What is the [HA] (in mol L-¹) of a solution containing 1.439 mol L-¹ of a diprotic acid with pKA1 = 4.86 and PKA2 = 9.38 ? H₂A + H₂O PKA1 H3O+ + HA H3O+ + A²- HA + H₂O PKA2 Answer: 0.014

Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter8: Acids And Bases
Section: Chapter Questions
Problem 8.42P
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What is the [HA] (in mol L-¹) of a solution containing 1.439 mol L-¹ of a diprotic acid with pKA1 = 4.86 and PKA2 = 9.38 ?
PKA1
H₂A + H₂O H3O+ + HA
HA + H₂O=H3O+ + A²-
Answer: 0.014
PKA2
Transcribed Image Text:What is the [HA] (in mol L-¹) of a solution containing 1.439 mol L-¹ of a diprotic acid with pKA1 = 4.86 and PKA2 = 9.38 ? PKA1 H₂A + H₂O H3O+ + HA HA + H₂O=H3O+ + A²- Answer: 0.014 PKA2
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