Use Stokes' Theorem to calculate fe F-dĩ, where F = zyi+3=j+5zk, and C is the closed path around a square of side 4, centered at the origin, lying in the rz-plane, and oriented clockwise viewed from the positive y-axis.

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A: Given that z=3-j4-3+j44∠A+jsin30°

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A: (.)   The given series is ,                                                        ∑n=1∞1+n281+na7…

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