These equations can be applied for dry soil, except: a) Sre = wGs b) Gsp, /1+ e c) Ms / V d) Ph/1 + w
Q: A saturated soil specimen has w = 36% and ᵞd = 85.43 lb/ft3. Determine: Void ratio
A: Given: Water content, w = 36% = 0.36 Dry unit weight = 85.43 lb/ft3 Degree of saturation, S = 100% =…
Q: A saturated soil has a void ratio of 0.6 and specific gravity of 2.8. Compute the value of (a) the…
A: Given: Void ratio, e = 0.6 Specific gravity, Gs = 2.8 Degree of saturation, S = 1
Q: The soil with specific gravity (Gs) of 2.61 has a water content of 45%. The void ratio is 0.67, and…
A: Given that Dry density = 16kN/m3 void ratio e = 1.67
Q: Classify this soil for sandy soil if the submerged unit weight equal to water unit weight emax =…
A: Formula used - γ' = G - Seγw1 + eHere,γ' = submerged unit weightG = specific gravity = 2.65e = void…
Q: Q-14: A soil has a void ratio of 0.70, degree of saturation 50% and G =2.7. Find the water content,…
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Q: 1. A 76.6% saturated soil has a moisture content of 38.4% and a specific gravity of 2.683. Find the…
A: Given data : The value of moisture content w=38.4100=0.384 The value of specific gravity G=2.683 The…
Q: A soil deposit consists of four horizontal soil layers. The ratio of average permeability in…
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Q: Calculate the dry unit weight of soil having void ratio of 0.73 and a value of Gs of 2.72. Take unit…
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Q: Given data Degree of saturation=D0.5 Void ratio=0:47 Specific gravity of soil=2.7 Determine water…
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Q: The moist unit weight of soil sample is 17.5 kN/m3. Given that w=12% and Gs 2.64. Carry out…
A: Solution: Given Data: Moist unit weight of sample soil sample=17.5 kN/m3w=12%Gs=2.64 1. Dry unit…
Q: Determine the water content of the soil with zero air voids and void ratio equal to 0.5. Take G=2.7
A: Given, e = void ratio= 0.5 G = 2.7 Since soil sample filled with zero air voids so, S = 1
Q: A saturated soil has a void ratio of 0.6 and specific gravity of 2.8. Compute the value of (a) the…
A: Given: Void ratio, e = 0.6 Specific gravity, Gs = 2.8 Degree of saturation, S = 1 (as the soil is…
Q: Approximate ratio of the permeabilities of two clay soils, having D₁ values of 0.8 mm and 0.4 mm…
A: given- D10=0.8 mm & 0.4 mmratio of permeabilities is required.
Q: An anisotropic soil deposit has coefficient of permeability in vertical and horizontal directions as…
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Q: A saturated soil specimen has w = 36% and ᵞd = 85.43 lb/ft3. Determine: Saturated unit weight (in…
A: Given: Water content, w = 36% Dry unit weight, γd = 85.43 lb/ft3
Q: A) Calculate the void ratio and specific gravity of solids of a saturated soil whose unit weight is…
A: Given For a- Unit weight 1877kg/m3 , water content= 41% b- area = 6cm2, length = 12 cm, h = 20-3 =…
Q: Determine the saturated unit weight of soil in kN/m3.
