Using Canadian Standards: CSA S16, Steel handbook design aids, Canadian building code. Determine the governing slenderness ratio for: A W250x58, L = 24 ft, one end pinned and the other fixed. An HSS305x203x13, L = 18 ft, both ends fixed, and the weak axis is braced at third points
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- A two span beam subjected to shear and flexure only is reinforced as follows: SECTION @ MIDSPAN @ FACE OF SUPPORTS TOP BARS 2-∅20 mm 5-∅20 mm BOTTOM BARS 3-∅20 mm 2-∅20 mm Given: Stirrup diameter, ds = 10 mm Concrete f'c = 21 MPa Steel rebar fy = 415 MPa Stirrup fy = 275 MPa Beam size b x h = 270 mm x 450 mm Assume all bars laid out in single layer. Calculate the following: Tensile steel ratio in positive bending at midspan = __________ (in 5 decimal places) Design Moment strength of section at midspan for positive bending = ___________ kN·m (nearest whole number) Nominal Moment strength of section at face of support for negative bending = ___________ kN·m (nearest whole number)a two span beam subject to shear and flexure only is reinforced as follows: Section: TOP BARS @ midspan: 2-ø20mm @ face of supports: 5-ø20mm Section: BOTTOM BARS @midspan: 3-ø20mm @ face of supports: 2-ø20mm GIVEN: Stirrup diameter ds = 10mm concrete f'c= 21 mpa steel rebar fy= 415 mpa stirrup fy = 275 mpa beam size b x h = 270 mm x 450 mm assume all bars laid out in a single layer. Determine the DESIGN moment strength of section at midspan for positive bendinga two span beam subject to shear and flexure only is reinforced as follows: Section: TOP BARS @ midspan: 2-ø20mm @ face of supports: 5-ø20mm Section: BOTTOM BARS @midspan: 3-ø20mm @ face of supports: 2-ø20mm GIVEN: Stirrup diameter ds = 10mm concrete f'c= 21 mpa steel rebar fy= 415 mpa stirrup fy = 275 mpa beam size b x h = 270 mm x 450 mm assume all bars laid out in a single layer. Determine the tensile ratio in positive bending at midspan =
- Problem 3b. The built-up shown has Fy=50 ksi MC18X 42.7 W12 X 72 KL = 18.5 ft %3D Find the following: a. The KL/r b. The design strength for LRFD. c. The allowable strength for ASD. d. Is the section? Why?A simply supported beam section was investigated and found out the following elements: b=250mm h=450mm concrete cover = 40mm diameter of stirrups = 10mm fy = 276Mpa f'c = 34.5 Mpa Bot bar reinforcement: 2pcs-20mm Determine the Maximum steel ratio permitted by the code answer in millimeter and 4 decimal places.For the column shown what is the nominal compressive strength (Pn) ? Pn=? W12x50 10 12X50 THT X combilevered WI
- Refer to the figure shown below. 350 Given are the following: fc 55 MPa fou 1,350 MPa Aps - 1.500 mnm2 fpy - 1,100 MPa Use bonded tendons as prestressed reinforcement. Determine the design monment capacity of the section. (kN-m)Architectural considerations of a certain non-structural element requires an upright triangular beam section with the following design cross section: Width of Base, b 300 mm Overall Height, H = 450 mm Effective Depth, d 400 mmUse NSCP 2010 Provisions, f'c = 21 MPa, fy 345 MPa (A). Determine the no. of pcs. 16mm dia, bars at balanced strain condition. (B). Determine the no. of pcs. 16mm dia, bars for maximum steel requirement of code for tension control. (C). Determine the factored strength of the section if reinforced with 3-16mm dia, bars.Q3 STEEL
- Design Specifications 1st and 2nd floor Member Roof Deck Load (Typical) Live Load Item Superimposed Dead Load (Typical) Live Load Superimposed Dead a. b. C. For the structural plan attached, Hint: Self-weight B1 B2 Notes: 1. For simplicity, neglect self-weight of concrete slab B3 G1 G2 C1 C2 Design Loadings Application Slabs Slabs Slabs Slabs Value 4 3 2 3 4 4 4 Value 4 means pinned means continuous Assume all members have the same stiffness (same El) for simplicity 8 4 6 Unit kN/m kN/m kN/m kN/m kN/m kN/m kN/m Unit kPa kPa kPa kPa Determine the factored bending moment (LRFD) to be used in the design of Beam B1 in kNm. Determine the factored shear force (LRFD) to be used in the design of Girder G2 in kN. Determine the factored axial load (LRFD) to be used in the design of Column C1 in kN. -I T C2 G2 C1 G1 C1 5000 B3 1 B2 B1 B2 C2 C1 ∙H. GROUND FLOOR FRAMING PLAN C1 I G2 H G1 İ 8 C2 C1 G1 C1 5000 B3 1 B2 B1 + B2 1 B3 . C2 C1 I C1 SECOND FLOOR AND ROOF DECK FRAMING PLAN G1 G1Q4/ Give reason PLLA and PDLA are more common used for load-bearing applications?Is the beam shown below adequate for flexural (moment) stresses? Use ASD.