t denote time in seconds. What is the value of dV/dt?
- Ohm's law for electrical circuits like the one shown in the figure states that V = RI. In this equation, V is a constant voltage, I is the current in amperes, and Ris the resistance in ohms. Your firm has been asked to supply the resistors for a circuit in which V will be 240 volts and I is to be 20±0.2 amp. In what interval does R have to lie for I to be within 0.2 amp of the value I, = 20? R. To what interval must R be held to meet the requirements for the resistance? ohmsThe prefix “mega” (M) and “kilo” (k), when referring to amounts of computer data, refer to factors of 1024 or 210 rather than 1000 for the prefix kilo, and 10242 = 220 rather than 1,000,000 for the prefix Mega (M). If a wireless (WiFi) router transfers 150 Mbps of data, how many bits per second is that in decimal arithmetic?In the United States, normal household voltage is 115 volts. However, it is not uncommon for actual voltage to differ from normal voltage by at most 5 volts. Express this situation as an inequality involving an absolute value. Use x as the actual voltage and solve for x.
- QUESTION 8 Find the uncertainty in a calculated electrical potential difference from the measurements of current and resistance. Electric potential difference depends on current and resistance according to this function V(I,R) = IR. Your measured current and resistance have the following values and uncertainties I = 2.4 Amps, 81 = 0.2 Amps and R = 29.5 Ohms and SR = 0.6 Ohms. What is the uncertainty in %3! %3D the , SV ? Units are not needed in your answer.An electron is fired at a speed v = 3.1 x 10° m/s and at an angle 0, = 36.8° between two parallel conducting plates as shown in the figure. If s 1.8 mm and the voltage difference between the plates is AV = 98.8 V, determine how close, w, the electron will get to the bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the coordinate system is in the middle of the parallel plate capacitor. !!Ohm's law states V = IR. Find I and error if V = 80(+/-)5 and R = 20(+/-)4