Two previously undeformed rectangular specimens of an alloy are to be strain hardened by reducing their cross-sectional areas (rectangular cross-sections will be maintained). For one specimen, the initial and deformed dimensions are 120 mm x 150 mm and 80 mm x 180 mm, respectively. The second specimen, with initial area of 20,800 mm^2 must have the same deformed hardness as the first specimen. a) Calculate the percent cold work (as %; include units in answer) done on the first specimen. b) Calculate the second specimen's area in mm^2 (include units) after deformation.

Two previously undeformed rectangular specimens of an alloy are to be strain hardened by reducing their cross-sectional areas (rectangular cross-sections will be maintained). For one specimen, the initial and deformed dimensions are 120 mm x 150 mm and 80 mm x 180 mm, respectively. The second specimen, with initial area of 20,800 mm^2 must have the same deformed hardness as the first specimen. a) Calculate the percent cold work (as %; include units in answer) done on the first specimen. b) Calculate the second specimen's area in mm^2 (include units) after deformation.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

A material has a linear elastic perfectly plastic stress-strain. A cylindrical specimen of that material having an initial length of 35 mm and a tadius of 7 mm is pulled until it elongates 0.8mm. a. Calculate the stain and the corresponding stress at that elongation value. b. Afterward, the specimen is released to zero stress level, how does the final length of the specimen compare with its original length? How much plastic deformation remains if it exists?
The problem: A 13 mm-diameter tensile specimen has a 50 mm gauge length. The load corresponding to the 0.2 percent offset is 6800 kg and the maximum load is 8400 kg. Fracture occurs at 7300 kg. The diameter after fracture is 8 mm and the gauge length at fracture is 65 mm. a) Calculate the standard mechanical properties of the used specimen in the tension test, first determine the standard properties and then calculated them? This includes computation each of: Yield strength. Ultimate tensile strength. Fracture stress. Ductility (percent of elongation and reduction in cross section area). b) If E = 207 GPa, estimate the elastic recoverable strain at maximum load? c) By using the same conditions of the above test, Discussion the possibility to replace the metallic sample with ceramic sample? tion:
200 stress 150 (MPa) 100 50 0.1 0-2 strain From the tensile stress-strain behavior for the brass specimen the diameter is 12-8 mm Calcalate the folluwing:- %3B 1- The Yield stress. 2-Modulus of elasticity. 3 - The Tensile strength.
%VY lI. photo_202... -> 200 stress (MPa) 150 100 50 0.1 0.2 strain From the tensile stress -strain behavior for the brass specimen ,0 the diameter is 12-8 mm Calculat e the followWing:- |- The Yield stress, 2-Modulus of elasticity. 3- The Tensile strength .
The problem: A 13 mm-diameter tensile specimen has a 50 mm gauge length. The load corresponding to the 0.2 percent offset is 6800 kg and the maximum load is 8400 kg. Fracture occurs at 7300 kg. The diameter after fracture is 8 mm and the gauge length at fracture is 65 mm. a) Calculate the standard mechanical properties of the used specimen in the tension test, first determine the standard properties and then calculated them? This includes computation each of: Yield strength. Ultimate tensile strength. Fracture stress. Ductility (percent of elongation and reduction in cross section area). b) If E = 207 GPa, estimate the elastic recoverable strain at maximum load? c) By using the same conditions of the above test, Discussion the possibility to replace the metallic sample with ceramic sample?
Q5:In tensile test of rectangular cross section specimen has 200 mm initial length, the width and thickness decrease by 12% and 8%. Find the change in length ?
In the First project: you have been asked to perform tensile testing for four different materialsand analyse the results and work on some NDT process selection:a. For the results shown in Table 1 of the tensile testing that you have performed, find thefollowing, if you know that the original length of specimen is 20.8 mm and the original diameteris 6.4 mm. Fill the calculated results in the summary table below (Table 1):1. Plot the engineering stress versus engineering strain for each material and L-D Diagram.2. Compute the modulus of elasticity, E in GPa.3. Determine the yield strength at a strain offset of 0.002.4. Determine the tensile strength in MPa.5. What is the approximate %El ductility, measured by percent elongation?6. Compute the modulus of resilience.7. Determine the fracture stress in MPa.8. Compute the final area (Af) in mm2.
For a piece of copper alloy, a standard stress test was applied to it, the following data was collected, from which a stress-strain diagram must be generated, where as data it is known that the initial diameter of the element is 0.505in. The analysis must include the following: 1.Modulus of Elasticity and modulus of resilience. 2.Percentage of elongation. 3.Percentage of area reduction. 4.Real and engineering stress at fracture. It is known that after the specimen fractures, its dimensions in terms of length and diameter are 3.014 and 0.374in, respectively.
The problem: A 13 mm-diameter tensile specimen has a 50 mm gauge length. The load corresponding to the 0.2 percent offset is 6800 kg and the maximum load is 8400 kg. Fracture occurs at 7300 kg. The diameter after fracture is 8 mm and the gauge length at fracture is 65 mm. a) Calculate the standard mechanical properties of the used specimen in the tension test, first determine the standard properties and then calculated them? This includes computation each of Yield strength. Ultimate tensile strength. Fracture stress. Ductility (percent of elongation and reduction in cross section area). b) IfE- 207 GPa, estimate the elastic recoverable strain at maximum load? ) By using the same conditions of the above test, Discussion the possibility to replace the metallic sample with ceramic sample?
As Fast As you can Please mak sure the answer is correct 100% Please match the following to the appropriate areas or sublocations illustrated on the steel stress-strain curve shown below: (ultimate tensile stress- yield stress - repture stress) (4) The maximum stress point on the stress strain curve. (2) The point where the proportional limit ends and the moment the elastic limit of the specimen is reached, the specimen will return to its original state after the loading is removed. Typically occurs before the steel specimen starts to plastically yield. (5) The point at which the steel specimens has underwent necking and breaks. This typically occurs after the maximum stress is reached during the experiment.
C1. A mild steel tensile specimen of initial length 41 mm and initial diameter 6.2 mm is subjected to a tensile test and the following data are obtained. Yield Strength as 115 MPa Maximum Strength as 210 MPa Fracture Strength as 168 MPa Percentage of Elongation as 50 % Percentage of Reduction in area as 32% Determine the Final length, Final area, Yield load, Ultimate load & Fracture load. The yield load in N is The Ultimate load in N is The Fracture load in N is
The following data were obtained from the tensile test of Aluminum alloy. The initial diameter of testspecimen was 0.505 inch and gauge length was 2.0 inch. Plot the stress strain diagram and determine(a) Proportional Limit (b) Modulus of Elasticity (c) Yield Stress at 0.2% offset (d) Ultimate Stress and(e) Nominal Rupture Stress.