The gravitational acceleration on Mars is nearly 3.8 m/s2. Air resistance is negligible. You are standing on top of a cliff and dropping a briefcase wrench. Choosing the positive direction to be up, and the point t=0 to be the moment when you drop the key, please answer the following questions paying particular attention to the signs. (a) What is the function expressing the velocity (directional speed) of the key? v(t)=

The gravitational acceleration on Mars is nearly 3.8 m/s2. Air resistance is negligible. You are standing on top of a cliff and dropping a briefcase wrench. Choosing the positive direction to be up, and the point t=0 to be the moment when you drop the key, please answer the following questions paying particular attention to the signs. (a) What is the function expressing the velocity (directional speed) of the key? v(t)=

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Description: The gravitational acceleration on Mars is nearly 3.8 m/s2. Air resistance is negligible. You are standing on top of a cliff and dropping a briefcase wrench. Choosing the positive direction to be up, and the point t=0 to be the moment when you drop th

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter2: Motion In One Dimension

Section: Chapter Questions

Problem 7OQ: A student at the top of a building of height h throws one ball upward with a speed of vi and then...

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I have no idea to how to start to this question: Wags (a dog) decides to go on a journey. He begins his journey by traveling 58 meters in a direction directly south. He then runs 100.0 meters in a direction 30◦north of west. During the last leg of his journey, he follows a scent for 59 meters in a direction 30◦east of north. What distance does Wags end up from his initial startingpoint?
Use the given acceleration function and initial conditions to find the velocity vector v(t), and position vector r(t). Then find the position at time t = 3. a(t) = tj + tk v(1) = 7j, r(1) = 0 v(t) = r(t) = r(3) = Need Help? Read It
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A car drives horizontally off of a 6.60 m tall cliff. The car lands 7.39 m from the base of the cliff. Assuming air resistance can be ignored, at what speed did the car leave the top of the cliff and at what speed is the car traveling just before striking the ground?
A helicopter is ascending vertically with a speed of 5.30 m/s. At a height of 107 m above the Earth, a package is dropped from the helicopter. How much time does it take for the package to reach the ground? [Hint: What is v0 for the package?] Express your answer to three significant figures and include the appropriate units. My Answer is that t= 4.163 but what unit is it? I tried s, m/s, min but none of them were correct. PLEASE HELP CONFIRM MY ANSWER and THE UNIT along with 4.163
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At time t = 0 a particle at the origin of an xyz-coordinate system has a velocity vector of Vo =i+ 12j - k. The acceleration function of the particle is a(t) = 16ti+j+ (cos 2t)k. Find the speed of the particle at time t = 1. Round your answer to two decimal places. Speed =
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A diver jumps off a cliff of height h at an angle θ = 260 (see figure). He reaches a maximum height of h subscript m a x end subscript= 20 m above the top of the cliff before falling to the water below. He hits the water x=295 m from the base of the cliff. Determine the height of the cliff, h. Take g=10m/s2 . Round your answer to one decimal place.
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