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Q: Dry sand e = 0.6 G, = 2.68 H Groundwater table Clay e = 0.8 G, = 2.75 H, Figure Q1(b): The soil…
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Q: Partially saturated soil is said to be
A: In general, soil is a three phase system occupied of solid, liquid and gaseous matter. The voids in…
Q: 2. The void ratio of a soil is 1.2. Determine the buik and effective unit weights at, first 75%,…
A: A mixture's void ratio is the volume of voids divided by the volume of solids. The void ratio is the…
Q: 25. Degree of saturation of a natural soil deposit having water content 15%, specific gravity 2.50…
A: given- water contentw=15%specific gravity G=2.50void ratio e=0.5
Q: The moist unit weights and degrees of saturation of soil are given in the table
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Q: PROBLEM NO. 2 A fined grained soil (no sand) is found to have a liquid limit of 70%, and a plastic…
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Q: Results of two consolidated-drained triaxial tests on a clayey soil are as follows: a's (kN/m?) Test…
A: Since you have asked multiple question, we will solve the first question for you. If youwant any…
Q: Determine Gs, void ratio and saturated unit weight of a saturated soil sample if: a. Dry unit weight…
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Q: 2.1 A soil specimen has a volume of 0.05 m² and a mass of 87.5 kg. Given: w = 15%, G, = 2.68.…
A: Given,Volume of soil (V)=0.05 m3mass of soil (M)=87.5 kgwater content (w)=15%w=0.15Gs=2.68Now,Bulk…
Q: void ratio and the specific gravity of soil. 2. In a fully saturated soil, prove that Wsat = Yw %3!…
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Q: Problem D The critical hydraulic gradient for a soil sample is equal to 1.18. If the specific…
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Q: 4. For a given soil, the following are known: G, = 2.74, moist unit weight, y = 20.6 kN/m³, and…
A: Specific gravity, bulk density and water content has been given and it has been asked to determine…
Q: 5. The moist unit weights and degree of saturation of a soil are given in the table. Determine void…
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Q: A saturated soil sample has following properties: water content = 86 % void ratio = 0.7 What is the…
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Q: : (A) The degree of saturation of a soil is 55% and the moist unit weight is 16.66 kN/m. When the…
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Q: Compute the void ratio of uniformly graded coarse grained soil in (i) loosest possible state (ii)…
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Q: For a given soil, the following are known: G= 2.74, moist unit weight = 20 kN/m^3, and moisture…
A: Given data : The value of specific gravity G=2.74 The value of water content w%=16 The value of…
Q: Find the water content of soil if dry unit weight is 18 KN/m3 and Bulk unit weight is 20 KN/m3
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Q: For a given sand, the maximum and minimum void ratios are 0.78 and 0.43 respectively. Given Gs=2.67,…
A: Given that: Maximum void ratio, emax = 0.78…
Q: 2. For a saturated soil, the following are given: w=23%, Gs=2.67. Determine: A. Saturated unit…
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Q: Discuss whether the statement "Void ratio changes when a densely packed dry soil is being saturated"…
A: Void ratio is defined as the volume of voids to the volume of solids . Void ratio (e)=VVVSvolume of…
Q: The hydraulic gradient of a soil of specific gravity 2.67 and void ratio 0.45 is 0.46, calculate the…
A: Given: Specific gravity, G = 2.67 Void ratio, e = 0.45 Hydraulic gradient, i = 0.46
Q: As per Darcy's Law, permeability of a soil is directly proportional to the velocity of water flowing…
A: Darcy law describe about flow through soil . Darcy law states that discharge per unit time is…
Q: Situation 1: For a given soil sample it has a specific gravity of 2.66, void ratio e=0.60is…
A: Specific Gravity = 2.66 Void ratio = 0.6 Unit weight when soil become S = 40 % Ysat = [(…
Q: A soil specimen has a volume of 0.06 m3 and a mass of 89.5 kg. Given: w=16%, Gs = 2.64. Determine a.…
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Q: A 76.6% saturated soil has a moisture content of 38.4% and a specific gravity of 2.683. Find the…
