What is the sampling distribution of x when μ = 0? Normal with mean 1.1 and standard deviation 3.3333. Normal with mean 0 and standard deviation 60. Normal with mean 0 and standard deviation 14.1421. Normal with mean 17 and standard deviation 0.1852. Do a Normal probability calculation to find the P-value. (Recall that the alternative hypothesis is two-sided.) Use Table A. Select the P-value obtained by your calculation. 0.7794 0.1151 0.2302 0.3849

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter1: Functions
Section1.CR: Chapter 1 Review
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Macmillan Learning
Does the job satisfaction of assembly workers differ when their work is machine-paced rather than self-paced? Workers are
assigned either to an assembly line moving at a fixed pace or to a self-paced setting. All subjects work in both settings, in
random order. This is a matched pairs design. After two weeks in each work setting, the workers take a test of job satisfaction.
The response variable is the difference in satisfaction scores, self-paced minus machine-paced.
The parameter of interest is the mean μ of the differences in scores in the population of all assembly workers. The study of job
satisfaction requires that we test
Ho:μ = 0
Ha: 0
Suppose we know that differences in job satisfaction scores (self-paced minus machine-paced) in the population of all workers
follow a Normal distribution with standard deviation o = 60.
Data from 18 workers give x = 17. That is, these workers prefer the self-paced environment on the average. Because the
alternative is two-sided, the P-value is the probability of getting an x at least as far from μ = 0 in either direction as the
observed x = 17.
The figure shows the output of the P-Value of a Test of Significance applet.
Ho:
Ha:
μ = 0
Ομ> 0
Ομ<0
Ομ± 0
0=60
n = 18
O I have data, and the
observed X= 17
The truth about the
population is μ = 0
Sample Mean=17
P-value = 0.2293
Transcribed Image Text:Macmillan Learning Does the job satisfaction of assembly workers differ when their work is machine-paced rather than self-paced? Workers are assigned either to an assembly line moving at a fixed pace or to a self-paced setting. All subjects work in both settings, in random order. This is a matched pairs design. After two weeks in each work setting, the workers take a test of job satisfaction. The response variable is the difference in satisfaction scores, self-paced minus machine-paced. The parameter of interest is the mean μ of the differences in scores in the population of all assembly workers. The study of job satisfaction requires that we test Ho:μ = 0 Ha: 0 Suppose we know that differences in job satisfaction scores (self-paced minus machine-paced) in the population of all workers follow a Normal distribution with standard deviation o = 60. Data from 18 workers give x = 17. That is, these workers prefer the self-paced environment on the average. Because the alternative is two-sided, the P-value is the probability of getting an x at least as far from μ = 0 in either direction as the observed x = 17. The figure shows the output of the P-Value of a Test of Significance applet. Ho: Ha: μ = 0 Ομ> 0 Ομ<0 Ομ± 0 0=60 n = 18 O I have data, and the observed X= 17 The truth about the population is μ = 0 Sample Mean=17 P-value = 0.2293
Macmillan Learning
Does the job satisfaction of assembly workers differ when their work is machine-paced rather than self-paced? Workers are
assigned either to an assembly line moving at a fixed pace or to a self-paced setting. All subjects work in both settings, in
random order. This is a matched pairs design. After two weeks in each work setting, the workers take a test of job satisfaction.
The response variable is the difference in satisfaction scores, self-paced minus machine-paced.
The parameter of interest is the mean μ of the differences in scores in the population of all assembly workers. The study of job
satisfaction requires that we test
Ho:μ = 0
Ha: 0
Suppose we know that differences in job satisfaction scores (self-paced minus machine-paced) in the population of all workers
follow a Normal distribution with standard deviation o = 60.
Data from 18 workers give x = 17. That is, these workers prefer the self-paced environment on the average. Because the
alternative is two-sided, the P-value is the probability of getting an x at least as far from μ = 0 in either direction as the
observed x = 17.
The figure shows the output of the P-Value of a Test of Significance applet.
Ho:
Ha:
μ = 0
Ομ> 0
Ομ<0
Ομ± 0
0=60
n = 18
O I have data, and the
observed X= 17
The truth about the
population is μ = 0
Sample Mean=17
P-value = 0.2293
Transcribed Image Text:Macmillan Learning Does the job satisfaction of assembly workers differ when their work is machine-paced rather than self-paced? Workers are assigned either to an assembly line moving at a fixed pace or to a self-paced setting. All subjects work in both settings, in random order. This is a matched pairs design. After two weeks in each work setting, the workers take a test of job satisfaction. The response variable is the difference in satisfaction scores, self-paced minus machine-paced. The parameter of interest is the mean μ of the differences in scores in the population of all assembly workers. The study of job satisfaction requires that we test Ho:μ = 0 Ha: 0 Suppose we know that differences in job satisfaction scores (self-paced minus machine-paced) in the population of all workers follow a Normal distribution with standard deviation o = 60. Data from 18 workers give x = 17. That is, these workers prefer the self-paced environment on the average. Because the alternative is two-sided, the P-value is the probability of getting an x at least as far from μ = 0 in either direction as the observed x = 17. The figure shows the output of the P-Value of a Test of Significance applet. Ho: Ha: μ = 0 Ομ> 0 Ομ<0 Ομ± 0 0=60 n = 18 O I have data, and the observed X= 17 The truth about the population is μ = 0 Sample Mean=17 P-value = 0.2293
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