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Use the Squeeze Theorem to show that lim x2 co X-0 cos(207TX) = 0. Illustrate by graphing the functions f(x) = -x², g(x) = x² cos(207x), and h(x) = x² on the same screen. Let f(x) = -x², g(x) = x² cos(207x), and h(x) = x². Then 0s cos(207x) s 1 f(x)=x² cos(207x)s ? Since lim f(x)= lim h(x)= x-0 x-0 by the Squeeze Theorem we have lim_ g(x)=

Use the Squeeze Theorem to show that lim x2 co X-0 cos(207TX) = 0. Illustrate by graphing the functions f(x) = -x², g(x) = x² cos(207x), and h(x) = x² on the same screen. Let f(x) = -x², g(x) = x² cos(207x), and h(x) = x². Then 0s cos(207x) s 1 f(x)=x² cos(207x)s ? Since lim f(x)= lim h(x)= x-0 x-0 by the Squeeze Theorem we have lim_ g(x)=

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter4: Calculating The Derivative
Section4.CR: Chapter 4 Review
Problem 5CR: Determine whether each of the following statements is true or false, and explain why. The chain rule...
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Use the Squeeze Theorem to show that lim x² cos(207TX) = 0. X → 0 Illustrate by graphing the functions f(x) = -x², g(x) = x² cos(207x), and h(x) = x² on the same screen. Let f(x) = -x², g(x) = x² cos(207tx), and h(x) = x². Then [0 ✓≤ cos(207TX) ≤ 1 f(x) V ≤ x² cos(207Tx) ≤ ? S . Since lim f(x) = lim_h(x) : = X → 0 X → 0 , by the Squeeze Theorem we have lim g(x) X → 0 =
Transcribed Image Text:Use the Squeeze Theorem to show that lim x² cos(207TX) = 0. X → 0 Illustrate by graphing the functions f(x) = -x², g(x) = x² cos(207x), and h(x) = x² on the same screen. Let f(x) = -x², g(x) = x² cos(207tx), and h(x) = x². Then [0 ✓≤ cos(207TX) ≤ 1 f(x) V ≤ x² cos(207Tx) ≤ ? S . Since lim f(x) = lim_h(x) : = X → 0 X → 0 , by the Squeeze Theorem we have lim g(x) X → 0 =
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