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Q: How to solve this question? A soil has a dry density of 1.84 g/cm3 and void ratio of 0.45.…
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Q: 2.1 According to the following soil information: D=0.41mm, D»=0.185mm, Dv=0.09mm Please calculate…
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Q: In an embankment, the soil was compacted at a unit weight of 17 kN/m³. The water content was…
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Q: A fully saturated soil mass has specific gravity of 2.5 void ratio 0.45 .Determine water content
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Q: For a soil given determine coefficient of uniformity
A: Given data : Diameter corresponding to 60% finer (D60)=1.81 mmDiameter corresponding to 10% finer…
Q: Classify this soil for sandy soil if the submerged unit weight equal to water unit weight emax =…
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Q: 1) The moist unit weight of a soil is 19.2 kN/m3 . Given that Gs = 2.69 and w = 9.8%, determine: a.…
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- Question 2 Classify the following soils using the Unified soil classification system. Give the group symbol. No. 4 = 60 No. 200 = 40 LL = 26 PL = 4 A GW-GM В GW-GC c) GP-GM GM-GCQuestion 14 Classify the following soils using the Unified soil classification system. Give the group symbol. No. 4 = 100 No. 200 = 77 LL = = 63 PL 25 %D A) CL В ML MH CHThese equations can be applied for dry soil, except: a) Sre = wGs %3D b) Gspw /1+ e c) Ms / V d) Po /1 + w
- Q1: Classify the below soil according to Unified Soil Classification System (USCS) and .the AASHTO System Sieve No. sieve Diameter 4.75 2 1.18 06 pass % 65 4. 10 52 40 16 30 40 26 0.425 0.25 0.075 21 60 14 200 10 And the Liquid Limit (LL) = 35. Plastic Limit (PL) = 18 100 90 80 70 60 50 40 30 20 10 0.01 0.1 10 Sieve Dia mm passing%Question 10 Classify the following soils using the Unified soil classification system. Give the group symbol. No. 4 = 99 No. 200 = 76 LL = = 60 PL = 32 А) СH В CL OH MHSubject: Soil Mechanics A. Classify the Soil Using USCS (with explanation/ justification) Given data: D10 = ? D30= 0.0023mm D60= 0.032mm Liquid Limit= 49% Plastic Limit= 24% CHOICES: a. CL (lean clay with gravel) b. CL ( lean clay with sand) c. ML (silt with gravel) d. ML (Silt with sand)
- Question 18 Classify the following soils using the Unified soil classification system. Give the group symbol. No. 4 = 92 No. 200 = 48 LL = 30 PL = 8 A) SP В GC SM D SCExercise No.4.3 For a given soil, show that Ysat e Yd Yd Ysat + YwQ1: A. Answer in True or False 1. A soil has a Cu =1, then it is considered as a poorly graded soll. 2. A soil has L.L-60% and P.L-35%, then it plots a point below the A-line in the plasticity car 3. A soil described with a symbol (SP) has % passing No. 200 sieve more than 50% 4. Decreasing water content below shrinkage limit is accompanied with a decreasing in void ra 5. Water molecules are considered polar and known as dipoles. 6. Dry Density is the smallest density. 7. Capillary rise is directly proportional to the pore channel diameter. 8. The unconfined compressive strength is twice the undrained cohesion. 9. Piping or boiling occurs when effective stress equals to zero. 10. It is assumed that the secondary compression begins when the primary conso
- Q2- Classify the soil of following properties according to Unified and Textural Classification Systems; L.L = 40% P.L = 35% (show all calculations and steps). Size, mm 0.212 0.15 0.075 0.02 0.006 0.004 0.001 % finer 100 89 (50+17 47 38 30 (5+.17Problem 1: For a gravel with D60 0.48mm, D30 0.25mm, and D10 coefficient and the coefficient of gradation. Is it a well-graded or poorly graded soil? - = = = 0.11mm, calculate the uniformity Problem 2: 0.3 mm, D30 The following values for a sand are given: D10 Determine Cu and Cc and state if it is a well-graded or a poorly graded soil. = 0.41 mm, and D60 = = 0.77 mm.Q1: Classify the below soil according to Unified Soil Classification System (USCS) and the AASHTO System. Sieve No. sieve Diameter pass % 65 4. 4.75 10 52 16 1.18 40 30 0.6 26 40 0.425 21 60 0.25 14 200 0.075 10 And the Liquid Limit (LL) = 35, lastic Limit (PL) = 18 100 90 80 70 60 50 40 30 20 10 0.01 0.1 1 10 Sieve Dia mm % Buyssed