The wire diameter Mean coil diameter. Number of active coils Total number of coils Free length of the sprin. Pitch of the coil
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- A bumping post at the end of a track in a railway yard has a spring constant k = 8.0 MN/m (see figure). The maximum possible displacement d or the end of the striking plate is 450 mm. What is the maximum velocity vmaxthat a railway car of weight W = 545 kN can have without damaging the bumping post when it strikes it?Design a helical spring to be used in spring balance with a wire diameter of 6mm and the outside diameter should be limited to 66mm. if the permissible shear stress of the spring material is 325 N/mm? and the Modulus of rigidity is 85kN/mm?. a) Compute the deflection of spring per active turn and the axial load on the spring considering the effect of curvature, take Wahl's factor as Kw= 1.1 b) Calculate the value of axial load neglecting the effect of stress factor. **Note: Please upload your handwritten working/solution to the link provided. The value of Mean diameter of the spring in mm . The Spring Index is. Shear stress factor, neglecting curvature effect . Deflection per active turn in mm Axial Load W in N .. Axial Load W in N. considering effect of curvature .1. Design a compression helical spring to carry a load of 500 N with a deflection of 25 mm. The spring index may be taken as 8. Assume the following values for the spring material: Permissible shear stress = 350 MPa Modulus of rigidity = 84 kN/mm2 4С - 1 0.615 Wahl's factor where C-spring index. 4С - 4
- A helical compression spring is wound using 0.12-in-diameter phosphor-bronze B159 wire. The spring index C = 10 and the total number of coils is N = 14. You may assume that the spring has both ends squared and ground and is supported between fixed ends. Also, Sgy = 0.45 · Sut- a. Estimate the spring rate. b. Estimate the static load corresponding to the yield strength. c. What should the free length of the spring be to ensure that when it is compressed solid the torsional stress does not exceed the yield strength? d. Calculate the critical value of the free length of the spring to avoid buckling.A helical spring made of oil hardened and tempered steel compression springs, made of circular wire, is subjected to an axial force, which varies from (2.5 KN) to (3.5 KN). Over this range of force, the deflection of the spring should be approximately (5 mm). The spring index can be taken as (5). The spring has square and ground ends. If ultimate tensile strength of (1050 N/mm2) and modulus of rigidity of (81370 N/mm2). The permissible shear stress for the spring wire should be taken as (50 %) of the ultimate tensile strength.Design the spring and calculate the following: 1. Wire diameter; 2. Mean coil diameter; 3. Number of active coils; 4. Total number of coils; 5. Solid length of the spring; 6. Free length of the spring: 7. pitch of coils (p); 8. Required spring rate; 9. Actual spring rate; and 10. Draw a neat sketch .of the spring showing various dimensionsDesign a compression helical spring to carry a load of 500 N with a deflection of 25 mm. The spring index may be taken as 8. Assume the following values for the spring material: Permissible shear stress 350 MPa Modulus of rigidity = 84 kN/mm? 4С -1 0.615 Wahl's factor 4C – 4 where C= spring index. C [Ans. d= 5.893 mm; D= 47.144 mm;n=6| %3D
- A helical compression spring is 1o exert a force of 8.0 Ib when compressed 1o a length of 1.75 in. At a length of 1.25 in, the force must be 12.0 Ib. The spring will be installed in a machine that cycles slowly. and approximately 200 000 cycles total are expected. The tem- perature will not exceed 200°F. The spring will be installed in a hole having a diameter of 0.75 in. For this application. specify a suitable material, wire diameter. mean diameter. OD. ID. free length, solid length. number of coils, and type of end condition. Check the stress at the maximum operating load and at the solid length condition. The first of two solution procedures will be shown. The numbered steps can be used as a guide for future problems and as a Kind of algorithm for the spreadsheet approach that follows the manual solution.A spring with squared and ground ends is used for a load and deflection of 1.2 kN and 20 mm, respectively, with a spring index of 4. The wire diameter is 6 mm and the modulus of rigidity is 84 GPa. Which of the following is the active number of turns of the spring?2. A helical valve spring is to be designed for an operating load range of approximately 90 to 135 N. The deflection of the spring for the load range is 7.5 mm. Assume a spring index of 10. Permissible shear stress for the material of the spring = 480 MPa and its modulus of rigidity 80 kN/mm2. Design the spring. 4С - 1 0.615 , C being the spring index. Take Wahl's factor %3D 4С - 4 [Ans. d = 2.74 mm ; D = 27.4 mm ; n = 6]
- A helical spring with a load range of from 450 N to 800 N from valve-closed to valve-open conditions is used to close the valve of a spring-set relief valve having a lift of 10 mm. Assuming the spring wire to be of chrome vanadium steel, the spring is rendering average service, determine the diameter of the wire if the spring index is 7 and Sg - 420 MPa. Use G=83GPA. Select one: O a. 2.4-mm wire O b. 5-mm wire O c. 6-mm wire O d. 7-mm wireA square end compression helical spring has an operation load range of 3.5KN to 4.2KN.The deflection for the load range is 8mm and the spring index is 6.if the permissible shear stress and module of rigidity for the material of the spring are 380MPa and 90pa respectively, including the effect of the wire curvature. Design the spring by, determine (A)wire diameter (B) mean coil diameter (C) number of active turns (D)total number of turnsspring is to be inserted with an initial compression to produce a force equal to 125 N between the right-hand end of the lever and the stop. When the maximum force at A reaches to a value of 200 N, the end of the lever moves downward by 25 mm. assuming a spring index 8 determine the following parameters: 1. Spring rate 2. Size of the wire 3. Outside diameter of the spring 4. Number of active coils, and 5. Free length, assuming squared and ground ends Note: the allowable shear stress may be taken as 420 MPa, and G = 80 GPa. Hint: Ans. 0.33 N/mm: 3.4 mm; 27.2 mm; 77 mm - 200 mm - 200 mm Lever Stop -Spring