The shear strength of each of ten test spot welds is determined, yielding the following data (psi): 367 389 375 377 384 388 409 362 358 415 Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle of P(X ≤ 400). [Hint: P(X ≤ 400) = ((400 -μ)/o).] (Round your answer to four decimal places.)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 91E
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The shear strength of each of ten test spot welds is determined, yielding the following data (psi):
375 377 384 388 409 362 358 415
367 389
Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle of P(X ≤400). [Hint: P(X ≤400) = ((400 -μ)/o).] (Round your answer to four decimal
places.)
Transcribed Image Text:The shear strength of each of ten test spot welds is determined, yielding the following data (psi): 375 377 384 388 409 362 358 415 367 389 Suppose we decide to examine another test spot weld. Let X = shear strength of the weld. Use the given data to obtain the mle of P(X ≤400). [Hint: P(X ≤400) = ((400 -μ)/o).] (Round your answer to four decimal places.)
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