Using For-Loop and If-statement, find the smallest number divisible by 4 in the 1D array "a1". Do not use any shortcut functions. The code should be able to work with any 1D array of numbers of any length. 0, 4, 0,-8, 2.5, 2, 14]) a1=np.array([-1,2,4,5,-10,
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- Using JavaScriptDefine a function getMonth which accepts number from 1 to 12 as an argument and return the descriptive name of the month. For example: getMonth(1) should return January while getMonth(12) returns December, finally getMonth(-1) returns null. Use array or object to define a list of names for the month and refrain from using if statement to check the argument if it's 1, 2, etc.take & array from user and print all the elements after doubling its and you have to separate function for doubling operation.In main() for now: do these - one at a time, each in it's own loop (we will make functions out of them later –Declare an array RandArray with 20 integers –Assign each of the 20 values with a random value from 0 to 99 Hint: Use rand()%100 For mimir: Do not call srand at the top of main. // normally: Call srand(time(0)) at the top of main –(you need #include<cstdlib>) –Write another loop that prints the array, with index values Important: If the output values do not match mimir, please add srand(17); // inside your main function - at the top code format: #include <iostream>using namespace std; #include <cstdlib> // required for rand() int main(){ srand(17); // define a constant ARRAYSIZE that is 20 // declare randArray // set the 20 elements in randArray to be a random number between 0 and 99 // hint: use rand()%100 // print the 20 values return 0;}
- Now, write another function that prints the values of any array in reverse order. (The function should not change the original array). As an example, if a [] = {1, 2, 3, 4, 5}; The function would print the values in reverse as: 5, 4, 3, 2, 1You are given arr, an array of integers, n, the size of the array, and a number k. The arguments are passed in the order: n, arr. k. Your task is to write the function findMinMaxSums which computes the maximum and minimum possible sums of the elements in the array after having discarded exactly k elements. Return these numbers in an array: [max, min]. You should not use any sorting library functions. • Note: k 2 #include 3 #include 4 5 std::vector findMin 6 // write your code he 7 8 9 10 11 12 13 14 15 16 17 18 Tests } int main() { int n, k; std::cin>> n; std::vectorcint> arra for (int i = 0; i > arr[ } Example 1 Example 2 Example 3 + Add Test Case (0/6) tRewrite the Binary search function in the textbook to use a generic type for the array elements. Test the function with arrays of int, double, and string values. *When using test arrays make sure elements are stored in ascending sorted order*
- Do this using C++. Initialize an integer array with random number between 0 to 51 using rand() function. And search one random generated key element from this array. If match not found, an error must be print on screen "key not found" or "element not found in the list". Searching technique "linear search"Create a function named "onlyOdd".The function should accept a parameter named "numberArray".Use the higher order function filter() to create a new array that only containsthe odd numbers. Return the new array.// Use this array to test your function:const testingArray = [1, 2, 4, 17, 19, 20, 21];Please help me with this: using js create an array of 30 random numbers that range between 1and 100. And yet again, write a function that will receive a number from the userand determine if that number exists in the array or not. But this time, start bySORTING your input list. After a sort, the list in problem 1 is as follows:[2, 2, 3, 5, 12, 14, 14, 15, 23, 36, 39, 41, 44, 44, 45, 48,49, 50, 52, 52, 59, 71, 81, 82, 88, 89, 89, 93, 96, 97] Approach: Implement a method called findC(x, A, i, j), where x is the number we arelooking for in array A, the first index of the array is i and the last index is j. We wantto determine whether x exists in A anywhere between index i and index j. Your firstcall to this method will therefore look like this: findC(x, A, 0, A.length-1). In the body of your function, compare x with the item that is in the middle of thearray, as you did before. As before, call the middle of index of the array mid. But thistime, if x<=a[mid], recursively call your…
- With the following C++ code, implement the “indirect sum” method of computing a sum. You will need to provide an implementation inside both the setup() and sum() functions in the sum_indirect.cpp file in the code harness. Here, setup() consists of initializing an array of length N to contain random numbers in the range 0..N-1 (hint: use lrand48() % N). --- #include <algorithm> #include <chrono> #include <iomanip> #include <iostream> #include <random> #include <vector> #include <string.h> void setup(int64_t N, uint64_t A[]) { printf(" inside sum_indirect problem_setup, N=%lld ", N); } int64_t sum(int64_t N, uint64_t A[]) { printf(" inside sum_indirect perform_sum, N=%lld ", N); return 0; }Programming in C language. RandomNumbers Declare an integer array locally with the size of 200. Create a program that asks the user how many numbers the have. Use your getChoicel) function from before. Make sure it does not exceed 200 as the locally declared array has the size of 200. Use a loop to assign random numbers from 1 to 10000 to the array elements. (Remember to use srand() to seed the random number generator). Use a second loop to display each number, and also determine the average of all values in the array. You must also find the largest and the smallest numbers. After the for loop, display the average of all numbers. This program will let you enter a list of numbers into an array. It will then display all of the numbers, and finally display the average of all numbers. How many numbers would you like to enter?10 Number 1 is 42 Number 2 is 8468 Number 3 is 6335 Number 4 is 6501 umber 5 is 9170 Number 6 is 5725 Number 7 is 1479 Number 8 is 9359 Number 9 is 6963 Number 10 is…A left rotation operation on an array of size n shifts each of the array's elements 1 unit to the left. Given an integer, d, rotate the array that many steps left and return the result. Example:d=2arr=[1,2,3,4,5] After 2 rotations, arr'=[3,4,5,1,2]. Function Description: Complete the rotateLeft function in the editor below. rotateLeft has the following parameters: 1. int d: the amount to rotate by 2. int arr[n]: the array to rotate Returns 1. int[n]: the rotated array Input Format: The first line contains two space-separated integers that denote n, the number of integers, and d, the number of left rotations to perform.The second line contains n space-separated integers that describe arr[]. Constraints: 1. 1<=n<=10^5 2. 1<=d<=n 3. 1<=a[i]<=10^6