The plates of parallel plate capacitor A consist of two metal discs of identical radius, R1 = 4.00 cm, separated by a distance d = 2.00 mm, as shown in the figure below. a.Calculate the capacitance of this parallel plate capacitor with the spacebetween the plates filled with air. b.A dielectric in the shapeof a thick-walled cylinder of outer radiusR1= 4.00 cm, inner radius R2= 2.00 cm, thickness d = 2.00 mm, anddielectric constant k= 2.00 is placed between the plates, coaxial with them, as shown in the figure. Calculate the capacitance of capacitor B, with this dielectric. c.The dielectric cylinder is removed, and instead a solid disc of radius R1 made of the same dielectric is placed between the plates to form capacitor C, as shown in the figure. What is the new capacitance?

Glencoe Physics: Principles and Problems, Student Edition
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Chapter25: Electromagnetic Induction
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Problem 79A
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The plates of parallel plate capacitor A consist of two metal discs of identical radius, R1 = 4.00 cm, separated by a distance d = 2.00 mm, as shown in the figure below.

a.Calculate the capacitance of this parallel plate capacitor with the spacebetween the plates filled with air.

b.A dielectric in the shapeof a thick-walled cylinder of outer radiusR1= 4.00 cm, inner radius R2= 2.00 cm, thickness d = 2.00 mm, anddielectric constant k= 2.00 is placed between the plates, coaxial with them, as shown in the figure. Calculate the capacitance of capacitor B, with this dielectric.

c.The dielectric cylinder is removed, and instead a solid disc of radius R1 made of the same dielectric is placed between the plates to form capacitor C, as shown in the figure. What is the new capacitance?

Capacitor A
Capacitor B
Capacitor C
Top view
Metal disc
R₁
Air
Dielectric
R₁
Dielectric
Side view
|R₂|e
Air
Transcribed Image Text:Capacitor A Capacitor B Capacitor C Top view Metal disc R₁ Air Dielectric R₁ Dielectric Side view |R₂|e Air
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