The velocity of an object moving along the x-axis is given in m/s by v(t) = t^2 – 6t + 8, where t is in s. If the object starts from x=1m at t=0s, then what is the acceleration of the object when t = 2 s?

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The velocity of an object moving along the x-axis is given in m/s by
v(t) = t^2 – 6t + 8, where t is in s. If the object starts from x=1m at
t=0s, then what is the acceleration of the object when t = 2 s?
Transcribed Image Text:The velocity of an object moving along the x-axis is given in m/s by v(t) = t^2 – 6t + 8, where t is in s. If the object starts from x=1m at t=0s, then what is the acceleration of the object when t = 2 s?
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