From the image below, how to solve it and the ff question marks/ blanks that I don't know how do I gonna do.Please help ftThe motion of a particle is governed by the relation a = 4t?, where a is-second. When t is zero, v = 2 "and t is insecftand s = 4 ft. Find the values of v and s when t = 2 sec.secSolution:a = 4t?dv= 4t?dtds=-t +?dt3dv = 4t?dt4ds =-t + ?12S, dv = f, 4t°dtS, dv = ;t*dt%3D12v-2 = ?s -4=t* - ?12v=+?12Hence: if t = 2 sec, substitute in (a) and (b)V+ ?+ ?

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The motion of a particle is governed by the relation a = 4t², where a is and t is in see ft second. When t is zero, v = 2 and s = 4 ft. Find the values of v and s when t = 2 sec. %3D sec

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter1: A Physics Toolkit

Section: Chapter Questions

Problem 3STP

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