Water (p = 1.0 g/cm³) flows through a horizontal pipe of varying cross section. In the first section, the cross section area is 25.5 cm?, the flow speed is 0.4 m/s, and the pressure is 2.0 x 105 Pa. In the second section, the cross section area is 5 cm?. Calculate the pressure difference AP = IP, - P2l between the small and large sections. P,

Principles of Physics: A Calculus-Based Text
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Author:Raymond A. Serway, John W. Jewett
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Chapter15: Fluid Mechanics
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Problem 17P: Mercury is poured into a U-tube as shown in Figure P15.17a. The left arm of the tube has...
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Water (p = 1.0 g/cm³) flows through a horizontal pipe of varying cross section. In the first section, the cross section area is 25.5
cm?, the flow speed is 0.4 m/s, and the pressure is 2.0 x 105 Pa. In the second section, the cross section area is 5 cm?.
Calculate the pressure difference AP = IP, - P2l between the small and large sections.
P,
Transcribed Image Text:Water (p = 1.0 g/cm³) flows through a horizontal pipe of varying cross section. In the first section, the cross section area is 25.5 cm?, the flow speed is 0.4 m/s, and the pressure is 2.0 x 105 Pa. In the second section, the cross section area is 5 cm?. Calculate the pressure difference AP = IP, - P2l between the small and large sections. P,
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