The shear stress-strain diagram for an alloy is shown in the figure. If a bolt having a diameter of 0.25 in. is made of this material and used in the lap joint, determine the modulus of elasticity E and the force P required to cause the material to yield. Take p = 0.3. 7 (ksi) Ty=50 P 0.004 y (rad)
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- The strength-to-weight ratio of a structural material is defined as its load-carrying capacity divided by its weight. For materials in tension, use a characteristic tensile stress obtained from a stress-strain curve as a measure of strength. For instance, either the yield stress or the ultimate stress could be used, depending upon the particular application. Thus, the strength-to-weight ratio RS/Wfor a material in tension is defined as Rs/w= in which a is the characteristic stress and 7 is the weight density. Note that the ratio has units of length. Using the ultimate stress Uas the strength parameter, calculate the strength-to-weight ratio (in units of meters) for each of the following materials: aluminum alloy 606I-T6, Douglas fir (in bending}, nylon. structural steel ASTM-A57.2, and a titanium alloy. Obtain the material properties from Tables [-1 and 1-3 of Appendix I. When a range of values is given in a table, use the average value.Clear my choice Let's consider a rod having a solid circular cross-section with diameter of 4 mm and it is made of a material having a Young's modulus E= 200 Gpa and a Poisson's ratio of 0.3. If a tensile force Fis subjected to that rod cross-section, the diameter becomes 3.995 mm. determine the applied force F. Select one: O F= 5236 N OF=15708N O F= 13090 N OF=10472 N OF=4189 N O F=6283 N Clear my choice Finish attempt NEXT ACTIVITY MENG360 Test -Spring 2020-2021 Jup toLet's consider a rod having a solid circular cross-section with diameter of 6 mm and it is made of a material having a Young's modulus E = 200 Gpa and a Poisson's ratio of 0.3. If a tensile force F is subjected to that rod cross-section, the diameter becomes 5.995 mm. determine the applied force F. Select one: O F=15708N O F= 10472 N O F=5236 N O F= 13090 N O F=6283 N O F=4189 N
- 3. A steel bolt and nut are tightened around an aluminum sleeve. Find the internal forces as the nut is rotated 1 turn (1 turn = 1.5 mm) given the cross sectional areas and the moduli of elasticity for the steel and the aluminum. AST = 150 mm? EST = 200 GPa EAL = 70 GPa AAL = 100 mm? L=150 mm AST Final 1.5 mm Position AlLet's consider a rod having a solid circular cross-section with diameter of 6 mm and it is made of a material having a Young's modulus E = 200 Gpa and a Poisson's ratio of 0.3. If a tensile force Fis subjected to that rod cross-section, the diameter becomes 5.998 mm. determine the applied force F. Select one: O F=15708 N O F= 5236 N O F= 6283 N O F=4189 N O F= 10472 N O F= 13090N Clear my choice Finish attempt. IOUS ACTIVITY 360 Test - Spring 2020-2021 Jump to. 11:21 PM 4) G ENG 4/15/2021 LEGO ort sc delete end home backspace num lock 7V home enter 4E K pause MLet's consider a rod having a solid circular cross-section with diameter of 4 mm and it is made of a material having a Young's modulus E = 200 Gpa and a Poisson's ratio of 0.3. If a tensile force F is subjected to that rod cross-section, the diameter becomes 3.995 mm. determine the applied force F. Select one: F = 10472 N O F = 6283N O F= 15708 N O F = 4189N O F = 5236 N O F = 13090 N Clear my choice
- The steel bolt and anchor assembly is used to reinforce the roof of a passageway in an underground coal mine. In installation, the bolt is tensioned to 5,500 lb. Calculate the stress, strain, and extension of the bolt with length I= 39 in. if it is formed from 1045 steel alloy. Coal seam Passageway in. Roof line (Express your answer using three significant figures.) |ksi (Express your answer using two significant figures.) |×10-4 (Express your answer using whole numbers.) mils AL = %3DClear my choice Let's consider a rod having a solid circular cross-section with diameter of 6 mm and it is made of a material having a Young's modulus E = 120 Gpa and a Poisson's ratio of 0.33. If a tensile force F is subjected to that rod cross-section, the diameter becomes 5.998 mm. determine the applied force F. Select one: O F= 5712 N O F= 2285 N O F= 8568 N O F= 2856 N O F= 3427 N O F=7140 N Finish attempt..Let’s consider a rod having a solid circular cross-section with diameter of 6 mm and it is made of a material having a Young’s modulus E = 200 Gpa and a Poisson’s ratio of 0.3. If a tensile force F is subjected to that rod cross-section, the diameter becomes 5.998 mm. determine the applied force F. Select one: F = 6283 N F = 10472 N F = 4189 N F = 5236 N F = 13090 N F = 15708 N
- The state of stress at a point in a structural member is given by = 0x = Ax² + By², ay = Cy² + Dz², oz Ez² + Fx² Txy = Gy + Hz, Txz = Iz + Jx, Tyz = Kx + Ly where A, B,..., L are constants. Find expressions of the body forces to ensure the equi- librium. Units of the stresses are MPa.The force P is applied on the top of the solid cylindrical body which rests on a circular cap as shown below. Determine the smallest dimensions di, ds, and t required to support the load P. Use the table given below and your student ID to obtain the values of the force P and the allowable stresses for all the materials used in the problem (ie., Pand the allowable stresses are given). 30 mm allowable allowable tensile stress (kPa) allowable shear stress (kPa) Student bearing P(N) ID stress (kPa) 1000 175 300 155Determine the equivalent stiffness constant of the ff.