What is the output of the comparison x>=y for x=[ 1224 ]; y=[-2 0 2 4]; O 0011 O 1101 O 1110 1111
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- Ex: Let A1 ={x, y}, A2 ={1, 2}, and A3 ={a, b}, Find A1 × A2, (A1 × A2) × A3, A1 × A2 × A3.2- Let a = [123; 2 3 4; 12 5], b = [ 2133 points ; 50 -2; 2 3 -1] prod = a* b. What is the value of prod?Write a generator function named count_seq that doesn't require any arguments and generates a sequence that starts like this: 2, 12, 1112, 3112, 132112, 1113122112, 311311222112, 13211321322112, ...To get a term of the sequence, count how many there are of each digit (in a row) in the **previous** term. For example, the first term is "one 2", which gives us the second term "12". That term is "one 1" followed by "one 2", which gives us the third term "1112". That term is "three 1" followed by "one 2", or 3112. Etc.Your generator function won't just go up to some limit - it will keep going indefinitely. It may need to treat the first one or two terms as special cases, which is fine. It should yield the terms of the sequence as **strings**, rather than numeric values, for example "1112" instead of 1112.
- 12 - fx =sort(StudentList!A2:F38,2, true) A C 1 Student ID Surname Forename 10009lAkins Lewis 10026 Allen Mary Explain the formula highlighted above and each of the parts in the formular. In other words, briefly describe in your own words what it does and what the result is. For this question, describe the following parameters in the formula above: - StudentList!A2:F38 is the range of cells (A2:F38) pulled from the sheet labeled Studentlist! - ,2 is - ,true is2- H=[0:5:20] What do you think the output could be? Your answerGiven the code: void d(int n) { if(n<2) { cout << n << " "; return; } cout << n << " "; d(n/3); } 1. Trace the function when n is 12.
- Please fix this code:le.com/forms/d/e/1FAlpQLSc6PlhZGOLJ4LOHo5cCGEf9HDChfQ-tT1bES-BKgkKu44eEnw/formResponse The following iterative sequence is defined for the set of positive integers: Sn/2 3n +1 ifn is odd if n is even Un = Using the rule above and starting with 13, we generate the following sequence: 13 u13 = 40 u40 =20 u20 = 10→ u10 =5 u5 = 16 u16 = 8 ug = 4 → Us =2 u2 =1. It can be seen that this sequence (starting at 13 and finishing at 1) contains 10 terms. The below function takes as input an integer n and returns the number of terms generated by the sequence starting at n. function i-Seq (n) u=n; i=%3; while u =1 if statement 1 u=u/2; else statement 2 end i=i+1; end statement 1 and statement 2 should be replaced by: None of the choices statement 1 is "mod(u,2)=D%3D0" and statement 2 is "u = 3*u+1;" statement 1 is "u%2" and statement 2 is "u = 3*u+1;" O statement 1 is "mod(n,2)=30" and statement 2 is "u = 3*n+1;"def fquartic(x): return (x**4-1) Find the roots There are two real roots of this function. Even though you may immediately see what those roots are, use scipy.optimize.root_scalar to find those roots one by one: Use the default method (i.e. don't specify a specific method for root finding) Specify appropriate x0 and x1 values for each one of the roots (don't pick them right on top of the roots, but pick them close) Make sure that the converged attribute of your solutions are both True.
- 2. code locations Consider the following C code and the corresponding assembly code: void baz(int a, int * p) { pushq %rbp movq %rsp,%rbp subq $16,%rsp int c; C = a-*p; movl %ecx,16(%rbp) movq %rdx, 24(%rbp) movq 24(%rbp), %rax movl (%rax),%eax movl 16(%rbp),%edx subl %eax,%edx movl %edx,%eax movl %eax,-4(%rbp) cmpl $0, -4(%rbp) je L2 if (c) { int d = c*2; movl -4(%rbp),%eax addl %eax,%eax movl %eax,-8(%rbp) *p -= d; movl 24(%rbp),%rax movl (%rax),%eax subl -8(%rbp),%eax movl %eax,%edx movq 24(%rbp), %rax movl %edx, (%rax) jmp L4: (continued on next page)What is output of A = [1 0 2]; b = [30 7]; c=a.*b ?To perform pivoting The following function is supposed to accept an augmented matrix, ab, and a pivot row index, i and returns a matrix with all elements below the pivot element eliminated. There are 3 errors in this code... find all the errors and circle them, then write the corrected version of each line below the code. def forward_elim(ab_orig,i): n = len(ab_orig) ab = copy.deepcopy(ab_orig) | for k in range(i,n): for j in range(i,n): ab[k.j] = ab_orig[k,i]*ab_orig[i.j] return ab return ab should be return ab_orig for k in range(i,n) should be for k in range(i+1,n) O for j in range(i,n) n should be n+1 ab[kj] = ab_orig[k,i]*ab_orig[i,j] should be ab[kj] = ab_orig[j.i]*ab_orig[i,k] V There should be a line just above the return ab line that reads: