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The height (feet) of an object moving vertically is given by s= - 16t² + 48t+ 36, where t is in seconds. Find the object's velocity at t=9, its maximum height and when it occurs, and its velocity when s = 0. The velocity of the object at t=9 seconds is 0 ft/second. (Simplify your answer. Type an integer or a decimal.) The maximum height occurs at t = seconds. (Simplify your answer. Type an integer or a decimal.) The maximum height is feet. (Simplify your answer. Type an integer or a decimal.) feet/second. The velocity when s=0 is (Round to the nearest hundredth.)

The height (feet) of an object moving vertically is given by s= - 16t² + 48t+ 36, where t is in seconds. Find the object's velocity at t=9, its maximum height and when it occurs, and its velocity when s = 0. The velocity of the object at t=9 seconds is 0 ft/second. (Simplify your answer. Type an integer or a decimal.) The maximum height occurs at t = seconds. (Simplify your answer. Type an integer or a decimal.) The maximum height is feet. (Simplify your answer. Type an integer or a decimal.) feet/second. The velocity when s=0 is (Round to the nearest hundredth.)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter9: Quadratic Functions And Equations
Section9.6: Solving Quadratic Equations By Using The Quadratic Formula
Problem 15CYU
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The height (feet) of an object moving vertically is given by s= - 16t² + 48t+ 36, where t is in seconds. Find the object's velocity at t= 9, its maximum height and when it occurs, and its velocity when s = 0. The velocity of the object at t=9 seconds is 0 ft/second. (Simplify your answer. Type an integer or a decimal.) The maximum height occurs at t= seconds. (Simplify your answer. Type an integer or a decimal.) The maximum height is feet. (Simplify your answer. Type an integer or a decimal.) The velocity when s=0 is feet/second. (Round to the nearest hundredth.)
Transcribed Image Text:The height (feet) of an object moving vertically is given by s= - 16t² + 48t+ 36, where t is in seconds. Find the object's velocity at t= 9, its maximum height and when it occurs, and its velocity when s = 0. The velocity of the object at t=9 seconds is 0 ft/second. (Simplify your answer. Type an integer or a decimal.) The maximum height occurs at t= seconds. (Simplify your answer. Type an integer or a decimal.) The maximum height is feet. (Simplify your answer. Type an integer or a decimal.) The velocity when s=0 is feet/second. (Round to the nearest hundredth.)
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