3a. T(s)=4s* + 8s +16s² +12s3s +2b. T(s)=4.s* +8s' +16s² +12s2s +2s +3с. Т(s) %—4s* + 8s' +16s² +12sd. T(s)=432s* +4s' +8s² +6s T(t) 0,(1)02(1),J2D1KD2D1=D2= 2 N-m-s/rad, J1=J2= 2 kg/m², K=3 N/m.The transfer function of the system T(s) (Theta2 isthe output and The torque is the input) is

Answered: T(t) 0\(1) 02(t), J2 D1 K D2 D1=D2= 2…

T(t) 0\(1) 02(t), J2 D1 K D2 D1=D2= 2 N-m-s/rad, J1=J2= 2 kg/m2, K=3 N/m. The transfer function of the system T(s) (Theta2 is the output and The torque is the input) is

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

3
a. T(s)=
4s* + 8s +16s² +12s
3s +2
b. T(s)=
4.s* +8s' +16s² +12s
2s +2s +3
с. Т(s) %—
4s* + 8s' +16s² +12s
d. T(s)=
4
3
2
s* +4s' +8s² +6s

T(t) 0,(1)
02(1),
J2
D1
K
D2
D1=D2= 2 N-m-s/rad, J1=J2= 2 kg/m², K=3 N/m.
The transfer function of the system T(s) (Theta2 is
the output and The torque is the input) is

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