Three different bacteria are cultured in one environment and feed on three nutrients. Each individual of species I consumes 1 unit of each of the first and second nutrients and 2 units of the third nutrient. Each individual of species II consumes 2 units of the first nutrient and 2 units of the third nutrient. Each individual of species III consumes 2 units of the first nutrient, 3 units of the second nutrient, and 5 units of the third nutrient. The culture is given 5,300 units of the first nutrient, 6,000 units of the second

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.4: Applications
Problem 28EQ
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Three different bacteria are cultured in one environment and feed on three nutrients. Each individual of species I consumes 1 unit of each of the first and second nutrients and 2 units of the third nutrient. Each individual of species II consumes 2 units of the first nutrient and 2 units of the third nutrient. Each individual of species III consumes 2 units of the first nutrient, 3 units of the second nutrient, and 5 units of the third nutrient. The culture is given 5,300 units of the first nutrient, 6,000 units of the second nutrient, and 11,300 units of the third nutrient. Let 
x = individuals of species I,
 
y = individuals of species II,
 and 
z = individuals of species III.
Write an equation for the total number of units of the first nutrient in terms of xy, and z.
 
 
 
Write an equation for the total number of units of the second nutrient in terms of xy, and z.
 
 
 
Write an equation for the total number of units of the third nutrient in terms of xy, and z.
 
 
 
How many of each species can be supported such that all of the nutrients are consumed? (If there are infinitely many solutions, express your answers in terms of z as in Example 3.)
(x, y, z) =
 
 
 
 
 
 
 
, where 700 ≤ z ≤ 2000
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