Under what conditions would a test cross be performed? When an organism with the dominant phenotype has an unknown genotype. When trying to determine the outcome of a trihybrid cross. When an organism with the recessive phenotype has an unknown genotype. When an organism has a known genotype but unknown phenotype.
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A: Answer
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- A X cross, is conducted when an organism with the dominant phenotype and unknown genotype is crossed with a Y individual in order to identify the unknown genotype.Distinguish between monohybrid, dihybrid and test crosses. Maximum number of characters (including HTML tags addedGive typing answer with explanation and conclusion "B"-yellow "b"-green. When 2 heterozygous parents for both traits are crossed it's called a dihybrid cross- AaBb × AaBb. Fill in the Punnett Square with the genotypes of this cross.
- Using the following information perform following crosses using the forked line and predict all possible phenotypes types of the offspring. List the number and description of the phenotypes of the offspring. 1. aa BB Cc Dd Ee X aa bb Cc Dd EE 2. Ff Rr Gg dd Bb X Ff RR Gg Dd Bb 3. Dd gg JJ bb Hh Ee X DD GG Jj Bb Hh EeConstruct a sex-linked cross on a black male cat and a female orange cat. The genotypes involved are XB, XO, and Y. State the genotypes and phenotypes of the offspring.Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are dominant to green (y). What are the possible genotypes and phenotypes for a cross between PpYY and ppYy pea plants? How many squares would you need to complete a Punnett square analysis of this cross?
- figure shows the results of a dihybrid cross involving seed shape and seed color. Q. What proportion of the round and yellow F2 progeny from this cross is homozygous at least at one locus?Three linked loci are evaluated to determine the recombination frequency of the loci. To set up the test cross, an individual that is true breeding dominant for all three phenotypes is crossed with an individual that is true breeding recessive for all three phenotypes. F1 offspring are crossed with individuals that are recessive for all phenotypes. The phenotypic results are shown in the table below. Phenotype Number of Offspring Dominant 1, Dominant 2, Dominant 3 322 Dominant 1, Dominant 2, Recessive 3 82 Recessive 1, Dominant 2, Recessive 3 5 Dominant 1, Recessive 2, Dominant 3 2 Recessive 1, Dominant 2, Dominant 3 28 Recessive 1, Recessive 2, Dominant 3 89 Recessive 1, Recessive 2, Recessive 3 312 Dominant 1, Recessive 2, Recessive 3 25 1. Which two phenotypes are parental? 2. What is the map distance between locus 1 and locus 2? 3. What is the map distance between locus 1 and locus 3? 4. What is the map distance between…F2 Cross: Tall, White, Axial x Dwarf, Violet, Terminal DdwwAA x ddWWaa Character: Stem height, Flower color & position Use fork-line method to check the possible offspring. Show and interpret all the possible genotypes and phenotypes of the offsprings.
- Using the punnet square solve the following:Please work out this Di-Hybrid cross . -Mom is homozygous dominant for both traits -Dad is homozygous recessive for both traits Trait Key:S= Straights= CurlyL= Long l= Short 1st Question to answer ---- How many of the offspring come out straight & long? 2nd Question to answer ---- How many of the offspring come out curly & short?Some mice are born with a yellow coat controlled by the gene Y. Examine the setup and outcome of the following crosses, which produce two generations: Po: yellow mouse X gray mouse F1 :5 yellow mice, 4 gray mice P: yellow mouse from F1 X yellow mouse from F1 F2 : 7 gray mice, 15 yellow mice with 9 dead Analyze the information provided to answer these questions: • What type of cross is the first cross? • Which trait is dominant? • What is the genotype of the yellow mouse in the first cross? • What is the genotype of the gray mouse in the second cross? Why are 9 mice dead in F2?A cross in plants is done between the parents CCDD and ccdd to create a dihybrid F1 plant. This F1 plant was subsequently test crossed to a ccdd plant and you find the the progeny as follows: 40% CD 40% cd 10% Cd 10% cD If you did a similar experiment in which the parents were changed to ccDD and CCdd, what percentage of the test cross progeny would have the cd phenotype? 40% 80% 10% 20%