What is the molarity of an unknown HCl solution with a specific gravity of 1.10 and an assay percentage of 18.5 %? (atomic weight: H = 1.00794, Cl = 35.4527)
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What is the molarity of an unknown HCl solution with a specific gravity of 1.10 and an assay percentage of 18.5 %? (atomic weight: H = 1.00794, Cl = 35.4527)
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- What is the molarity of an unknown HCI solution with a specific gravity of 1.10 and an assay percentage of 18.5% (H=1.0094, Cl=35.45.27)3.A sample is known to contain NaOH, Na2CO3 NaHCO3 or compatible mixture of these together with inert matter. With methyl orange, a 1.100 g sample requires 31.40 mL of HCl ( 1.00 mL is equivalent to 0.0140g CaO). With phenolphthalein indicator, the same weight of sample requires 13.30mL of the acid. What is the percent composition of the sample? ww wwApproximately 6 mL of conc. perchloric acid ( 72% ) was transferred to a bottle and diluted with about 1 liter of water. A sample containing 251.5 mg of primary standard Na2B4O7.10H2O (Fwt= 382g/mol) required 27.41 mL of the HClO4 solution to reach the methyl red end point. What is the molar concentration of the HClO4 solution? Na2B4O7.10H2O + HClO4 ------------> NaClO4 H2B4O7.10H2O
- simple steps Find the % of sodium carbonate in a sample if 5.002 g of the sample required 29.10 cm³ of 0.7344 mol dm-³ HCl for complete neutralisation. Make sure to solve the problem using the balanced equation. Solution (a) Determine moles of HC1 (titrant, known) (b) Use a balanced equation relate moles of analyte to moles of titrant (reaction ratio) (c) Determine mass of analyte (determine unknown) and % in sample10-27. A 10.231-g sample of window cleaner containing ammonia was diluted with 39.466 g of water. Then 4.373 g of solution were titrated with 14.22 mL of 0.106 3 M HCl to reach a bromocresol green end point. (a) What fraction of the 10.231-g sample of window cleaner is contained in the 4.373 g that were analyzed? (b) How many grams of NH3 (FM 17.031) were in the 4.373-g sample? (c) Find the weight percent of NH3 in the cleaner.Sixty mL of an impure acid solution was diluted to 500mL. A 30.00mL portion of this solution was titrated with 25.00mL of 0.1230M NaOH solution. Calculate the % (w/v) HAc in the sample. (FWt HAc = 60) Show all the solutions involved and round-off final answers to two decimal places except for Molarity. (Molar concentrations should be in four decimal places)
- 2- 150 mg of NazC2O4 containing solution is titrated with a KMNO4 solution with the corretion factor 1.03. The consumption of KMNO4 is found as 29 mL. Find the theoretical molarity (M) and real concentration (Mreal) of the KMNO4 solution.20.0 cm3 of a H2C2O4 solution required 8.60 cm³ of a 0.2010 M solution of sodium hydroxide for complete neutralization using phenolphthalein indicator (first permanent pink end-point). 20.0 cm3 of the same H2C2O4 solution required 7.85 cm³ of a KMnO4 solution to reach the permanent pink endpoint. Calculate the molarity of both the H2C2O4 solution and KMNO4 solution.Approximately 6.0mL of concentrated perchloric acid (70%) was transferred to a bottle and diluted with about 1.0L of water. A sample containing 251.5 mg of primary standard Na2B4O7.10H2O required 27.41 mL of the HClO4 solution to reach the methyl red end point. Calculate the molar concentration of the HClO4 (Fwt = 382g/mole)
- A 50.00 (±0.03) mL portion of an HCl solution required 29.71(±0.03) mL of 0.01963(±0.0030) M Ba(OH)2 to reach an end point with bromocresol green indicator. The molar concentration of the HCl is calculated using the equation below (attached image): a.) Calculate the uncertainty of the result (absolute error). M=0.02333(±?????) M b.) Calculate the coefficient of variation for the result. CV= (Sy/y) x 100%A chemist receive different mixtures for analysis with the statement that it contain NaOH, NaHCO3 , Na2CO3 or compatible mixtures of these substances together with the inert material. From the data given, identify the respective materials and calculate the percentage of each component. 1.000g samples and 0.2500 N HCl were used in all cases. Sample 1 With phenolphthalein as the indicator, 24.32 ml of HCl was used. A duplicate sample required 48.64 ml HCl using methyl orange as the indicator. Sample 2. With phenolphthalein as the indicator it uses 28.2 ml of HCl to make it colorless and added with methyl orange indicator and uses 11.3 ml of HCl to reach the end point.3. To 20,00 ml of 0,1250 mol/l solution of silver nitrate – 25,00 ml of 0,1000 mol/l solution of potassium thiocyanate were added. Calculate pAg of this mixture. pKs(AgSCN) = 11,97 Express numerical result with an accuracy of: Х,ХX