The soil sample is 75% gravel with laboratory result shown below. Is it well graded or poorly graded? D10 = 0.08 mm D30 = 0.22 mm D60 = 0.41 mm Select one: a. Poorly graded b. Well graded
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The soil sample is 75% gravel with laboratory result shown below. Is it well graded or poorly graded?
D10 = 0.08 mm
D30 = 0.22 mm
D60 = 0.41 mm
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- 2. Based on the USCS, what is the 20 points percentage of the gravel in this sample? * Sieve Percent 100 Sieve 90 opening (mm) passing (finer) No. 80 70 4 4.75 99.0 60 10 2 94.0 50 20 0.85 67.4 40 30 30 0.6 51.4 20 40 0.425 39.4 10 60 0.25 23.4 140 0.106 13.4 0.01 0.1 1 10 200 0.075 2.0 Particle size (mm) Pan O (a) 0 % O (b) 6% O (c) 1% O (d) 32.6% Percent finer by weightQ3. A 1200 g sample of Gravel in the SSD condition in air and weighed 770 g when immersed in water. Also, a 500 g sample of Sand in the SSD condition in air and weighed 300 g when immersed in water Calculate the BSG(SSD) of the sand and gravel 1) the BSG (SSD) of the Gravel * 1.2.791 2.4.71 3.3.703 4.2.50 2) the BSG (SSD) of the Sand * 1.2.221 2.3.590 3.2.500 4.3.232 Choose one answer and write the answer number for me5.5 The modified Proctor test (ASTM D 698, method C) was performed for a soil with G, = 2.70, and the results are as follows: Moist Weight in Mold, gf Water Content, % 6.5 3250 9.3 3826 12.6 4293 14.9 4362 17.2 4035 18.6 3685 (d) What is y at wopi? (e) What is the range of water content if the relative compaction (R.C.) is required to be 95% of the modified Proctor Ya.max?
- Sieve and Atterberg limits tests were made on a soil specimen and th results are given below: Sieve No. Wt. of sieve (gm) Wt. of sieve + Soil (gm) 1" 450 518 378 420 L.L = 32% 4 100 370 425 PL = 17% 365 200 442 W₂ = 21% 485 Pan 793 D15 = 0.002 1. Classify the specimen according to the Unified Soil Classification System (USCS). Assign the group name and the group symbol. 2. Determine the soil activity. in the soil Liquidity index and consistency indexFor a soil specimen, the following are given: % passing Sieve No. 4 = 92% % passing Sieve No. 10 = 81% % passing Sieve No. 40 = 78% % passing Sieve No. 200 = 65% LL = 48% PI = 32% Classify the soil by the AASHTO system. O A-2-7 (15) O A-7-6 (18) O A-7-6 (32) O A-2-5 (6)The amount of soil retained in the #4 sieve is 45g, soil retained in the pan is 108g and the total mass of dry soil is 500g. What is the percentage of sand in the soil sample given in number 1 based on USCS specifications? Select one: a. 22% b. none of the choices c. 69% d. 9% e. 91%
- the results of the sieve analysis done on a soil are shown below: determine its classification using USCS a.GW b. GP c. SP d. none e. SWI am working on a lab report for a sieve analysis that was conducted in the lab. I got that the soil was made up of approximately: 20.5% gravel, 77.8% sand, and 1.7% fines. The values for the coefficient of uniformity (Cu) and coefficient of gradation (Cc) are 10.56 and 0.528 respectively. What does this mean when it comes to engineering design? Would the soil be considered good for building a structure? If so, is there a specific type of structure that would work best with this type of soil?The soil tested at the laboratory was found that the particle passing sieve No.200 is 89%, retained on sieve No. 4 is 3%, Liquid limit of 70%, organic matter of 25%, and Plasticity Index of 40%. Determine the type of soil * PLASTICITY CHART 60 50 CH A LINE: Pl 0,73(LL-20)| 30 CL MH&OH 20 CL ML ML&OL 10 20 30 40 50 60 70 80 90 100 LIQUID LIMIT (LL) (%) O Organic clay O Clay with high plasticity O Organic Silt O Sandy Clay PLASTICITY INDEX (PI) (%)
- For a given sieve analyis: No. 4 - % finer 60%, for No. 200 -%finer 40. LL=26, PL= 4. Classify the soil using USCS. Justify your answer. a. GW b. GM-GC c. GC d. GMThe Name :- Answer the following questions :-( Choose 5 only) 1- .is the moisture content that defines where the soil changes from a plastic to a viscous fluid state. 2- The difference between the PL and the LL is defined as.... 3- Why is it not possible to use core cutter method for calculating the density of cohesion less soil? 4- The relative density of a soil is 5- In the sieve analysis test Place the sieve stack in the mechanical shaker and shake for . minutes . 6- Hydrometer testing is performed on soil passing from a sieve.The coefficient of permeability (K value) of a soil describes how easily a liquid will move through a soil. True )False Permeability measurement is used to: calculation of seepage through earth dams calculation of seepage under sheet pile walls estimating the seepage rate from waste storage O all of the answers are correct Which state describes soil that does not show cracks when deformed (choose correct state that applies). A) Plastic state B) Liquid State C) Semisolid state D) Solid state