Two square conductor plates, whose sides measure 0.5mm, were separated by a distance of 1mm to make a parallel-plate capacitor. I. What is the capacitance of this capacitor? A. 0.002 nF B. 2.2125 pF C. 0.0022 pF D. 221.25 uF II. What is the amount of charge on each plate given that the magnitude of electric field between the parallel plates is 3,000,000,000 N/C? A. 6.64 x 1-^-9 nC B. 6 x 10^-6 C C. 664 C D. 6.64 nC III. What is the electric potential difference between the parallel-plates? A. 300 V B. 3 MV C. 3 000 000 MV D. 300 000 V
Two square conductor plates, whose sides measure 0.5mm, were separated by a distance of 1mm to make a parallel-plate capacitor. I. What is the capacitance of this capacitor? A. 0.002 nF B. 2.2125 pF C. 0.0022 pF D. 221.25 uF II. What is the amount of charge on each plate given that the magnitude of electric field between the parallel plates is 3,000,000,000 N/C? A. 6.64 x 1-^-9 nC B. 6 x 10^-6 C C. 664 C D. 6.64 nC III. What is the electric potential difference between the parallel-plates? A. 300 V B. 3 MV C. 3 000 000 MV D. 300 000 V
Chapter8: Capacitance
Section: Chapter Questions
Problem 62P: When a 360-nF air capacitor is connected to a power supply, the energy stored in the capacitor is...
Related questions
Concept explainers
Dielectric Constant Of Water
Water constitutes about 70% of earth. Some important distinguishing properties of water are high molar concentration, small dissociation constant and high dielectric constant.
Electrostatic Potential and Capacitance
An electrostatic force is a force caused by stationary electric charges /fields. The electrostatic force is caused by the transfer of electrons in conducting materials. Coulomb’s law determines the amount of force between two stationary, charged particles. The electric force is the force which acts between two stationary charges. It is also called Coulomb force.
Question
INSTRUCTIONS : Two square conductor plates, whose sides measure 0.5mm, were separated by a distance of 1mm to make a parallel-plate capacitor.
I. What is the capacitance of this capacitor?
A. 0.002 nF
B. 2.2125 pF
C. 0.0022 pF
D. 221.25 uF
II. What is the amount of charge on each plate given that the magnitude of electric field between the parallel plates is 3,000,000,000 N/C?
A. 6.64 x 1-^-9 nC
B. 6 x 10^-6 C
C. 664 C
D. 6.64 nC
III. What is the electric potential difference between the parallel-plates?
A. 300 V
B. 3 MV
C. 3 000 000 MV
D. 300 000 V
PLEASE WRITE THE SOLUTIONS PLEASE THANK YOU
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Recommended textbooks for you
Physics for Scientists and Engineers, Technology …
Physics
ISBN:
9781305116399
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:
9781133104261
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Physics for Scientists and Engineers, Technology …
Physics
ISBN:
9781305116399
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:
9781133104261
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Physics for Scientists and Engineers: Foundations…
Physics
ISBN:
9781133939146
Author:
Katz, Debora M.
Publisher:
Cengage Learning
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
Physics for Scientists and Engineers with Modern …
Physics
ISBN:
9781337553292
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning