The reaction Cl2(g) + CHCl3(g) --> CCl4(g) + HCl(g) proceeds through the following mechanism: Cl2(g) --> 2 Cl(g) Cl(g) + CHCl3(g) --> HCl(g) + CCl3(g) Cl(g) + CCl3(g) --> CCl4(g) (a) The second step of this mechanism is rate-determining (slow). What is the rate law for this reaction? Rate = k [Cl2] [CHCl3]Rate = k [Cl2]2 [CHCl3] Rate = k [Cl2] [CHCl3]2Rate = k [Cl2]1/2 [CHCl3] Rate = k [Cl2] [CHCl3]1/2 Rate = k [Cl2]2 Rate = k [Cl2]2 [CHCl3]1/2 (b) What would the rate law be if the first step of this mechanism were rate-determining? Rate = k [Cl2] [CHCl3] Rate = k [Cl2]2 [CHCl3] Rate = k [Cl2] [CHCl3]2 Rate = k [Cl2]1/2 [CHCl3] Rate = k [Cl2] [CHCl3]1/2 Rate = k [Cl2]2 Rate = k [Cl2]2 [CHCl3]1/2 Rate = k [Cl2]
The reaction Cl2(g) + CHCl3(g) --> CCl4(g) + HCl(g) proceeds through the following mechanism: Cl2(g) --> 2 Cl(g) Cl(g) + CHCl3(g) --> HCl(g) + CCl3(g) Cl(g) + CCl3(g) --> CCl4(g) (a) The second step of this mechanism is rate-determining (slow). What is the rate law for this reaction? Rate = k [Cl2] [CHCl3]Rate = k [Cl2]2 [CHCl3] Rate = k [Cl2] [CHCl3]2Rate = k [Cl2]1/2 [CHCl3] Rate = k [Cl2] [CHCl3]1/2 Rate = k [Cl2]2 Rate = k [Cl2]2 [CHCl3]1/2 (b) What would the rate law be if the first step of this mechanism were rate-determining? Rate = k [Cl2] [CHCl3] Rate = k [Cl2]2 [CHCl3] Rate = k [Cl2] [CHCl3]2 Rate = k [Cl2]1/2 [CHCl3] Rate = k [Cl2] [CHCl3]1/2 Rate = k [Cl2]2 Rate = k [Cl2]2 [CHCl3]1/2 Rate = k [Cl2]
Introduction to General, Organic and Biochemistry
11th Edition
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Chapter7: Reaction Rates And Chemical Equilibrium
Section: Chapter Questions
Problem 7.42P
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Question
The reaction Cl2(g) + CHCl3(g) --> CCl4(g) + HCl(g) proceeds through the following mechanism:
Cl2(g) --> 2 Cl(g)
Cl(g) + CHCl3(g) --> HCl(g) + CCl3(g)
Cl(g) + CCl3(g) --> CCl4(g)
Cl(g) + CHCl3(g) --> HCl(g) + CCl3(g)
Cl(g) + CCl3(g) --> CCl4(g)
(a) The second step of this mechanism is rate-determining (slow). What is the rate law for this reaction?
Rate = k [Cl2] [CHCl3]Rate = k [Cl2]2 [CHCl3]
Rate = k [Cl2] [CHCl3]2Rate = k [Cl2]1/2 [CHCl3]
Rate = k [Cl2] [CHCl3]1/2
Rate = k [Cl2]2
Rate = k [Cl2]2 [CHCl3]1/2
(b) What would the rate law be if the first step of this mechanism were rate-determining?
Rate = k [Cl2] [CHCl3]
Rate = k [Cl2]2 [CHCl3]
Rate = k [Cl2] [CHCl3]2
Rate = k [Cl2]1/2 [CHCl3]
Rate = k [Cl2] [CHCl3]1/2
Rate = k [Cl2]2
Rate = k [Cl2]2 [CHCl3]1/2
Rate = k [Cl2]
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