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What is the current in the 6.0-Ω resistor?
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Solved in 2 steps with 2 images
- Determine the equivalent resistance between terminals a and b. R1 a 5 Ohms R2 7 Ohms R3 ww 8 Ohms R5 4 Ohms R4 10 OhmsR-18.0 2 R 6.00 2 R 3.00 2 9.0 V 3.0 V 13For a Wheatstone bridge with R1 = 432.1 Ω, R2 = 55.2 kΩ, and Rk = 6654.543 Ω, what is Rx ? For a Wheatstone bridge with R2 /R1 = 55, and Rk = 300Ω, what is Rx ?
- Calculate the current through resistor R₁. Give your answer in units of milliamperes. Please enter a numerical answer below. Accepted formats are numbers or "e" based scientific notation e.g. 0.23, -2, 1e6, 5.23e-8 Enter answer here mAR-18.0 2 R 6.00 2 R 3.00 2 9.0 V 3.0 V 13Q#1 (a) If in figure-(a) V-30V, Ri-2 Ω, R4Ω, Rs-6 Ω, R4-8 Ω, Rs- 10 Ω, Re-12Ω, R14Ω, R- 16 Ω, R18 Ω, R10 20 Ω then find the value of Rr , Ir , ] and V,.
- Apply the loop rule to loop abcdefghija in the figure below. E, = 24.0 V b d 0.10 2 R 5.0 2 Rs 20 2 E2 = 48.0 V R2 k 12 a e 0.50 2 40 2 0.20 2 R3 78 2 1s E3 E4 = 36.0 V 6.0 V %3D 1 0.05 Ωh O -(1,R2) + E, - (I,r2) – (1,R4) – (I3r2) - E4 – (1gr3) + E4 - (1,R3) = 0 O -(1,R1) + E, - (I,r2) – (1,R,) – (I3r3) – E, - (I,r3) + E - (I,R4) = 0 -(1,R;) + E, - (1,i) - (1,R5) – (I3r4) - E, - (13r3) + Ez - (I3R3) = 0 O -(1,R2) + E, - (I3r3) – (I„R5) – (I34) – E4 - (I3r3) + E4 - (I3R4) = 0 Additional Materials O ReadingFind I1, I2, and I3. 14 V 4.0 N be 6.0 N 10 V 2.0 Ω Loop abcda: 10 – 611 – 2 I3 = 0 (equation 1) Loop befcb: -412 -14 + 61 -10 = 0 (equation 2) Ii + I2 = I3 %3D I1 + I2 – I3 = 0 (equation 3)a 3 Ω w 5Ω h 6V+ L g Determine Vhe. 4 V + f + 7 V 6Ω W C 2V + d 4Ω e
- R₁ 5.0 Ω a R₂ 78 Ω» T4₁ 1₂ £₁ = 24.0 V 0.102 E2= 48.0 V w 0.50 Ω 2₂= 6.0 V Fa ww i 0.05 02 h R₂ ww 40 Q Rs - 20 Ω e > TA 20.20 Ω E₁36.0 V (a) Apply the junction rule at point a. Use the convention that current leaving a junction is positive and current entering a junction is negative. 1₁x + 1₂ x (d) Find the currents flowing in the circuit. 4₁ = А 1₂= SANA А A + 13x The next two parts of the problem will require you to use the math type box to enter an equation for Kirchhoff's loop rule in terms of variables only. An example problen with what the required formatting should look like for the system to recognize it as a correct answer is provided below. Example: Apply the loop rule to loop abcdelka, using variables instead of values. (i.e. E₁, 12, R₁, r₂ etc.). Use the Mathtype Editor (orange box). • Use subscripts using the menu in the math editor. • The answer is case sensitive (use R and r differently as appropriate). . When forming the product IR, don't forget the multiplication…Show that the relationship below is correct if point N is instantaneous center: ωχ VM w? I'N = rM + VM TM .N15V a. + AM 10.2. 4 t=0 um 45² 652 im + V 1 ic (t) b. Assume switch has been closed for Find a mathematical expression for Vc it capacitor is initially uncharged and the switch is closed at t = 0. Sketch Vc lt). 20m F a long time. opening Fird an expression for ic immediately after the switch and sketch it.